ÌâÄ¿ÄÚÈÝ

25¡æÊ±£¬½«0.01molCH3COONaºÍ0.002molHClÈÜÓÚË®£¬ÐγÉ1L»ìºÏÈÜÒº¡£
£¨1£©¸ÃÈÜÒºÖдæÔÚ×Å________¸öƽºâÌåϵ£¬ÓõçÀë·½³Ìʽ»òÀë×Ó·½³Ìʽ±íʾ£º£¨¿ÉÌîÂú£¬Ò²¿É²»ÌîÂú£¬Èç²»¹»¿Õ£¬¿ÉÒÔÔÙ¼Ó£©a.____________b.____________c.____________
£¨2£©ÈÜÒºÖй²ÓÐ_______ÖÖ²»Í¬µÄÁ£×Ó
£¨3£©ÔÚÕâЩÁ£×ÓÖУ¬Å¨¶ÈΪ0.01mol/LµÄÊÇ____________£¬Å¨¶ÈΪ0.002mol/LµÄÊÇ____________£»
£¨4£©__________ºÍ__________Á½ÖÖÁ£×ÓÎïÖʵÄÁ¿Ö®ºÍµÈÓÚ0.01mol¡£
£¨1£©Èý£»a. CH3COOHCH3COO-+H+£»b. CH3COO-+H2OCH3COOH+OH-£»c. H2OOH-+H+£¨a,b,c¿Éµßµ¹Ë³Ðò£©
£¨2£©7
£¨3£©Na+£»Cl-
£¨4£©CH3COOH£»CH3COO-
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø