题目内容
已知:在△ABC中,a,b,c分别是角A、B、C所对的边,向量
=(2
sin
,
),
=(sin(
+
),1)且
•
=
.
(1)求角B的大小.(2)若角B为锐角,a=6,S△ABC=6
,求b的值.
| m |
| 3 |
| B |
| 2 |
| ||
| 2 |
| n |
| B |
| 2 |
| π |
| 2 |
| m |
| n |
| 3 |
(1)求角B的大小.(2)若角B为锐角,a=6,S△ABC=6
| 3 |
解(1)∵
•
=
∴
•
=2
sin
•sin(
+
)+
=
2
sin
cos
=
sinB=
∴B=
或B=
(2)∵B为锐角,∴B=
,由S=
acsinB=6
,
解得c=4
由b2=a2+c2-2accosB=36+48-2×6×4
×
=12.
b=2
| m |
| n |
| 3 |
∴
| m |
| n |
| 3 |
| B |
| 2 |
| B |
| 2 |
| π |
| 2 |
| ||
| 2 |
| 3 |
2
| 3 |
| B |
| 2 |
| B |
| 2 |
| ||
| 2 |
sinB=
| 1 |
| 2 |
| π |
| 6 |
| 5π |
| 6 |
(2)∵B为锐角,∴B=
| π |
| 6 |
| 1 |
| 2 |
| 3 |
解得c=4
| 3 |
由b2=a2+c2-2accosB=36+48-2×6×4
| 3 |
| ||
| 2 |
b=2
| 3 |
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