ÌâÄ¿ÄÚÈÝ
°±ÔÚ¹úÃñ¾¼ÃÖÐÕ¼ÓÐÖØÒªµØÎ»¡£
£¨1£©¹¤ÒµºÏ³É°±Ê±£¬ºÏ³ÉËþÖÐÿ²úÉú1 mol NH3£¬·Å³ö46.1 kJµÄÈÈÁ¿¡£
¢Ù ¹¤ÒµºÏ³É°±µÄÈÈ»¯Ñ§·½³ÌʽÊÇ ¡£
¢Ú ÒÑÖª£º
N2 (g)
H2 (g)
Ôò¶Ï¿ª1 mol N£H¼üËùÐèµÄÄÜÁ¿ÊÇ_______kJ¡£
£¨2£©Ï±íÊǵ±·´Ó¦Æ÷Öа´n(N2):n(H2)=1:3ͶÁϺó£¬ÔÚ200¡æ¡¢400¡æ¡¢600¡æÏ£¬·´Ó¦´ïµ½Æ½ºâʱ£¬»ìºÏÎïÖÐNH3µÄÎïÖʵÄÁ¿·ÖÊýËæÑ¹Ç¿µÄ±ä»¯ÇúÏß¡£
¢Ù ÇúÏßa¶ÔÓ¦µÄζÈÊÇ ¡£
¢Ú ¹ØÓÚ¹¤ÒµºÏ³É°±µÄ·´Ó¦£¬ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ £¨Ìî×Öĸ£©¡£
A. ¼°Ê±·ÖÀë³öNH3¿ÉÒÔÌá¸ßH2µÄƽºâת»¯ÂÊ
B. ¼Ó´ß»¯¼ÁÄܼӿ췴ӦËÙÂÊÇÒÌá¸ßH2µÄƽºâת»¯ÂÊ
C. ÉÏͼÖÐM¡¢N¡¢Qµãƽºâ³£ÊýKµÄ´óС¹ØÏµÊÇK(M)=" K(Q)" >K(N)
¢Û Mµã¶ÔÓ¦µÄH2ת»¯ÂÊÊÇ ¡£
4NH3(g) + 3O2(g) = 2N2(g) + 6H2O(g)¡£
Ôò¸ÃȼÁÏµç³ØµÄ¸º¼«·´Ó¦Ê½ÊÇ ¡£
£¨1£©¢ÙN2(g)+ 3H2(g)
2NH3(g)£¬¦¤H =" ¡ª92.2" kJ¡¤mol-1¢Ú 391£¨2£©¢Ù 200¡æ£»¢Ú AC£»¢Û 75%£¨3£©2NH3£6e¡ª + 6OH¡ª= N2 + 6H2O
ÊÔÌâ·ÖÎö£º£¨1£©¢ÙºÏ³ÉËþÖÐÿÉú³É1mol NH3£¬·Å³ö46.1kJÈÈÁ¿£¬ÒÀ¾ÝÈÈ»¯Ñ§·½³Ìʽд³ö£¬±ê×¢ÎïÖʾۼ¯×´Ì¬ºÍ¶ÔÓ¦·´Ó¦·Å³öµÄÈÈÁ¿£¬ÈÈ»¯Ñ§·½³Ìʽ£ºN2£¨g£©+3H2£¨g£©
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿