题目内容
| lim |
| x→2 |
| 1 |
| x-2 |
| 4 |
| x2-4 |
| 1 |
| 4 |
| 1 |
| 4 |
分析:先通分把
(
-
)等价转化为
,再消除零因子,得到
,由此能求出结果.
| lim |
| x→2 |
| 1 |
| x-2 |
| 4 |
| x2-4 |
| lim |
| x→2 |
| x-2 |
| (x -2)(x+2) |
| lim |
| x→2 |
| 1 |
| x+2 |
解答:解:
(
-
)
=
=
=
.
故答案为:
.
| lim |
| x→2 |
| 1 |
| x-2 |
| 4 |
| x2-4 |
=
| lim |
| x→2 |
| x-2 |
| (x -2)(x+2) |
=
| lim |
| x→2 |
| 1 |
| x+2 |
=
| 1 |
| 4 |
故答案为:
| 1 |
| 4 |
点评:本题考查函数的极限和求法,是基础题.解题时要认真审题,仔细解答,注意合理地消除零因子.
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