ÌâÄ¿ÄÚÈÝ
A¡¢B¡¢C¡¢D¡¢FÊdz£¼ûµÄ»¯ºÏÎÆäÖÐFÔÚ³£ÎÂÏÂÊÇÒ»ÖÖÎÞɫҺÌ壬DΪǿËᣬÇë¸ù¾ÝÏÂͼת»¯¹ØÏµ£¨·´Ó¦Ìõ¼þ¼°²¿·Ö²úÎïÒÑÂÔÈ¥£©£¬»Ø´ðÏÂÁÐÎÊÌ⣺![]()
£¨1£©ÈôA¡¢B¡¢C¡¢D¾ùΪº¬ÁòÔªËØµÄ»¯ºÏÎAÊÇÒ»ÖÖ³£¼ûµÄ¿óʯµÄÖ÷Òª³É·Ö£¬ÇÒAµÄĦ¶ûÖÊÁ¿Îª120
¡£ ·´Ó¦¢ÙµÄ»¯Ñ§·½³ÌʽΪ £»
£¨2£©ÈôA¡¢B¡¢C¡¢D¾ùΪº¬µªÔªËصϝºÏÎÇÒAµÄÒ»¸ö·Ö×ÓÖÐÖ»º¬ÓÐ10¸öµç×Ó£¬Ôò£º
¢ÙA·Ö×ÓʽΪ__________£»
¢Ú·´Ó¦¢ÜµÄÀë×Ó·½³ÌʽΪ________________________________________________
¢ÛÈ¡CuºÍCu2OµÄ»ìºÏÎïÑùÆ·12£®0g£¬¼ÓÈëµ½×ãÁ¿µÄDµÄÏ¡ÈÜÒºÖУ¬ÓÃÅÅË®·¨ÊÕ¼¯²úÉúµÄÆøÌ壬±ê×¼×´¿öÏÂÆäÌå»ýΪ2£®24L£¬ÔòÑùÆ·ÖÐCu2OµÄÖÊÁ¿Îª__________g¡£
£¨1£©4FeS2+11O2
Fe2O3+8SO2£»£¨2·Ö£©
£¨2£©¢ÙNH3 £»£¨2·Ö£©
¢Ú3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O£»£¨2·Ö£©
¢Û4£®32g£¨2·Ö£¬4£®3
Ò²µÃ·Ö£©
½âÎöÊÔÌâ·ÖÎö£º£¨1£©AÊÇÒ»ÖÖ³£¼ûµÄ¿óʯµÄÖ÷Òª³É·Ö£¬ÇÒAµÄĦ¶ûÖÊÁ¿Îª120
£¬AÊÇFeS2,EΪÑõÆø£¬Ôò·´Ó¦¢ÙµÄ»¯Ñ§·½³ÌʽΪ4FeS2+11O2
Fe2O3+8SO2£»
£¨2£©¢ÙA¡¢B¡¢C¡¢D¾ùΪº¬µªÔªËصϝºÏÎAµÄÒ»¸ö·Ö×ÓÖÐÖ»º¬ÓÐ10¸öµç×Ó£¬ÔòAÊÇNH3£»
¢ÚEÊÇÑõÆø,BÊÇNO£¬CÊÇNO2£¬FÊÇË®£¬DΪÏõËᣬËùÒÔ·´Ó¦¢ÜµÄÀë×Ó·½³ÌʽΪ3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O
¢ÛÉèCuºÍCu2OµÄÎïÖʵÄÁ¿·Ö±ðΪx¡¢y£¬¸ù¾ÝµÃʧµç×ÓÊØºã£¬2£®24L/22£®4L/mol¡Á3=2x+2y,¶þÕßµÄÖÊÁ¿Îª12£®0g£¬ËùÒÔÓÐ64x+144y=12£¬½âµÃy=0£®03mol,Òò´ËCu2OµÄÖÊÁ¿ÊÇ0£®03mol¡Á144g/mol=4£®32g
¿¼µã£º¿¼²éÁò¡¢µªµÄ»¯ºÏÎïµÄÍÆ¶Ï¼°ÐÔÖÊ£¬»¯Ñ§·½³Ìʽ¡¢Àë×Ó·½³ÌʽµÄÊéд£¬Ñõ»¯»¹Ô·´Ó¦µÄ¼ÆËã