ÌâÄ¿ÄÚÈÝ
£¨6·Ö£©2008Äê±±¾©°ÂÔË»áËùÓûð¾æÈ¼ÁÏΪ±ûÍ飨C3H8£©£¬Ï¤Äá°ÂÔË»áËùÓûð¾æÈ¼ÁÏΪ65%¶¡Í飨C4H10£©ºÍ35%±ûÍ飨C3H8£©£¬ÒÑÖª³£ÎÂÏÂ1mol±ûÍéȼÉշųö2220kJÈÈÁ¿£¬1molÕý¶¡ÍéȼÉշųö2878kJÈÈÁ¿£¬1molÒì¶¡ÍéȼÉշųö2869.6kJÈÈÁ¿¡£ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©±íʾÕý¶¡ÍéȼÉÕµÄÈÈ»¯Ñ§·´Ó¦·½³Ìʽ £»
£¨2£©ÏÂÁÐÓйØËµ·¨ÕýÈ·µÄÊÇ £»
£¨3£©ÒÑÖª1mol H2ȼÉÕÉú³ÉҺ̬ˮ·Å³öÈÈÁ¿ÊÇ285.8 kJ£¬ÏÖÓÐ5mol ÇâÆøºÍ±ûÍéµÄ»ìºÏÆøÌ壬ÍêȫȼÉÕʱ·ÅÈÈ3847kJ£¬ÔòÇâÆøºÍ±ûÍéµÄÌå»ý±ÈΪ ¡£
£¨1£©±íʾÕý¶¡ÍéȼÉÕµÄÈÈ»¯Ñ§·´Ó¦·½³Ìʽ £»
£¨2£©ÏÂÁÐÓйØËµ·¨ÕýÈ·µÄÊÇ £»
| A£®°ÂÔË»ð¾æÈ¼ÉÕʱµÄÄÜÁ¿×ª»¯Ö÷ÒªÊÇÓÉ»¯Ñ§ÄÜת±äΪÈÈÄÜ |
| B£®ÏàͬÌõ¼þÏ£¬Õý¶¡ÍéµÄÈÈÖµ±È±ûÍé´ó |
| C£®Õý¶¡Íé±ÈÒì¶¡Íé²»Îȶ¨ |
| D£®Òì¶¡Íé·Ö×ÓÖеÄ̼Çâ¼ü±ÈÕý¶¡ÍéµÄ¶à |
£¨1£©C4H10(Õý¶¡Í飬g) + 13/2O2(g)¡ú4CO2(g)+5H2O(l) ¡÷H=" -2878" kJ?mol-1_£¨2·Ö£¬ÆäËûºÏÀí´ð°¸¶¼¶Ô£©£»
£¨2£©A C£¨2·Ö£¬ÓдíÈ«¿Û£¬²»È«¿Û1·Ö£©£»
£¨3£©3:1£¨2·Ö£©
£¨2£©A C£¨2·Ö£¬ÓдíÈ«¿Û£¬²»È«¿Û1·Ö£©£»
£¨3£©3:1£¨2·Ö£©
£¨2£©B£ºÓÉÌâÉèÌõ¼þ¿ÉÖªµ¥Î»ÖÊÁ¿µÄ±ûÍéÓëÕý¶¡ÍéȼÉշųöµÄÈÈÁ¿·Ö±ðΪ50.5kJºÍ49.6£»C£ºµÈÁ¿µÄÕý¶¡ÍéÓëÒì¶¡ÍéȼÉշųöµÄÈÈÁ¿Ç°Õߴ󣬹ÊÕý¶¡Íé×ÔÉíµÄÄÜÁ¿´ó£¬Ïà¶Ô²»Îȶ¨¡£D£ºÁ½ÕßµÄ̼Çâ¼üÊýÄ¿Ïàͬ¡£
£¨3£©ÉèÇâÆøÎªxmol£¬Ôò285.8x £« 2220¡Á£¨5¡ªx£©=3847£¬Çó½â¼´¿É
£¨3£©ÉèÇâÆøÎªxmol£¬Ôò285.8x £« 2220¡Á£¨5¡ªx£©=3847£¬Çó½â¼´¿É
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿