ÌâÄ¿ÄÚÈÝ

¿ÕÆøÖÊÁ¿¸ßµÍÖ±½ÓÓ°Ïì×ÅÈËÀàµÄÉú²úºÍÉú»î£¬ËüÔ½À´Ô½Êܵ½ÈËÃǵĹØ×¢¡£±»ÎÛȾµÄ¿ÕÆøÖÐÔÓÖʵijɷÖÓжàÖÖ£¬ÆäÖмÆÈë¡¶¿ÕÆøÖÊÁ¿ÈÕ±¨¡·¿ÕÆøÎÛȾָÊýµÄÏîÄ¿ÓÐSO2¡¢CO¡¢NO2¡¢O3ºÍ¿ÉÎüÈë¿ÅÁ£ÎïµÈ¡£

   Çë»Ø´ðÏÂÁÐÎÊÌ⣺

¢Å S¡¢N¡¢OµÄµÚÒ»µçÀëÄÜÓÉ´óµ½Ð¡µÄ˳ÐòΪ                          ¡£

¢Æ Ѫºìµ°°×Öк¬ÓÐFe2£«£¬COÒ×ÓëѪºìµ°°×½áºÏ³ÉÎȶ¨µÄÅäºÏÎï¶øÊ¹ÈËÖж¾

¢Ù д³öÑÇÌúÀë×ӵĻù̬µç×ÓÅŲ¼Ê½                       ¡£

¢Ú COÓжàÖֵȵç×ÓÌ壬ÆäÖг£¼ûµÄÁ½ÖÖΪ                    ¡£CO½á¹¹ÖЦҼüºÍ§±¼üÊýĿ֮±ÈΪ                     

¢ÛFe(CO)5³£ÎÂϳÊҺ̬£¬ÈÛµãΪ£­20.5¡æ£¬·ÐµãΪ103¡æ£¬Ò×ÈÜÓڷǼ«ÐÔÈܼÁ£¬¾Ý´Ë¿ÉÅжÏFe(CO)5¾§ÌåÊôÓÚ    ___________   £¨Ìî¾§ÌåÀàÐÍ£©£¬FeÔªËØµÄ»¯ºÏ¼Û         ¡£

¢Ç SO2ÊÇÒ»ÖÖ´óÆøÎÛȾÎΪ¼õÇáSO2ÎÛȾ£¬»ðÁ¦·¢µç³§Éú²úÖг£ÔÚȼúÖмÓÈëCaOÒÔ¡°¹ÌÁò¡±¡£ CaO¾§°ûÈçͼËùʾ£¬ÆäÖÐCa2£«ÖÜΧµÄÒõÀë×ÓÅäλÊýΪ       £¬CaO¾§ÌåºÍNaCl¾§ÌåÖÐÀë×ÓÅÅÁз½Ê½Ïàͬ£¬Æä¾§¸ñÄÜ·Ö±ðΪ£ºCaO£º3401kJ/mol¡¢NaCl£º786kJ/mol¡£CaO¾§ÌåµÄÈ۵㠠     NaCl¾§ÌåµÄÈ۵㣨Ìî¡°¸ßÓÚ¡±¡¢¡°µÈÓÚ¡±»ò¡°µÍÓÚ¡±£©£¬µ¼ÖÂÁ½Õß¾§¸ñÄܲîÒìµÄÖ÷ÒªÔ­ÒòÊÇ                                             ¡£

¢È Ëæ×ÅÈËÃÇÉú»îÖÊÁ¿µÄÌá¸ß£¬²»½öÊÒÍâµÄ»·¾³°²È«ÎªÈËÃÇËùÖØÊÓ£¬ÊÒÄڵĻ·¾³°²È«ºÍʳƷ°²È«Ò²Ô½À´Ô½ÎªÈËÃÇËù¹Ø×¢¡£¼×È©ÊÇÊÒÄÚÖ÷Òª¿ÕÆøÎÛȾÎïÖ®Ò»£¨Æä·ÐµãÊÇ£­19.5 ¡æ£©£¬¼×´¼ÊÇ¡°¼Ù¾Æ¡±ÖеÄÖ÷ÒªÓк¦ÎïÖÊ£¨Æä·ÐµãÊÇ64.65 ¡æ£©£¬¼×´¼µÄ·ÐµãÃ÷ÏÔ¸ßÓÚ¼×È©µÄÖ÷ÒªÔ­ÒòÊÇ£º                                                                    ¡£

£¨12·Ö:ÿ¿Õ2·Ö£©

A£®¢Å N£¾O£¾S  

¢Æ ¢Ù  1s22s22p63s23d6   ¢Ú N2¡¢CN£­  1:2 ¢Û·Ö×Ó¾§Ìå   0

¢Ç  6¡¡¡¡¸ßÓÚ   CaO¾§ÌåÖÐÀë×ӵĵçºÉÊý´óÓÚNaCl

¢È  ¼×´¼·Ö×Ӽ䴿ÔÚÇâ¼ü£¬¶ø¼×ȩûÓÐ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¿ÕÆøÖÊÁ¿¸ßµÍÖ±½ÓÓ°Ïì×ÅÈËÀàµÄÉú²úºÍÉú»î£¬ËüÔ½À´Ô½Êܵ½ÈËÃǵĹØ×¢£®±»ÎÛȾµÄ¿ÕÆøÖÐÔÓÖʵijɷÖÓжàÖÖ£¬ÆäÖмÆÈë¡¶¿ÕÆøÖÊÁ¿ÈÕ±¨¡·¿ÕÆøÎÛȾָÊýµÄÏîÄ¿ÓÐSO2¡¢CO¡¢NO2¡¢O3ºÍ¿ÉÎüÈë¿ÅÁ£ÎïµÈ£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©S¡¢N¡¢OµÄµÚÒ»µçÀëÄÜÓÉ´óµ½Ð¡µÄ˳ÐòΪ
 
£®
£¨2£©Ñªºìµ°°×Öк¬ÓÐFe2+£¬COÒ×ÓëѪºìµ°°×½áºÏ³ÉÎȶ¨µÄÅäºÏÎï¶øÊ¹ÈËÖж¾£®
¢Ùд³öÑÇÌúÀë×ӵĻù̬µç×ÓÅŲ¼Ê½
 
£®
¢ÚCOÓжàÖֵȵç×ÓÌ壬ÆäÖг£¼ûµÄÁ½ÖÖΪ
 
£®¾«Ó¢¼Ò½ÌÍø
£¨3£©SO2ÊÇÒ»ÖÖ´óÆøÎÛȾÎΪ¼õÇáSO2ÎÛȾ£¬»ðÁ¦·¢µç³§Éú²úÖг£ÔÚȼúÖмÓÈëCaOÒÔ¡°¹ÌÁò¡±£® CaO¾§°ûÈçͼËùʾ£¬ÆäÖÐCa2+µÄÅäλÊýΪ
 
£¬CaO¾§ÌåºÍNaCl¾§ÌåÖÐÀë×ÓÅÅÁз½Ê½Ïàͬ£¬Æä¾§¸ñÄÜ·Ö±ðΪ£ºCaO£º3401kJ/mol¡¢NaCl£º786kJ/mol£®CaO¾§ÌåµÄÈÛµã
 
NaCl¾§ÌåµÄÈ۵㣨Ìî¡°¸ßÓÚ¡±¡¢¡°µÈÓÚ¡±»ò¡°µÍÓÚ¡±£©£®
£¨4£©Ëæ×ÅÈËÃÇÉú»îÖÊÁ¿µÄÌá¸ß£¬²»½öÊÒÍâµÄ»·¾³°²È«ÎªÈËÃÇËùÖØÊÓ£¬ÊÒÄڵĻ·¾³°²È«ºÍʳƷ°²È«Ò²Ô½À´Ô½ÎªÈËÃÇËù¹Ø×¢£®¼×È©ÊÇÊÒÄÚÖ÷Òª¿ÕÆøÎÛȾÎïÖ®Ò»£¨Æä·ÐµãÊÇ-19.5¡æ£©£¬¼×´¼ÊÇ¡°¼Ù¾Æ¡±ÖеÄÖ÷ÒªÓк¦ÎïÖÊ£¨Æä·ÐµãÊÇ64.65¡æ£©£¬¼×´¼µÄ·ÐµãÃ÷ÏÔ¸ßÓÚ¼×È©µÄÖ÷ÒªÔ­ÒòÊÇ£º
 
£®

¿ÕÆøÖÊÁ¿¸ßµÍÖ±½ÓÓ°Ïì×ÅÈËÀàµÄÉú²úºÍÉú»î£¬ËüÔ½À´Ô½Êܵ½ÈËÃǵĹØ×¢¡£±»ÎÛȾµÄ¿ÕÆøÖÐÔÓÖʵijɷÖÓжàÖÖ£¬ÆäÖмÆÈë¡¶¿ÕÆøÖÊÁ¿ÈÕ±¨¡·¿ÕÆøÎÛȾָÊýµÄÏîÄ¿ÓÐSO2¡¢CO¡¢NO2¡¢O3ºÍ¿ÉÎüÈë¿ÅÁ£ÎïµÈ¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©S¡¢N¡¢OµÄµÄµÚÒ»µçÀëÄÜÓÉ´óµ½Ð¡µÄ˳ÐòΪ                  ¡£

£¨2£©SO2¡¢CO¡¢NO2¡¢O3³£ÎÂϾùÎªÆøÌ壬¹Ì̬ʱ¾ùÊôÓÚ          ¾§Ìå¡£

£¨3£©Ëæ×ÅÈËÃÇÉú»îÖÊÁ¿µÄÌá¸ß£¬ÊÒÄڵĻ·¾³°²È«ºÍʳƷ°²È«Ô½À´Ô½ÎªÈËÃÇËù¹Ø×¢¡£¼×È©£¨HCHO£©ÊÇÊÒÄÚÖ÷Òª¿ÕÆøÎÛȾÎïÖ®Ò»£¨Æä·ÐµãÊǨC19.5 ¡æ£©£¬¼×´¼£¨CH3OH£©ÊÇ¡°¼Ù¾Æ¡±ÖеÄÖ÷ÒªÓк¦ÎïÖÊ£¨Æä·ÐµãÊÇ64.65 ¡æ£©¡£¼×È©·Ö×ÓÖÐCÔ­×Ó²ÉÈ¡        ÔÓ»¯¹ìµÀ·½Ê½¡£¼×´¼µÄ·ÐµãÃ÷ÏÔ¸ßÓÚ¼×È©µÄÖ÷ÒªÔ­ÒòÊÇ£º

__________                                      ¡£

£¨4£©CuClµÄÑÎËáÈÜÒºÄܹ»ÓëCO·¢Éú·´Ó¦£ºCuCl+CO+H2O=Cu(CO)Cl¡¤H2O£¬¸Ã·´Ó¦¿ÉÓÃÓڲⶨ¿ÕÆøÖÐCOº¬Á¿¡£

¢Ùд³öÍ­Ô­×ӵĻù̬µç×ÓÅŲ¼Ê½                          ¡£

¢ÚCuClµÄ¾§Ìå½á¹¹ÈçÏÂͼ¼×Ëùʾ£¬Óëͬһ¸öCl£­¾àÀë×î½üµÄÏàÁÚCu£«ÓР        ¸ö¡£

¢ÛCu(CO)Cl¡¤H2OµÄ½á¹¹ÈçÉÏͼÒÒËùʾ£¬Í¼Öбêʾ³ö8¸öÊǹ²¼Û¼ü£¬ÆäÖР          ¸öÊÇÅäλ¼ü£¬

 

£¨13·Ö£©

¿ÕÆøÖÊÁ¿¸ßµÍÖ±½ÓÓ°Ïì×ÅÈËÀàµÄÉú²úºÍÉú»î£¬ËüÔ½À´Ô½Êܵ½ÈËÃǵĹØ×¢¡£±»ÎÛȾµÄ¿ÕÆøÖÐÔÓÖʵijɷÖÓжàÖÖ£¬ÆäÖмÆÈë¡¶¿ÕÆøÖÊÁ¿ÈÕ±¨¡·¿ÕÆøÎÛȾָÊýµÄÏîÄ¿ÓÐSO2¡¢CO¡¢NO2¡¢O3ºÍ¿ÉÎüÈë¿ÅÁ£ÎïµÈ¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©S¡¢N¡¢OµÄµÄµÚÒ»µçÀëÄÜÓÉ´óµ½Ð¡µÄ˳ÐòΪ                  ¡£

£¨2£©SO2¡¢CO¡¢NO2¡¢O3³£ÎÂϾùÎªÆøÌ壬¹Ì̬ʱ¾ùÊôÓÚ          ¾§Ìå¡£

£¨3£©Ëæ×ÅÈËÃÇÉú»îÖÊÁ¿µÄÌá¸ß£¬ÊÒÄڵĻ·¾³°²È«ºÍʳƷ°²È«Ô½À´Ô½ÎªÈËÃÇËù¹Ø×¢¡£¼×È©£¨HCHO£©ÊÇÊÒÄÚÖ÷Òª¿ÕÆøÎÛȾÎïÖ®Ò»£¨Æä·ÐµãÊǨC19.5 ¡æ£©£¬¼×´¼£¨CH3OH£©ÊÇ¡°¼Ù¾Æ¡±ÖеÄÖ÷ÒªÓк¦ÎïÖÊ£¨Æä·ÐµãÊÇ64.65 ¡æ£©¡£¼×È©·Ö×ÓÖÐCÔ­×Ó²ÉÈ¡       ÔÓ»¯¹ìµÀ·½Ê½¡£¼×´¼µÄ·ÐµãÃ÷ÏÔ¸ßÓÚ¼×È©µÄÖ÷ÒªÔ­ÒòÊÇ£º__________                                  ¡£

£¨4£©CuClµÄÑÎËáÈÜÒºÄܹ»ÓëCO·¢Éú·´Ó¦£ºCuCl+CO+H2O=Cu(CO)Cl¡¤H2O£¬¸Ã·´Ó¦¿ÉÓÃÓڲⶨ¿ÕÆøÖÐCOº¬Á¿¡£

¢Ùд³öÍ­Ô­×ӵĻù̬µç×ÓÅŲ¼Ê½                           ¡£

¢ÚCuClµÄ¾§Ìå½á¹¹ÈçÏÂͼ¼×Ëùʾ£¬Óëͬһ¸öCl£­¾àÀë×î½üµÄÏàÁÚCu£«ÓР    ¸ö¡£

¢ÛCu(CO)Cl¡¤H2OµÄ½á¹¹ÈçÉÏͼÒÒËùʾ£¬Í¼Öбêʾ³ö8¸öÊǹ²¼Û¼ü£¬ÆäÖÐ6¸öÊÇÅäλ¼ü£¬ÇëÔÚͼÖÐÓüýÍ·±êʾ³ö¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø