ÌâÄ¿ÄÚÈÝ
ÅäÖÆ0.25 mol¡¤L£1µÄNaOHÈÜÒº100 mL£¬Ä³Ñ§Éú²Ù×÷ÈçÏ£º
¢ÙÓÃÍÐÅÌÌìÆ½³Æ³ö1.00 gÇâÑõ»¯ÄÆ£º½«ÌìÆ½µ÷ºÃÁãµã£¬ÔÙÔÚÁ½ÅÌÉϸ÷·ÅÒ»ÕÅͬÑùÖÊÁ¿µÄÖ½£¬°ÑÓÎÂëµ÷µ½1.00 gµÄλÖÃÉÏ£¬ÓÚ×óÅÌ·ÅÁ£×´ÇâÑõ»¯ÄÆÖÁÌìÆ½Æ½ºâ£¬È¡Ï³ƺõÄÇâÑõ»¯ÄÆ£¬²¢³·µôÁ½ÅÌÉϵÄÖ½£®
¢Ú°Ñ³ÆºÃµÄÇâÑõ»¯ÄÆ·ÅÈëÒ»Ö»100 mLµÄÉÕ±ÖУ¬¼ÓÈëÔ¼10 mLË®£¬½Á°èʹ֮Èܽ⣬ÈܽâºóÁ¢¼´Óò£Á§°ôÒýÁ÷½«ÈÜÒºÒÆÖÁÒ»Ö»100 mLµÄÈÝÁ¿Æ¿ÄÚ£¬¼ÓË®ÖÁÀë¿Ì¶ÈÏßÔ¼2 cm´¦£¬ÓõιܼÓË®ÖÁ¿Ì¶ÈÏߣ®
¢Ûд³öÒ»¸ö±êÓÐÅäÖÆÈÕÆÚµÄ¡°0.25 mol¡¤L£1¡¡NaOHÈÜÒº¡±µÄ±êÇ©£¬ÌùÔÚÈÝÁ¿Æ¿ÉÏÃܱձ£´æ£®
Ö¸³öÉÏÊö²Ù×÷ÖеÄ7´¦´íÎó£º
(1)________£»(2)________£»(3)________£»(4)________£»
(5)________£»(6)________£»(7)________£®
½âÎö£º
|
(1)NaOH·ÅÔÚֽƬÉϳÆÁ¿¡¡(2)ÓùýµÄÓÎÂë䲦»ØÔ´¦¡¡(3)ÍÐÅÌÌìÆ½³Æ³ö1.00 gµÄÇâÑõ»¯ÄÆ¡¡(4)ÉÕ±ºÍ²£Á§°ôδϴµÓ£¬Ï´µÓÒºÒàδתÈëÈÝÁ¿Æ¿¡¡(5)ÈܽâNaOHδÀäÈ´¾Í×ªÒÆÖÁÈÝÁ¿Æ¿ÖС¡(6)ÈÝÁ¿Æ¿ÖеÄÈÜҺδҡÔÈ¡¡(7)ÅäºÃµÄÈÜÒº·ÅÔÚÈÝÁ¿Æ¿Öб£´æ |