题目内容
公差不为零的等差数列{an}的前n项和为Sn,若S4=a4,则
=______.
| a5 |
| a4 |
设等差数列{an}的首项为a1,公差为d,
由S4=a4,得4a1+6d=a1+3d,得a1=-d,
∴
=
=
,
故答案为:
.
由S4=a4,得4a1+6d=a1+3d,得a1=-d,
∴
| a5 |
| a4 |
| a1+4d |
| a1+3d |
| 3 |
| 2 |
故答案为:
| 3 |
| 2 |
练习册系列答案
相关题目