ÌâÄ¿ÄÚÈÝ
¼×´¼£¨CH3OH£©×÷ΪÐÂÐÍÆû³µ¶¯Á¦È¼ÁÏ£¬ÒÔÏÂÊǼ״¼ÔÚ¹¤ÒµÉϵÄÖÆ±¸ºÍÉú»îÖеÄÓ¦Óá£
ÇëÌî¿Õ£º
£¨1£©ÔÚѹǿΪ0.1MPaÌõ¼þÏ£¬·´Ó¦ÊÒ2£¨ÈÝ»ýΪVL£©ÖÐa mol COÓë2a mol H2ÔÚ´ß»¯¼Á×÷ÓÃÏ·´Ó¦Éú³É¼×´¼£ºCO (g) +2H2(g)
CH3OH (g)£¬COµÄƽºâת»¯ÂÊÓëζȡ¢Ñ¹Ç¿µÄ¹ØÏµÈçͼËùʾ£¬Ôò£º
£¨1£©ÔÚѹǿΪ0.1MPaÌõ¼þÏ£¬·´Ó¦ÊÒ2£¨ÈÝ»ýΪVL£©ÖÐa mol COÓë2a mol H2ÔÚ´ß»¯¼Á×÷ÓÃÏ·´Ó¦Éú³É¼×´¼£ºCO (g) +2H2(g)
¢ÙÒ»¶¨Ìõ¼þϵÄÃܱÕÈÝÆ÷ÖÐ,¸Ã·´Ó¦µ½´ïƽºâ,ÒªÌá¸ßCOµÄת»¯ÂÊ¿ÉÒÔ²ÉÈ¡µÄ´ëÊ©ÊÇ_______ (Ìî×Öĸ´úºÅ)
A£®¸ßθßѹ B£®¼ÓÈë´ß»¯¼Á C£®Ôö¼ÓCOµÄŨ¶È D£®Ôö´óÇâÆøµÄŨ¶È E·ÖÀë³ö¼×´¼
¢ÚÔÚѹǿP1¡¢100¡æÊ±£¬CH3OH(g)
CO(g) + 2H2(g)·´Ó¦µÄƽºâ³£ÊýΪ________£¨Óú¬a¡¢VµÄ´úÊýʽ±íʾ£©
¢Û½«Ò»¶¨Á¿µÄNO2ÓëSO2ÖÃÓÚ¾øÈȺãÈÝÃܱÕÈÝÆ÷Öз¢ÉúNO2£¨g£©+SO2£¨g£©
SO3£¨g£©+NO£¨g£©ÉÏÊö·´Ó¦£¬Õý·´Ó¦ËÙÂÊËæÊ±¼ä±ä»¯µÄÇ÷ÊÆÈçͼËùʾ¡£ÓÉͼ¿ÉÖªÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ__________£¨Ìî×Öĸ£©¡£
A£®¸ßθßѹ B£®¼ÓÈë´ß»¯¼Á C£®Ôö¼ÓCOµÄŨ¶È D£®Ôö´óÇâÆøµÄŨ¶È E·ÖÀë³ö¼×´¼
¢ÚÔÚѹǿP1¡¢100¡æÊ±£¬CH3OH(g)
¢Û½«Ò»¶¨Á¿µÄNO2ÓëSO2ÖÃÓÚ¾øÈȺãÈÝÃܱÕÈÝÆ÷Öз¢ÉúNO2£¨g£©+SO2£¨g£©
A£®·´Ó¦ÔÚcµã´ïµ½Æ½ºâ״̬
B£®·´Ó¦ÎïŨ¶È£ºaµãСÓÚbµã
C£®·´Ó¦ÎïµÄ×ÜÄÜÁ¿¸ßÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿
D£®¡÷t1=¡÷t2ʱ£¬SO2µÄÏûºÄÁ¿£ºa¡«b¶Î´óÓÚb¡«c¶Î
£¨2£©¾Ý±¨µÀ£¬¿ÆÑ§¼ÒÔÚʵÑéÊÒÒÑÑÐÖÆ³öÔÚȼÁÏµç³ØµÄ·´Ó¦ÈÝÆ÷ÖУ¬ÀûÓÃÌØÊâµç¼«²ÄÁÏÒÔH2ºÍO2ΪÔÁÏÖÆÈ¡¹ýÑõ»¯ÇâµÄй¤ÒÕ¡£ÔÀíÈçͼËùʾ£ºÇëд³ö¼×µç¼«µÄµç¼«·´Ó¦Ê½£º________________________¡£
B£®·´Ó¦ÎïŨ¶È£ºaµãСÓÚbµã
C£®·´Ó¦ÎïµÄ×ÜÄÜÁ¿¸ßÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿
D£®¡÷t1=¡÷t2ʱ£¬SO2µÄÏûºÄÁ¿£ºa¡«b¶Î´óÓÚb¡«c¶Î
£¨2£©¾Ý±¨µÀ£¬¿ÆÑ§¼ÒÔÚʵÑéÊÒÒÑÑÐÖÆ³öÔÚȼÁÏµç³ØµÄ·´Ó¦ÈÝÆ÷ÖУ¬ÀûÓÃÌØÊâµç¼«²ÄÁÏÒÔH2ºÍO2ΪÔÁÏÖÆÈ¡¹ýÑõ»¯ÇâµÄй¤ÒÕ¡£ÔÀíÈçͼËùʾ£ºÇëд³ö¼×µç¼«µÄµç¼«·´Ó¦Ê½£º________________________¡£
£¨3£©Èô³£ÎÂÏÂÒ»¶¨Á¿µÄ¼×´¼ÍêȫȼÉÕÉú³ÉҺ̬ˮÊͷųöÁË1451.52 kJµÄÄÜÁ¿£¬ÔòµÈÖÊÁ¿µÄ¼×´¼È¼ÁÏµç³ØÀûÀíÂÛÉÏ¿ÉÌṩ________molµç×ӵĵçÁ¿¡££¨ÒÑÖª¼×´¼µÄȼÉÕÈÈΪ725.76 kJ/mol£©
£¨4£©ÒÑÖªÔÚ³£Î³£Ñ¹Ï£º
¢Ù2CH3OH (l)£«3O2(g) == 2CO2(g)£«4H2O (g)¡¡¦¤H1£½£1275.6 kJ/mol
¢Ú2CO (g)£«O2(g) == 2CO2(g) ¦¤H2£½£566.0 kJ/mol
¢ÛH2O (g) = H2O (l)¡¡¦¤H3£½£44.0 kJ/mol
д³ö¼×´¼²»ÍêȫȼÉÕÉú³ÉÒ»Ñõ»¯Ì¼ºÍҺ̬ˮµÄÈÈ»¯Ñ§·½³Ìʽ£º_____________________¡£
£¨4£©ÒÑÖªÔÚ³£Î³£Ñ¹Ï£º
¢Ù2CH3OH (l)£«3O2(g) == 2CO2(g)£«4H2O (g)¡¡¦¤H1£½£1275.6 kJ/mol
¢Ú2CO (g)£«O2(g) == 2CO2(g) ¦¤H2£½£566.0 kJ/mol
¢ÛH2O (g) = H2O (l)¡¡¦¤H3£½£44.0 kJ/mol
д³ö¼×´¼²»ÍêȫȼÉÕÉú³ÉÒ»Ñõ»¯Ì¼ºÍҺ̬ˮµÄÈÈ»¯Ñ§·½³Ìʽ£º_____________________¡£
£¨1£©¢ÙDE£»¢Ú a2 / V2£»¢ÛC
£¨2£©2H£«+O2+2e££½H2O2
£¨3£©12
£¨4£©CH3OH(l)£«O2(g) == CO(g)£«2H2O(l) ¦¤H£½£442.8 kJ/mol
£¨2£©2H£«+O2+2e££½H2O2
£¨3£©12
£¨4£©CH3OH(l)£«O2(g) == CO(g)£«2H2O(l) ¦¤H£½£442.8 kJ/mol
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¶ÔÈËÌ彡¿µ²»»áÔì³ÉΣº¦µÄÊÇ£¨¡¡¡¡£©
| A¡¢Óù¤ÒµÑΣ¨NaNO2£©×÷ÏÌζµ÷ζƷ | B¡¢Ê³ÑÎÖмÓÈëÒ»¶¨Á¿µÄµâËá¼Ø£¨KIO3£©ÖÆÊ³Óú¬µâÑÎ | C¡¢Óø£¶ûÂíÁÖ£¨35%¡«40%¼×ȩˮÈÜÒº£©½þÅݺ£²úÆ·£¬·À¸¯±£ÏÊ | D¡¢½«º¬Óм״¼£¨CH3OH£©µÄ¹¤Òµ¾Æ¾«¶ÒÖÆ³ÉÒûÓÃ°×¾Æ |