ÌâÄ¿ÄÚÈÝ

ϱíÊÇÓÃÓÚÎÞÍÁÔÔÅàµÄÒ»ÖÖÅàÑøÒºÅä·½£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

Ca(NO3)2

MgSO4

KH2PO4

KCl

FeCl3

H2O

1.0g

0.25g

0.25g

0.12g

0.005g

1000mL

£¨1£©ÓôËÅàÑøÒºÅàÓýij¸ßµÈÖ²Îïʱ£¬ÍùÍùÒª¸øÅàÑøÒºÖÐͨÈë¿ÕÆø£¬ÕâÒ»´ëÊ©µÄÄ¿µÄÊÇÓÃÒÔ´Ù½ø__________£¬ÒÔÀûÓÚ¶Ô¿óÖÊÔªËØµÄÎüÊÕ¡£ÒªÊ¹¸ÃÖ²ÎïÉú³¤Á¼ºÃ£¬¸ù¾Ý¹âºÏ×÷ÓÃËù±ØÐëµÄÌõ¼þ£¬³ýÁËÊÊÒ˵ÄζÈÍ⣬»¹ÐèÒª__________ºÍ__________¡£

£¨2£©Ö²ÎïÔÚÎüÊÕÅàÑøÒºÖеĿóÖÊÀë×Óʱ£¬Ö÷ÒªÊÇͨ¹ý________·½Ê½½øÐеġ£¾­¹ýÒ»¶Îʱ¼äºó£¬¼ì²âµ½ÅàÑøÒºÖÐÁô´æµÄCa2£«½Ï¶à£¬¶øNO3-½ÏÉÙ£¬ÕâÒ»ÏÖÏóÓëϸ°ûĤµÄ________Óйء£

£¨3£©Èô³ýÈ¥¸ÃÅàÑøÒºÖеÄMgSO4£¬½«Ö±½ÓÓ°ÏìÖ²ÎïÌåÄÚ________µÄºÏ³É¡£

£¨4£©¸ÃÅä·½ÖÐÊôÓÚÖ²ÎïËùÐèµÄ´óÁ¿¿óÖÊÔªËØÊÇ________£¬Î¢Á¿ÔªËØÊÇ________________¡£

 

´ð°¸£º
½âÎö£º

£¨1£©¸ùµÄÓÐÑõºôÎü  ¹âÕÕ  CO2£¨2£©Ö÷¶¯ÔËÊä  Ñ¡Ôñ͸¹ýÐÔ£¨3£©Ò¶ÂÌËØ£¨4£©N P K Ca Mg £»S Fe Cl

 


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ϱíÊÇÓÃÓÚÎÞÍÁÔÔÅàµÄÒ»ÖÖÅàÑøÒºÅä·½£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

Ca£¨NO3£©2¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­1£®0 g

MgSO4¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­0£®25 g

KH2PO4¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­0£®25 g

KCl¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­0£®12 g

FeCl3¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­0£®005 g

H2O¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­1000 mL

 £¨1£©ÓôËÅàÑøÒºÅàÓýij¸ßµÈÖ²Îïʱ£¬ÍùÍùÒª¸øÅàÑøÒºÖÐͨÈë¿ÕÆø£¬ÕâÒ»´ëÊ©µÄÄ¿µÄÊÇÓÃÒÔ´Ù½ø_____________£¬ÒÔÀûÓÚ¶Ô¿óÖÊÔªËØµÄÎüÊÕ¡£ÒªÊ¹¸ÃÖ²ÎïÉú³¤Á¼ºÃ£¬¸ù¾Ý¹âºÏ×÷ÓõıØÐèÌõ¼þ£¬³ýÁËÊÊÒ˵ÄζÈÍ⣬»¹ÐèÒª_____________ºÍ_____________¡£

£¨2£©Ö²ÎïÔÚÎüÊÕÅàÑøÒºÖпóÖÊÀë×Óʱ£¬Ö÷ÒªÊÇͨ¹ý_____________·½Ê½½øÐеġ£¾­¹ýÒ»¶Îʱ¼äºó£¬¼ì²âµ½ÅàÑøÒºÖÐÁô´æµÄCa2+½Ï¶à£¬¶øNO½ÏÉÙ£¬ÕâÒ»ÏÖÏóÓëϸ°ûĤµÄ_____________Óйء£

£¨3£©Èô³ýÈ¥¸ÃÅàÑøÒºÖеÄMgSO4£¬½«Ö±½ÓÓ°ÏìÖ²ÎïÌåÄÚ_____________µÄºÏ³É¡£

£¨4£©¸ÃÅä·½ÖÐÊôÓÚÖ²ÎïËùÐèµÄ´óÁ¿¿óÖÊÔªËØÊÇ_____________£¬Î¢Á¿ÔªËØÊÇ_____________¡£

ϱíÊÇÓÃÓÚÎÞÍÁÔÔÅàµÄÒ»ÖÖÅàÑøÒºÅä·½£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

Ca(NO3)2¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­1.0¿Ë

MgSO4¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­0.25¿Ë

KH2PO4¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­0.25¿Ë

KCl¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­0.12¿Ë

FeCl3¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­0.005¿Ë

H2O¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­1000ºÁÉý

£¨1£©ÓôËÅàÑøÒºÅàÓýij¸ßµÈÖ²Îïʱ£¬ÍùÍùÒª¸øÅàÑøÒºÖÐͨÈë¿ÕÆø£¬ÕâÒ»´ëÊ©µÄÄ¿µÄÊÇÓÃÒÔ´Ù½ø         £¬ÒÔÀûÓÚ¶Ô¿óÖÊÔªËØµÄÎüÊÕ¡£ÒªÊ¹¸ÃÖ²ÎïÉú³¤Á¼ºÃ£¬¸ù¾Ý¹âºÏ×÷ÓÃËù±ØÐëµÄÌõ¼þ£¬³ýÁËÊÊÒ˵ÄζÈÍ⣬»¹ÐèÒª           ºÍ            ¡£

£¨2£©Ö²ÎïÔÚÎüÊÕÅàÑøÒºÖеĿóÖÊÀë×Óʱ£¬Ö÷ÒªÊÇͨ¹ý         ·½Ê½½øÐеġ£¾­¹ýÒ»¶Îʱ¼äºó£¬¼ì²âµ½ÅàÑøÒºÖдæÔÚCa2+½Ï¶à£¬¶øNO½ÏÉÙ£¬ÕâÒ»ÏÖÏóÓëϸ°ûĤµÄ          Óйء£

£¨3£©Èô³ýÈ¥¸ÃÅàÑøÒºÖеÄMgSO4,½«Ö±½ÓÓ°ÏìÖ²ÎïÌåÄÚ         µÄºÏ³É¡£

£¨4£©¸ÃÅä·½ÖÐÊôÓÚÖ²ÎïËùÐèµÄ´óÁ¿¿óÖÊÔªËØÊÇ         £¬Î¢Á¿ÔªËØÊÇ          ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø