题目内容

已知：

(1)Zn(s)＋O2(g)ZnO(s)　ΔH＝－348.3 kJ/mol

(2)2Ag(s)＋O2(g)Ag2O(s)　ΔH＝－31.0 kJ/mol

则Zn(s)＋Ag2O(s)ZnO(s)＋2Ag(s)的ΔH等于

[　　]

A．

－317.3 kJ/mol

B．

－379.3 kJ/mol

C．

－332.8 kJ/mol

D．

317.3 kJ/mol

答案：A
解析：

根据盖斯定律，只要将“上式－下式”即可得Zn(s)＋Ag2O(s)ZnO(s)＋2Ag(s)　ΔH＝－317.3 kJ/mol．


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已知：(1)Zn(s)＋1/2O2(g) = ZnO(s)；ΔH =－348.3 kJ/mol；(2)2Ag(s)＋1/2O2(g) = Ag2O(s)；ΔH =－31.0 kJ/mol，则Zn(s)＋Ag2O(s) = ZnO(s)＋2Ag(s)的?ΔH等于（ ）

A．－317.3 kJ/molB．－379.3 kJ/molC．－332.8 kJ/molD．317.3 kJ/mol

已知： (1)Zn(s)＋1/2O2(g) = ZnO(s)；ΔH =－348.3 kJ/mol；(2)2Ag(s)＋1/2O2(g) = Ag2O(s)；ΔH =－31.0 kJ/mol，则Zn(s)＋Ag2O(s) = ZnO(s)＋2Ag(s)的ΔH等于（  ）

A．－317.3 kJ/mol         B．－379.3 kJ/mol      C．－332.8 kJ/mol           D．317.3 kJ/mol

 

已知：(1)Zn(s)＋1/2O2(g) = ZnO(s) △H =－348.3 kJ/mol

(2)  2Ag(s)＋1/2O2(g) = Ag2O(s) △H =－31.0 kJ/mol

则Zn(s)＋Ag2O(s) = ZnO(s)＋2Ag(s)的△H等于（    ）

A. －317.3 kJ/mol     B. －379.3 kJ/mol 

 C. －332.8 kJ/mol     D. 317.3 kJ/mol

 
已知：(1)Zn(s)+O2(g)ZnO(s)；ΔH=-348.3 kJ·mol-1

(2)2Ag(s)+O2(g)Ag2O(s)；ΔH=-31.0 kJ·mol-1

则Zn与Ag2O反应生成ZnO和Ag的热化学方程式为

A.Zn(s)+Ag2O(s)ZnO(s)+2Ag(s)；ΔH=317.3 kJ·mol-1

B.Zn+Ag2OZnO+2Ag；ΔH=317.3 kJ·mol-1

C.Zn(s)+Ag2O(s)ZnO(s)+2Ag(s)；ΔH=-317.3 kJ·mol-1

D.2Zn(s)+2Ag2O(s)2ZnO(s)+4Ag(s)；ΔH=-317.3 kJ

已知：(1)Zn(s)+O2(g)ZnO(s)；ΔH=-348.3 kJ·mol-1

(2)2Ag(s)+O2(g)Ag2O(s)；ΔH=-31.0 kJ·mol-1

则Zn与Ag2O反应生成ZnO和Ag的热化学方程式为

A.Zn(s)+Ag2O(s)ZnO(s)+2Ag(s)；ΔH=317.3 kJ·mol-1

B.Zn+Ag2OZnO+2Ag；ΔH=317.3 kJ·mol-1

C.Zn(s)+Ag2O(s)ZnO(s)+2Ag(s)；ΔH=-317.3 kJ·mol-1

D.2Zn(s)+2Ag2O(s)2ZnO(s)+4Ag(s)；ΔH=-317.3 kJ·mol-1

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