Question

 ÏÖÓÐA¡¢B¡¢C¡¢D¡¢EÎåÖÖÇ¿µç½âÖÊ£¬ËüÃÇÔÚË®ÖпɵçÀë²úÉúÏÂÁÐÀë×Ó£¨¸÷ÖÖÀë×Ó²»Öظ´£©¡£

ÑôÀë×Ó	H+¡¢Na+¡¢A13+¡¢Ag+¡¢Ba2+
ÒõÀë×Ó	OH¡ª¡¢C1¡ª¡¢CO32-¡¢NO3¡ª¡¢SO42-

ÒÑÖª£º

¢ÙA¡¢BÁ½ÈÜÒº³Ê¼îÐÔ£»C¡¢D¡¢EÈÜÒº³ÊËáÐÔ¡£

¢ÚAÈÜÒºÓëEÈÜÒº·´Ó¦¼ÈÓÐÆøÌåÓÖÓгÁµí²úÉú£»AÈÜÒºÓëCÈÜÒº·´Ó¦Ö»ÓÐÆøÌå²úÉú£¨³Áµí°üÀ¨Î¢ÈÜÎÏÂͬ£©¡£

¢ÛDÈÜÒºÓëÁíÍâËÄÖÖÈÜÒº·´Ó¦¶¼ÄܲúÉú³Áµí£»CÖ»ÄÜÓëD·´Ó¦²úÉú³Áµí¡£

ÊԻشðÏÂÁÐÎÊÌ⣺

£¨1£©½«CÈÜÒºÖðµÎ¼ÓÈëµÈÌå»ý¡¢µÈÎïÖʵÄÁ¿µÄŨ¶ÈµÄAÈÜÒºÖУ¬·´Ó¦ºóÈÜÒºÖи÷ÖÖÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ£º                                                                 ¡£

£¨2£©Ð´³öEÈÜÒºÓë¹ýÁ¿µÄBÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ                                   ¡£

£¨3£©ÒÑÖª£ºNaOH£¨aq£©+HNO₃£¨aq£©= NaNO₃£¨aq£©+H₂O(1);¡÷H=£­a KJ¡¤mol^-1¡£Çëд³öBÓëCµÄÏ¡ÈÜÒº·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ                                                      ¡£

£¨4£©ÔÚ100mL0.1mol¡¤L^-1EÈÜÒºÖУ¬ÖðµÎ¼ÓÈë35mL 2mol¡¤L^-1NaOHÈÜÒº£¬×îÖյõ½³ÁµíÎïÖʵÄÁ¿Îª                   ¡£

 

Answer 1

 £¨1£©c£¨Na⁺£©>c£¨C1^£­£©>c£¨HCO₃^£­£©>c£¨OH^£­£©>c£¨H⁺£©> c£¨CO₃^2£­£©

»òc£¨Na⁺£©>c£¨C1^£­£©>c£¨HCO₃^£­£©>c£¨OH^£­£©>c£¨H⁺£©

£¨2£©2A1³⁺ + 3SO^2-₄ +3Ba²⁺ + 8OH = 2A1O₂^£­ + 3BaSO₄¡ý+ 4H₂O

£¨3£©OH^£­£¨aq£©+H⁺£¨aq£©= H₂O£¨1£©£»¡÷H =-aKJ/mol   

(ÎïÖʾۼ¯×´Ì¬¡¢·´Ó¦ÈÈÈÎÒ»·½Ãæ´í¶¼²»¸ø·Ö£©£¨4£©0.01mol