ÌâÄ¿ÄÚÈÝ

A¡«DÊÇÔ­×ÓÐòÊýÔÚ20ÒÔÄÚµÄÔªËØ£¬ÆäÐÔÖÊ»ò½á¹¹ÐÅÏ¢Èçϱí
ÔªËØABCD
ÐÔÖÊ»ò
½á¹¹ÐÅÏ¢
Æäµ¥Öʺͻ¯ºÏÎïµÄÑæÉ«¾ùΪ»ÆÉ«ÆäÇ⻯ÎïµÄË®ÈÜÒºÄܸ¯Ê´²£Á§Æäµ¥ÖÊÔÚ¿ÕÆøÖÐÌå»ýº¬Á¿×î¶àµØ¿ÇÖк¬Á¿×î¶àµÄ½ðÊôÔªËØ
Çë¸ù¾Ý±íÖеÄÐÅÏ¢»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©AÀë×ӵĽṹʾÒâͼ______£¬BÔ­×ӵĵç×Óʽ______£¬CµÄµ¥Öʵĵç×ÓʽΪ______£®
£¨2£©ºÍBµÄÇ⻯ÎïËùº¬µç×ÓÊýÏàͬµÄ4ÖÖ΢Á£ÓÐ______£¬______£¬______£¬______£®
£¨3£©CµÄÆøÌ¬Ç⻯ÎïµÄË®»¯ÎïµÄµçÀë·½³Ìʽ£º______£®
£¨4£©¶ÔÓ¦Àë×Ó°ë¾¶´óС±È½Ï£ºA______D£®
A¡«DÊÇÔ­×ÓÐòÊýÔÚ20ÒÔÄÚµÄÔªËØ£ºAµÄµ¥Öʺͻ¯ºÏÎïµÄÑæÉ«¾ùΪ»ÆÉ«£¬ÔòAΪNa£»BµÄÇ⻯ÎïµÄË®ÈÜÒºÄܸ¯Ê´²£Á§£¬ÔòBΪF£»CµÄµ¥ÖÊÔÚ¿ÕÆøÖÐÌå»ýº¬Á¿×î¶à£¬ÔòCΪN£»DÔªËØÊǵؿÇÖк¬Á¿×î¶àµÄ½ðÊôÔªËØ£¬ÔòDΪAl£¬
£¨1£©Na+µÄ½á¹¹Ê¾ÒâͼΪ£¬FÔ­×Óµç×ÓʽΪ£¬N2µÄµç×ÓʽΪ£¬
¹Ê´ð°¸Îª£º£»£»£»
£¨2£©HFÖÐËùº¬µç×ÓÊýΪ10£¬³£¼ûµÄ10µç×ÓÁ£×ÓÓУºNe¡¢H2O¡¢NH3¡¢CH4¡¢OH-¡¢F-¡¢O2-¡¢N3-¡¢Na+¡¢Mg2+¡¢Al3+¡¢H3O+¡¢NH4+
¹Ê´ð°¸Îª£ºNe¡¢H2O¡¢NH3¡¢CH4¡¢OH-¡¢F-¡¢O2-¡¢N3-¡¢Na+¡¢Mg2+¡¢Al3+¡¢H3O+¡¢NH4+£¨ÆäÖеÄÈÎÒâ4Ïî¾ù¿É£©
£¨3£©NH3ÓëË®»¯ºÏΪNH3?H2O£¬ÔÚÈÜÒºÖз¢ÉúµçÀëNH3?H2O?NH4++OH-£¬
¹Ê´ð°¸ÓУºNH3?H2O?NH4++OH-£»
£¨4£©Na+¡¢Al3+µç×Ó²ã½á¹¹Ïàͬ£¬ºËµçºÉÊýÔ½´óÀë×Ӱ뾶ԽС£¬¹ÊÀë×Ó°ë¾¶Na+£¾Al3+£¬
¹Ê´ð°¸Îª£º£¾£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø