题目内容

△ABC中,点D在边AB上,CD平分∠ACB,若
CB
=a,
CA
=b,|a|=1,|b|=2,则
CD
=(  )
A.
1
3
a+
2
3
b
B.
2
3
a+
1
3
b
C.
3
5
a+
4
5
b
D.
4
5
a+
3
5
b
∵CD为角平分线,
BD
AD
=
BC
AC
=
1
2

AB
=
CB
-
CA
=
a
-
b

AD
=
2
3
AB
=
2
3
a
-
2
3
b

CD
=
CA
+
AD
=
b
+
2
3
a
-
2
3
b
=
2
3
a
+
1
3
b

故选B
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