题目内容
| lim |
| x→1 |
| 2 |
| x2-1 |
| 1 |
| x-1 |
| A、-1 | ||
B、-
| ||
C、
| ||
| D、1 |
分析:先通分,把原式等价转化为
,再消除零因子,进一步等价转化为
,然后再进行求解.
| lim |
| x→1 |
| 1-x |
| x2-1 |
| lim |
| x→1 |
| -1 |
| x+1 |
解答:解:
(
-
)
=
=
=-
.
故选B.
| lim |
| x→1 |
| 2 |
| x2-1 |
| 1 |
| x-1 |
=
| lim |
| x→1 |
| 1-x |
| x2-1 |
=
| lim |
| x→1 |
| -1 |
| x+1 |
=-
| 1 |
| 2 |
故选B.
点评:本题考查
型极限问题的运算,解题时要先通分,把原式等价转化为
,再消除零因子,进一步等价转化为
,然后再进行求解.
| 0 |
| 0 |
| lim |
| x→1 |
| 1-x |
| x2-1 |
| lim |
| x→1 |
| -1 |
| x+1 |
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