Question

£¨1£©£¨6·Ö£©½«6.50 gпͶÈë200 mLijŨ¶ÈµÄÑÎËáÖУ¬Ð¿ºÍÑÎËáÇ¡ºÃÍêÈ«·´Ó¦¡£

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£¨2£©£¨8·Ö£©È¡º¬MnO₂µÄÈíÃÌ¿óʯ27.86g¸ú×ãÁ¿Å¨ÑÎËá·´Ó¦£¨ÔÓÖʲ»²ÎÓë·´Ó¦£©£¬ÖƵÃ17.75gCl₂£¨±ê×¼×´¿ö£©£¬·´Ó¦Ô­ÀíÈçÏ£º

MnO₂£«4HCl£¨Å¨£©==== MnCl₂£«Cl₂¡ü£«2H₂O

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Answer 1

_{½â£ºn(Zn)=6.5 g/65 g.mol-1=0.1 mol               (1·Ö)}

       _{Zn + 2HCl ==== ZnCl + H2                                              (1·Ö)}

        _{1    2               1}

     _{0.1mol   x              y}

_{½âµÃ£ºx=0.2mol           y=0.1mol                   (¸÷1·Ö)}

_{C(HCl)= 0.2mol/0.2L=1mol.L-1}  

_{V(H2)= 0.1mol*22.4 L. mol-1=2.24 L                  (¸÷1·Ö)}

_{£¨2£©£¨¹²8·Ö£©}

_{½â£ºn(Cl2)=17.75g/71g. mol-1=0.25 mol                   (1·Ö)}

MnO₂£«4HCl£¨Å¨£©==== MnCl₂£«Cl₂¡ü£«2H₂O        2e-   £¨1·Ö£©

              _{1    4                 1                    2}

              _{X     y               0.25 mol              z}

_{½âµÃ£ºx=0.25mol       y=1mol     z= 0.5mol        £¨¸÷1·Ö£©}

 _m(MnO_{2)=0.25mol*87g.mol-1=21.75g}

_w(MnO_{2)=21.75g*100%/27.86g=78%                       (1·Ö)}

_{±»Ñõ»¯µÄHClÕ¼²ÎÓë·´Ó¦µÄHCl µÄÒ»°ë¼´£º0.5mol        (2·Ö)}