ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿À±½·ËØÊÇÀ±½·µÄ»îÐԳɷ֣¬¿ÉÔÚ¿ÚÇ»ÖвúÉúׯÉոУ¬Äܹ»Æðµ½½µÑªÑ¹ºÍµ¨¹Ì´¼µÄ¹¦Ð§£¬½ø¶øÔںܴó³Ì¶ÈÉÏÔ¤·ÀÐÄÔಡ£¬Ò²ÄÜ»º½â¼¡Èâ¹Ø½ÚÌÛÍ´¡£À±½·ËØõ¥À໯ºÏÎïµÄͨʽ¿ÉÒÔ±íʾΪ
(RΪÌþ»ù)£¬ÆäÖÐÒ»ÖÖÀ±½·ËØõ¥À໯ºÏÎïJµÄºÏ³É·ÏßÈçͼËùʾ£º
![]()
ÒÑÖª£º¢ÙA¡¢B¡¢E»¥ÎªÍ¬ÏµÎÆäÖÐAµÄ·Ö×ÓʽΪC5H10O£¬BµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª44£¬AºÍBµÄºË´Å¹²ÕñÇâÆ×ÏÔʾ¶¼ÓÐÁ½×é·å¡£
¢ÚJµÄ·Ö×ÓʽΪC15H22O4¡£
¢ÛR1CHO£«R2CH2CHO![]()
¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)GÖÐËùº¬¹ÙÄÜÍŵÄÃû³ÆÎª__________¡£
(2)ÓÉAºÍBÉú³ÉCµÄ»¯Ñ§·½³ÌʽΪ__________¡£
(3)ÓÉCÉú³ÉDµÄ·´Ó¦ÀàÐÍΪ________£¬DµÄ»¯Ñ§Ãû³ÆÎª_________¡£
(4)ÓÉHÉú³ÉIµÄ»¯Ñ§·½³ÌʽΪ________¡£
(5)ÔÚGµÄͬ·ÖÒì¹¹ÌåÖУ¬±½»·ÉϵÄÒ»ÂÈ´úÎïÖ»ÓÐÒ»ÖֵĹ²ÓÐ_____ÖÖ(²»º¬Á¢ÌåÒì¹¹)£¬ÆäÖк˴ʲÕñÇâÆ×ÏÔʾÁ½×é·åµÄÊÇ_______(д½á¹¹¼òʽ)¡£
¡¾´ð°¸¡¿ÃѼü¡¢(·Ó)ôÇ»ù (2)(CH3)3CCHO£«CH3CHO![]()
¼Ó³É·´Ó¦(»ò»¹Ô·´Ó¦) 4,4-¶þ¼×»ù-1-Îì´¼
£«2NaOH![]()
£«NaCl£«H2O 8
¡¾½âÎö¡¿
»¯ºÏÎïJµÄ·Ö×ÓʽΪC15H22O4£¬½áºÏJµÄ½á¹¹Îª
£¬¹ÊRΪ¡ªC6H13£¬Òò´Ë½áºÏÁ÷³Ìͼ֪£¬IΪ
£¬FΪC6H13COOH£»Òò´ËGΪ
£¬HΪ
£»½áºÏÒÑÖªÐÅÏ¢£¬BµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª44£¬BºË´Å¹²ÕñÇâÆ×ÏÔʾÓÐÁ½×é·å£¬¹ÊBΪCH3CHO£»AºÍBΪͬϵÎÔòAΪC4H9CHO£¬AµÄºË´Å¹²ÕñÇâÆ×ÏÔʾÓÐÁ½×é·å£¬ÔòAΪ(CH3)3CCHO£¬CΪ(CH3)3CCH=CHCHO£¬DΪ(CH3)3CCH2CH2CH2OH£¬EΪ(CH3)3CCH2CH2CHO£¬FΪ(CH3)3CCH2CH2COOH£¬¾Ý´Ë·ÖÎö×÷´ð¡£
£¨1£©GΪ
£¬Ëùº¬¹ÙÄÜÍŵÄÓÐÃѼü£¬(·Ó)ôÇ»ù£¬¹Ê´ð°¸Îª£ºÃѼü£¬(·Ó)ôÇ»ù£»
£¨2£©AΪ(CH3)3CCHO£¬BΪCH3CHO£»AºÍBÉú³ÉCµÄ»¯Ñ§·½³ÌʽΪ(CH3)3CCHO£«CH3CHO![]()
£»
£¨3£©CΪ(CH3)3CCH =CHCHO£¬DΪ(CH3)3CCH2CH2CH2OH£¬CÓëÇâÆø·¢Éú¼Ó³É·´Ó¦Éú³ÉD£»DΪ(CH3)3CCH2CH2CH2OH£¬Ãû³ÆÎª4£¬4-¶þ¼×»ù-1-Îì´¼£¬¹Ê´ð°¸Îª£º¼Ó³É(»¹Ô)£»4£¬4-¶þ¼×»ù-1-Îì´¼£»
£¨4£©
ÔÚÇâÑõ»¯ÄÆÈÜÒºÖз¢ÉúË®½â·´Ó¦Éú³ÉI£¬»¯Ñ§·½³ÌʽΪ
£«2NaOH![]()
£«NaCl£«H2O£¬¹Ê´ð°¸Îª£º
£«2NaOH![]()
£«NaCl£«H2O£»
£¨5£©GΪ
£¬GµÄͬ·ÖÒì¹¹ÌåÖУ¬±½»·ÉϵÄÒ»ÂÈ´úÎïÖ»ÓÐÒ»ÖÖµÄÓÐ
¡¢
¡¢
¡¢
¡¢
¡¢
¡¢
¡¢
¹²8ÖÖ£»ÆäÖк˴ʲÕñÇâÆ×ÏÔʾ2×é·åµÄÊÇ
£¬¹Ê´ð°¸Îª£º8£»
¡£