题目内容
| OA |
| a |
| OB |
| b |
| OP |
| c |
| c |
| a |
| b |
| 5 |
| 2 |
| 5 |
| 2 |
分析:利用
=
+
+
①及
=
+
+
②,求出
=
+
,
代入式子并利用
•(
-
)=0进行运算.
| c |
| b |
| BH |
| HP |
| c |
| a |
| AH |
| HP |
| c |
| HP |
| ||||
| 2 |
代入式子并利用
| HP |
| a |
| b |
解答:解:连接PA、PB,设 AB的中点为H,则HP为线段AB的中垂线,∴
•(
-
)=0,
∵
=
=
+
+
=
+
+
①,
∵
=
=
+
+
=
+
+
②. 把①②相加可得
=
+
,∴
•(
-
)=(
+
)•(
-
)=0+
=
=
.
OA OB
| HP |
| a |
| b |
∵
| c |
| OP |
| OB |
| BH |
| HP |
| b |
| BH |
| HP |
∵
| c |
| OP |
| OA |
| AH |
| HP |
| a |
| AH |
| HP |
| c |
| HP |
| ||||
| 2 |
| c |
| a |
| b |
| HP |
| ||||
| 2 |
| a |
| b |
| ||||
| 2 |
=
| 9-4 |
| 2 |
| 5 |
| 2 |
点评:本题考查两个向量加减法及其几何意义,两个向量垂直的性质,两个向量数量积的运算,体现了数形结合的数学思想.
练习册系列答案
相关题目