ÌâÄ¿ÄÚÈÝ
ÔÚÒ»¹Ì¶¨Ìå»ýµÄÃܱÕÈÝÆ÷ÖУ¬ÓÐÏÂÁл¯Ñ§·´Ó¦£ºCO£¨g£©+H2O£¨g£©?CO2£¨g£©+H 2£¨g£©£¬Æä»¯Ñ§Æ½ºâ³£ÊýKºÍζÈTµÄ¹ØÏµÈçϱí| T£¨¡æ£© | 700 | 800 | 830 | 1000 | 1200 |
| K | 0.6 | 0.9 | 1.0 | 1.7 | 2.6 |
A£®ÆäËûÌõ¼þ²»±ä£¬Éý¸ßζȣ¬COµÄת»¯Âʱä´ó
B£®Î¶ÈÉý¸ß£¬Õý¡¢Äæ·´Ó¦ËÙÂʶ¼Ôö´ó£¬ÔÚÆ½ºâÒÆ¶¯µÄ¹ý³ÌÖÐÆøÌåѹǿʼÖÕ±£³Ö²»±ä
C£®·´Ó¦´ïƽºâʱ£¬»ìºÏÆøÌåµÄƽ¾ùĦ¶ûÖÊÁ¿M£º18£¼M£¼26
D£®ÈôÔÚijƽºâ״̬ʱ£¬c£¨CO2£©×c£¨H2£©=c£¨CO£©×c£¨H2O£©£¬Ôò´ËʱµÄζÈΪ830¡æ
B¡¢¸Ã·´Ó¦ÎªÆøÌåÌå»ý²»±äµÄ·´Ó¦£¬ÈÝÆ÷µÄÌå»ý²»±ä£¬Éý¸ßζȣ¬Ñ¹Ç¿Ôö´ó£»
C¡¢·´Ó¦»ìºÏÆøÌåµÄ×ÜÖÊÁ¿²»±ä£¬×ܵÄÎïÖʵÄÁ¿²»±ä£¬Æ½¾ùĦ¶ûÖÊÁ¿Îª¶¨Öµ£¬ÓëÆðʼÎïÖʼ°¸÷ÎïÖʵÄÎïÖʵÄÁ¿Óйأ»
D¡¢ÔÚijƽºâ״̬ʱ£¬c£¨CO2£©×c£¨H2£©=c£¨CO£©×c£¨H2O£©£¬Ôò˵Ã÷ƽºâ³£Êýk=1£¬¾Ý´ËÅжϣ®
½â´ð£º½â£ºA¡¢ÓɱíÖÐÊý¾Ý¿ÉÖª£¬Î¶ÈÉý¸ß£¬Æ½ºâ³£ÊýÔö´ó£¬¹ÊÉý¸ßÎÂ¶ÈÆ½ºâÏòÕý·´Ó¦Òƶ¯£¬COµÄת»¯ÂÊÔö´ó£¬¹ÊAÕýÈ·£»
B¡¢¸Ã·´Ó¦ÎªÆøÌåÌå»ý²»±äµÄ·´Ó¦£¬ÈÝÆ÷µÄÌå»ý²»±ä£¬Éý¸ßζȣ¬Ñ¹Ç¿Ôö´ó£¬¹ÊB´íÎó£»
C¡¢·´Ó¦»ìºÏÆøÌåµÄ×ÜÖÊÁ¿²»±ä£¬×ܵÄÎïÖʵÄÁ¿²»±ä£¬Æ½¾ùĦ¶ûÖÊÁ¿Îª¶¨Öµ£¬·´Ó¦²»Ò»¶¨ÊÇ´ÓÕý·´Ó¦½øÐУ¬ÓëÆðʼÎïÖʼ°¸÷ÎïÖʵÄÎïÖʵÄÁ¿Óйأ¬¹Êƽ¾ùĦ¶ûÖÊÁ¿²»Ò»¶¨½éÓÚ18¡«26Ö®¼ä£¬¹ÊC´íÎó£»
D¡¢ÔÚijƽºâ״̬ʱ£¬c£¨CO2£©×c£¨H2£©=c£¨CO£©×c£¨H2O£©£¬Ôò˵Ã÷ƽºâ³£Êýk=1£¬ÓɱíÖÐÊý¾Ý¿ÉÖª£¬¸ÃζÈΪ830¡æ£¬¹ÊDÕýÈ·£»
¹ÊÑ¡BC£®
µãÆÀ£º±¾Ì⿼²é»¯Ñ§Æ½ºâµÄ¼ÆËãÓëÓ°ÏìÒòËØ¡¢»¯Ñ§Æ½ºâ³£ÊýµÈ£¬ÄѶÈÖеȣ¬BÑ¡ÏîΪÒ×´íµã£¬ÔÚ´ËÈÝÒ׺öÂÔζȶÔѹǿµÄÓ°Ï죮
£¨14·Ö£¬Ã¿¿Õ2·Ö£©
I£®ºÏ³É°±¹¤Òµ¶Ô¹úÃñ¾¼ÃºÍÉç»á·¢Õ¹¾ßÓÐÖØÒªµÄÒâÒå¡£ÆäÔÀíΪ£º
N2(g)+3H2(g) 2NH3(g) ¡÷H= -92.4 kJ/mol ¾Ý´Ë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©ÎªÁËÌá¸ß°±ÆøµÄ²úÂÊ£¬¿ÉÒÔÑ¡ÔñµÄ·½·¨ÊÇ _______ £¨ÌîÐòºÅ£¬´íÑ¡¿Û·Ö£©¡£
¢Ù Éý¸ßÎÂ¶È ¢Ú Ôö´óѹǿ ¢Û ʹÓô߻¯¼Á ¢Ü ¼°Ê±·ÖÀë³öNH3
£¨2£©¶ÔÔÚÃܱÕÈÝÆ÷ÖнøÐеĿÉÄæ·´Ó¦£ºN2(g)+3H2(g)2NH3(g)£¬ÏÂÁÐÄÄÖÖÇé¿öÏ£¬
˵Ã÷¸Ã·´Ó¦ÒѾ´ïµ½»¯Ñ§Æ½ºâ״̬____________________________________¡£
¢ÙN2µÄÕý·´Ó¦ËÙÂÊÊÇNH3µÄÄæ·´Ó¦ËÙÂʵÄ1/2
¢ÚÔÚºãÈÝÌõ¼þÏ£¬»ìºÏÆøÌåµÄѹǿ±£³Ö²»±ä
¢ÛN2¡¢H2¡¢NH3µÄÎïÖʵÄÁ¿Ö®±ÈΪ1£º3£º2
¢Üµ¥Î»Ê±¼äÄÚÿÉú³É3mol H2µÄͬʱÓÐ2mol NH3Éú³É
¢Ý3mol N-N¼ü¶ÏÁÑ£¬Í¬Ê±ÓÐ6mol N-H¼ü¶ÏÁÑ
£¨3£©Ò»¶¨Ìõ¼þÏ£¬NH3Ôڹ̶¨Ìå»ýµÄÃܱÕÈÝÆ÷Öз¢Éú·Ö½â·´Ó¦£¨¡÷H£¾0£©²¢´ïƽºâºó£¬½ö¸Ä±äϱíÖз´Ó¦Ìõ¼þx£¬¸ÃƽºâÌåϵÖÐËæxµÝÔöyµÝ¼õµÄÊǣߣߣߣß____________£¨Ñ¡ÌîÐòºÅ£©¡£
| Ñ¡Ïî | a | b | c | d |
| x | ÎÂ¶È | ÎÂ¶È | ¼ÓÈëH2µÄÎïÖʵÄÁ¿ | ¼ÓÈëNH3µÄÎïÖʵÄÁ¿ |
| y | NH3µÄÎïÖʵÄÁ¿ | ƽºâ³£ÊýK | NH3µÄת»¯ÂÊ | Éú³ÉÎïÎïÖʵÄÁ¿×ÜºÍ |
II£®£¨1£©ÔÚËáÐÔÈÜÒºÖУ¬µâËá¼Ø(KIO3)ºÍÑÇÁòËáÄÆ¿É·¢ÉúÈçÏ·´Ó¦£º
2IO3££«5SO32££«2H£«===I2£«5SO42££«H2O
Éú³ÉµÄµâ¿ÉÒÔÓõí·ÛÈÜÒº¼ìÑ飬¸ù¾Ý·´Ó¦ÈÜÒº³öÏÖÀ¶É«ËùÐèµÄʱ¼äÀ´ºâÁ¿¸Ã·´Ó¦µÄËÙÂÊ¡£
ijͬѧÉè¼ÆÊµÑéÈçϱíËùʾ£º
|
| 0.01mol¡¤L£1 KIO3ËáÐÔÈÜÒº(º¬µí·Û)µÄÌå»ý/mL | 0.01mol¡¤L£1 Na2SO3ÈÜÒºµÄÌå»ý/mL | H2OµÄÌå»ý /mL | ʵÑé ÎÂ¶È /¡æ | ÈÜÒº³öÏÖÀ¶É«Ê±ËùÐèʱ¼ä/s |
| ʵÑé1 | 5 | V1 | 35 | 25 | --------- |
| ʵÑé2 | 5 | 5 | 40 | 25 | ---------- |
| ʵÑé3 | 5 | 5 | V2 | 0 | ----------- |
¸ÃʵÑéµÄÄ¿µÄÊÇ_______________________________________________________________
________________________________________________£»
±íÖÐV1=___________mL.
£¨2£©¿ÉÄæ·´Ó¦C(s)+H2O(g) H2(g)+CO(g)£¬¡÷H>0´ïµ½Æ½ºâºó£¬¸Ä±äijһÍâ½çÌõ¼þ£¨²»¸Ä±äÎïÖʵÄÁ¿µÄÌõ¼þÏ£©£¬·´Ó¦ËÙÂÊ
Óëʱ¼ätµÄ¹ØÏµÈçÓÒͼ¡£
¢ÙͼÖÐt4µ½t6¶ÎʱÒýÆðƽºâÒÆ¶¯µÄÌõ¼þ¿ÉÄÜÊÇ £»
¢ÚͼÖбíʾƽºâ»ìºÏÎïÖÐCOµÄº¬Á¿×î¸ßµÄÒ»¶Îʱ¼äÊÇ ¡£
![]()
£¨14·Ö£¬Ã¿¿Õ2·Ö£©
I£®ºÏ³É°±¹¤Òµ¶Ô¹úÃñ¾¼ÃºÍÉç»á·¢Õ¹¾ßÓÐÖØÒªµÄÒâÒå¡£ÆäÔÀíΪ£º
N2(g)+3H2
(g)
2NH3(g) ¡÷H=" -92.4" kJ/mol ¾Ý´Ë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©ÎªÁËÌá¸ß°±ÆøµÄ²úÂÊ£¬¿ÉÒÔÑ¡ÔñµÄ·½·¨ÊÇ _______£¨ÌîÐòºÅ£¬´íÑ¡¿Û·Ö£©¡£
¢Ù Éý¸ßÎÂ¶È ¢Ú Ôö´óѹǿ ¢Û ʹÓô߻¯¼Á ¢Ü ¼°Ê±·ÖÀë³öNH3
£¨2£©¶ÔÔÚÃܱÕÈÝÆ÷ÖнøÐеĿÉÄæ·´Ó¦£ºN2(g)+3H2(g)
2NH3(g)£¬ÏÂÁÐÄÄÖÖÇé¿öÏ£¬
˵Ã÷¸Ã·´Ó¦ÒѾ´ïµ½»¯Ñ§Æ½ºâ״̬____________________________________¡£
¢ÙN2µÄÕý·´Ó¦ËÙÂÊÊÇNH3µÄÄæ·´Ó¦ËÙÂʵÄ1/2
¢ÚÔÚºãÈÝÌõ¼þÏ£¬»ìºÏÆøÌåµÄѹǿ±£³Ö²»±ä
¢ÛN2¡¢H2¡¢NH3µÄÎïÖʵÄÁ¿Ö®±ÈΪ1£º3£º2
¢Üµ¥Î»Ê±¼äÄÚÿÉú³É3mol H2µÄͬʱÓÐ2mol NH3Éú³É
¢Ý3mol N-N¼ü¶ÏÁÑ£¬Í¬Ê±ÓÐ6mol N-H¼ü¶ÏÁÑ
£¨3£©Ò»¶¨Ìõ¼þÏ£¬NH3Ôڹ̶¨Ìå»ýµÄÃܱÕÈÝÆ÷Öз¢Éú·Ö½â·´Ó¦£¨¡÷H£¾0£©²¢´ïƽºâºó£¬½ö¸Ä±äϱíÖз´Ó¦Ìõ¼þx£¬¸ÃƽºâÌåϵÖÐËæxµÝÔöyµÝ¼õµÄÊǣߣߣߣß____________£¨Ñ¡ÌîÐòºÅ£©¡£
| Ñ¡Ïî | a | b | c | d |
| x | ÎÂ¶È | ÎÂ¶È | ¼ÓÈëH2µÄÎïÖʵÄÁ¿ | ¼ÓÈëNH3µÄÎïÖʵÄÁ¿ |
| y | NH3µÄÎïÖʵÄÁ¿ | ƽºâ³£ÊýK | NH3µÄת»¯ÂÊ | Éú³ÉÎïÎïÖʵÄÁ¿×ÜºÍ |
II£®£¨1£©ÔÚËáÐÔÈÜÒºÖУ¬µâËá¼Ø(KIO3)ºÍÑÇÁòËáÄÆ¿É·¢ÉúÈçÏ·´Ó¦£º
2IO3££«5SO32££«2H£«===I2£«5SO42££«H2O
Éú³ÉµÄµâ¿ÉÒÔÓõí·ÛÈÜÒº¼ìÑ飬¸ù¾Ý·´Ó¦ÈÜÒº³öÏÖÀ¶É«ËùÐèµÄʱ¼äÀ´ºâÁ¿¸Ã·´Ó¦µÄËÙÂÊ¡£
ijͬѧÉè¼ÆÊµÑéÈçϱíËùʾ£º
| | 0.01mol¡¤L£1 KIO3ËáÐÔÈÜÒº(º¬µí·Û)µÄÌå»ý/mL | 0.01mol¡¤L£1 Na2SO3ÈÜÒºµÄÌå»ý/mL | H2OµÄÌå»ý /mL | ʵÑé ÎÂ¶È /¡æ | ÈÜÒº³öÏÖÀ¶É«Ê±ËùÐèʱ¼ä/s |
| ʵÑé1 | 5 | V1 | 35 | 25 | --------- |
| ʵÑé2 | 5 | 5 | 40 | 25 | ---------- |
| ʵÑé3 | 5 | 5 | V2 | 0 | ----------- |
________________________________________________£»
±íÖÐV1=___________mL.
£¨2£©¿ÉÄæ·´Ó¦C(s)+H2O(g)
¢ÙͼÖÐt4µ½t6¶ÎʱÒýÆðƽºâÒÆ¶¯µÄÌõ¼þ¿ÉÄÜÊÇ
¢ÚͼÖбíʾƽºâ»ìºÏÎïÖÐCOµÄº¬Á¿×î¸ßµÄÒ»¶Îʱ¼äÊÇ ¡£
£¨14·Ö£¬Ã¿¿Õ2·Ö£©
I£®ºÏ³É°±¹¤Òµ¶Ô¹úÃñ¾¼ÃºÍÉç»á·¢Õ¹¾ßÓÐÖØÒªµÄÒâÒå¡£ÆäÔÀíΪ£º
N2(g)+3H2(g)
2NH3(g) ¡÷H= -92.4 kJ/mol ¾Ý´Ë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©ÎªÁËÌá¸ß°±ÆøµÄ²úÂÊ£¬¿ÉÒÔÑ¡ÔñµÄ·½·¨ÊÇ _______ £¨ÌîÐòºÅ£¬´íÑ¡¿Û·Ö£©¡£
¢Ù Éý¸ßÎÂ¶È ¢Ú Ôö´óѹǿ ¢Û ʹÓô߻¯¼Á ¢Ü ¼°Ê±·ÖÀë³öNH3
£¨2£©¶ÔÔÚÃܱÕÈÝÆ÷ÖнøÐеĿÉÄæ·´Ó¦£ºN2(g)+3H2(g)
2NH3(g)£¬ÏÂÁÐÄÄÖÖÇé¿öÏ£¬
˵Ã÷¸Ã·´Ó¦ÒѾ´ïµ½»¯Ñ§Æ½ºâ״̬____________________________________¡£
¢ÙN2µÄÕý·´Ó¦ËÙÂÊÊÇNH3µÄÄæ·´Ó¦ËÙÂʵÄ1/2
¢ÚÔÚºãÈÝÌõ¼þÏ£¬»ìºÏÆøÌåµÄѹǿ±£³Ö²»±ä
¢ÛN2¡¢H2¡¢NH3µÄÎïÖʵÄÁ¿Ö®±ÈΪ1£º3£º2
¢Üµ¥Î»Ê±¼äÄÚÿÉú³É3mol H2µÄͬʱÓÐ2mol NH3Éú³É
¢Ý3mol N-N¼ü¶ÏÁÑ£¬Í¬Ê±ÓÐ6mol N-H¼ü¶ÏÁÑ
£¨3£©Ò»¶¨Ìõ¼þÏ£¬NH3Ôڹ̶¨Ìå»ýµÄÃܱÕÈÝÆ÷Öз¢Éú·Ö½â·´Ó¦£¨¡÷H£¾0£©²¢´ïƽºâºó£¬½ö¸Ä±äϱíÖз´Ó¦Ìõ¼þx£¬¸ÃƽºâÌåϵÖÐËæxµÝÔöyµÝ¼õµÄÊǣߣߣߣß____________£¨Ñ¡ÌîÐòºÅ£©¡£
|
Ñ¡Ïî |
a |
b |
c |
d |
|
x |
ÎÂ¶È |
ÎÂ¶È |
¼ÓÈëH2µÄÎïÖʵÄÁ¿ |
¼ÓÈëNH3µÄÎïÖʵÄÁ¿ |
|
y |
NH3µÄÎïÖʵÄÁ¿ |
ƽºâ³£ÊýK |
NH3µÄת»¯ÂÊ |
Éú³ÉÎïÎïÖʵÄÁ¿×ÜºÍ |
II£®£¨1£©ÔÚËáÐÔÈÜÒºÖУ¬µâËá¼Ø(KIO3)ºÍÑÇÁòËáÄÆ¿É·¢ÉúÈçÏ·´Ó¦£º
2IO3££«5SO32££«2H£«===I2£«5SO42££«H2O
Éú³ÉµÄµâ¿ÉÒÔÓõí·ÛÈÜÒº¼ìÑ飬¸ù¾Ý·´Ó¦ÈÜÒº³öÏÖÀ¶É«ËùÐèµÄʱ¼äÀ´ºâÁ¿¸Ã·´Ó¦µÄËÙÂÊ¡£
ijͬѧÉè¼ÆÊµÑéÈçϱíËùʾ£º
|
|
0.01mol¡¤L£1 KIO3ËáÐÔÈÜÒº(º¬µí·Û)µÄÌå»ý/mL |
0.01mol¡¤L£1 Na2SO3ÈÜÒºµÄÌå»ý/mL |
H2OµÄÌå»ý /mL |
ʵÑé ÎÂ¶È /¡æ |
ÈÜÒº³öÏÖÀ¶É«Ê±ËùÐèʱ¼ä/s |
|
ʵÑé1 |
5 |
V1 |
35 |
25 |
--------- |
|
ʵÑé2 |
5 |
5 |
40 |
25 |
---------- |
|
ʵÑé3 |
5 |
5 |
V2 |
0 |
----------- |
¸ÃʵÑéµÄÄ¿µÄÊÇ_______________________________________________________________
________________________________________________£»
±íÖÐV1=___________mL.
£¨2£©¿ÉÄæ·´Ó¦C(s)+H2O(g)
H2(g)+CO(g)£¬¡÷H>0´ïµ½Æ½ºâºó£¬¸Ä±äijһÍâ½çÌõ¼þ£¨²»¸Ä±äÎïÖʵÄÁ¿µÄÌõ¼þÏ£©£¬·´Ó¦ËÙÂÊ
Óëʱ¼ätµÄ¹ØÏµÈçÓÒͼ¡£
¢ÙͼÖÐt4µ½t6¶ÎʱÒýÆðƽºâÒÆ¶¯µÄÌõ¼þ¿ÉÄÜÊÇ £»
¢ÚͼÖбíʾƽºâ»ìºÏÎïÖÐCOµÄº¬Á¿×î¸ßµÄÒ»¶Îʱ¼äÊÇ ¡£
![]()