ÌâÄ¿ÄÚÈÝ
º£´øÖк¬ÓзḻµÄµâ£®ÎªÁË´Óº£´øÖÐÌáÈ¡µâ£¬Ä³Ñо¿ÐÔѧϰС×éÉè¼Æ²¢½øÐÐÁËÒÔÏÂʵÑ飺


ÇëÌîдÏÂÁпհףº
£¨1£©´ÓÉÏÊö²½ÖèÖпÉÖª£¬º£´øÖк¬ÓеĵâÔªËØµÄÖ÷Òª´æÔÚÐÎʽÊÇ______£®
£¨2£©²½Öè¢ÙׯÉÕº£´øÊ±£¬³ýÐèÒªÈý½Å¼Ü¡¢ÄàÈý½ÇÍ⣬»¹ÐèÒªÓõ½µÄʵÑéÒÇÆ÷ÊÇ______
£¨´ÓÏÂÁÐÒÇÆ÷ÖÐÑ¡³öËùÐèµÄÒÇÆ÷£¬ÓñêºÅ×ÖĸÌîдÔÚ¿Õ°×´¦£©£®
A£®ÉÕ± B£®±íÃæÃó C£®ÛáÛö D£®¾Æ¾«µÆ E£®¸ÉÔïÆ÷
£¨3£©²½Öè¢ÞÊÇ´Óº¬µâ±½ÈÜÒºÖзÖÀë³öµ¥ÖʵâºÍ»ØÊÕ±½£¬»¹Ðè¾¹ýÕôÁó£¬Ö¸³öÏÂÁÐʵÑé
×°ÖÃÖеĴíÎóÖ®´¦£®
¢Ù______
¢Ú______
¢Û______
½øÐÐÉÏÊöÕôÁó²Ù×÷ʱ£¬Ê¹ÓÃˮԡµÄÔÒòÊÇ______£»
£¨4£©²½Öè¢Ü·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ______£®²½Öè¢ÜÖеÄת»¯»¹¿ÉÒÔCl2»òË«ÑõË®£¨H2O2£©£¬Çë·Ö±ðд³ö·´Ó¦µÄÀë×Ó·½³Ìʽ£º
______¡¢______£®
£¨5£©¼ìÑ麣´øÖÐÊÇ·ñº¬ÓеâÔªËØ£¬¿ÉÒÔÔÚ²½Öè¢Üºó½øÐУ¬¼ìÑéʱ¿ÉÓõÄÊÔ¼ÁÊÇ______£®
£¨6£©ÏÂÁÐÎïÖÊ£¬²»ÄÜ×÷Ϊ´ÓµâË®ÖÐÝÍÈ¡µâµÄÈܼÁµÄÊÇ______£®
A£®ÈÈÁÑÆûÓÍ B£®CCl4 C£®¾Æ¾« D£®¼×±½
£¨7£©²½Öè¢ÛµÃµ½µÄÈÜÒºÓÐʱºòÈÔÊÇ»ë×ǵ쬯äͨ³£ÔÒòÊÇ______£®
ÇëÌîдÏÂÁпհףº
£¨1£©´ÓÉÏÊö²½ÖèÖпÉÖª£¬º£´øÖк¬ÓеĵâÔªËØµÄÖ÷Òª´æÔÚÐÎʽÊÇ______£®
£¨2£©²½Öè¢ÙׯÉÕº£´øÊ±£¬³ýÐèÒªÈý½Å¼Ü¡¢ÄàÈý½ÇÍ⣬»¹ÐèÒªÓõ½µÄʵÑéÒÇÆ÷ÊÇ______
£¨´ÓÏÂÁÐÒÇÆ÷ÖÐÑ¡³öËùÐèµÄÒÇÆ÷£¬ÓñêºÅ×ÖĸÌîдÔÚ¿Õ°×´¦£©£®
A£®ÉÕ± B£®±íÃæÃó C£®ÛáÛö D£®¾Æ¾«µÆ E£®¸ÉÔïÆ÷
£¨3£©²½Öè¢ÞÊÇ´Óº¬µâ±½ÈÜÒºÖзÖÀë³öµ¥ÖʵâºÍ»ØÊÕ±½£¬»¹Ðè¾¹ýÕôÁó£¬Ö¸³öÏÂÁÐʵÑé
×°ÖÃÖеĴíÎóÖ®´¦£®
¢Ù______
¢Ú______
¢Û______
½øÐÐÉÏÊöÕôÁó²Ù×÷ʱ£¬Ê¹ÓÃˮԡµÄÔÒòÊÇ______£»
£¨4£©²½Öè¢Ü·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ______£®²½Öè¢ÜÖеÄת»¯»¹¿ÉÒÔCl2»òË«ÑõË®£¨H2O2£©£¬Çë·Ö±ðд³ö·´Ó¦µÄÀë×Ó·½³Ìʽ£º
______¡¢______£®
£¨5£©¼ìÑ麣´øÖÐÊÇ·ñº¬ÓеâÔªËØ£¬¿ÉÒÔÔÚ²½Öè¢Üºó½øÐУ¬¼ìÑéʱ¿ÉÓõÄÊÔ¼ÁÊÇ______£®
£¨6£©ÏÂÁÐÎïÖÊ£¬²»ÄÜ×÷Ϊ´ÓµâË®ÖÐÝÍÈ¡µâµÄÈܼÁµÄÊÇ______£®
A£®ÈÈÁÑÆûÓÍ B£®CCl4 C£®¾Æ¾« D£®¼×±½
£¨7£©²½Öè¢ÛµÃµ½µÄÈÜÒºÓÐʱºòÈÔÊÇ»ë×ǵ쬯äͨ³£ÔÒòÊÇ______£®
£¨1£©²½Öè¢ÛµÃµ½º¬µâÀë×ÓµÄÈÜÒº£¬¹Ê´ð°¸Îª£ºµâÀë×Ó£»
£¨2£©×ÆÉÕ¹ÌÌåÎïÖÊÒ»°ãʹÓ㨴ɣ©ÛáÛö£¬¶øÛáÛö¼ÓÈÈÐèÒªÓÃÄàÈý½ÅÖ§³ÅÈ»ºó·ÅÔÚÈý½Å¼ÜÉÏ£¬Èý½Å¼ÜÏÂÃæµÄ¿Õ¼ä·Å¾Æ¾«µÆ£¬¹Ê´ð°¸Îª£ºCD£»
£¨3£©¸ù¾ÝÕôÁóµÄ×¢ÒâÊÂÏî¿ÉÖª£¬Í¼ÖгöÏÖÒÔÏ´íÎ󣺢ÙζȼÆË®ÒøÇòµÄλÖôíÎó£¬Ó¦ÓëÕôÁóƿ֧¹ÜÏÂÑØÆ½Æë£»¢ÚÉÕ±ÏÂûµæÊ¯ÃÞÍø£¬·ñÔò¼ÓÈÈʱ»áÊÜÈȲ»¾ù¶øÕ¨ÁÑ£»¢ÛÀäÀäÄý¹ÜÖÐÄýË®µÄÁ÷Ïò´íÎó£¬ÀäˮӦ´ÓÏ·½½ø£¬ÉÏ·½³ö£»ÓÖÓþƾ«µÆÖ±½Ó¼ÓÈÈζȱ仯¿ì£¬¶øË®Ô¡¼ÓÈÈÊÔ¹ÜÄÚÊÔ¼ÁÊÜÈȱȽϾùÔÈ£¬¹Ê´ð°¸Îª£º¢ÙζȼÆË®ÒøÇòµÄλÖôíÎó£¬Ó¦ÓëÕôÁóƿ֧¹ÜÏÂÑØÆ½Æë£»¢ÚÉÕ±ÏÂûµæÊ¯ÃÞÍø£¬·ñÔò¼ÓÈÈʱ»áÊÜÈȲ»¾ù¶øÕ¨ÁÑ£»¢ÛÀäÀäÄý¹ÜÖÐÄýË®µÄÁ÷Ïò´íÎó£¬ÀäˮӦ´ÓÏ·½½ø£¬ÉÏ·½³ö£»ÊÔ¼ÁÊÜÈȾùÔÈ£»
£¨4£©µâÀë×ÓÔÚËáÐÔÌõ¼þÏ¿ɱ»MnO2Ñõ»¯£»Cl2»òË«ÑõË®£¨H2O2£©¿ÉÑõ»¯µâÀë×Ó£¬¹Ê´ð°¸Îª£º2I-+MnO2+4H+=Mn2++I2+2H2O£»Cl2+2I-=2Cl-+I2£»H2O2+2I-+2H+=I2+2H2O£»
£¨5£©µâÓöµí·Û±äÀ¶É«£¬¹Ê´ð°¸Îª£ºµí·ÛÊÔÒº£»
£¨6£©ÈÈÁÑÆûÓÍÖк¬Óв»±¥ºÍµÄÏ©Ìþ£¬ÄÜÓëäå»òµâ·¢Éú·´Ó¦£¬ÈôÓÃÖ±ÁóÆûÓ;ͿÉÒÔÁË£»¾Æ¾«²»·Ö²ã£¬¹Ê´ð°¸Îª£ºAC£»
£¨7£©¹ýÂ˵Ĺý³ÌÖÐÈô°Ñ²£Á§°ô¿¿ÔÚÈý²ãÂËÖ½ÉÏʱ²»Ð¡ÐİÑÂËÖ½´ÁÆÆÁË£¬´Ëʱ¹ýÂ˳öµÄÂËÒº¿Ï¶¨ÊÇ»ì×ǵ컹ýÂËʱÂËÒºÒºÃæÒ»¶¨ÒªµÍÓÚÂËÖ½µÄ±ßÔµ£¬²»È»ÂËÒº¾Í»á²»¾¹ýÂËÖ½¶øÖ±½Ó´ÓÂËÖ½ºÍ©¶·Ö®¼äµÄ¿Õ϶ÖÐÁ÷¹ý£¬
¹Ê´ð°¸Îª£ºÂËÖ½ÆÆËð£»Çãµ¹ÒºÌåʱ£¬ÂËÒºÒºÃæ¸ßÓÚÂËÖ½±ßÔµ£®
£¨2£©×ÆÉÕ¹ÌÌåÎïÖÊÒ»°ãʹÓ㨴ɣ©ÛáÛö£¬¶øÛáÛö¼ÓÈÈÐèÒªÓÃÄàÈý½ÅÖ§³ÅÈ»ºó·ÅÔÚÈý½Å¼ÜÉÏ£¬Èý½Å¼ÜÏÂÃæµÄ¿Õ¼ä·Å¾Æ¾«µÆ£¬¹Ê´ð°¸Îª£ºCD£»
£¨3£©¸ù¾ÝÕôÁóµÄ×¢ÒâÊÂÏî¿ÉÖª£¬Í¼ÖгöÏÖÒÔÏ´íÎ󣺢ÙζȼÆË®ÒøÇòµÄλÖôíÎó£¬Ó¦ÓëÕôÁóƿ֧¹ÜÏÂÑØÆ½Æë£»¢ÚÉÕ±ÏÂûµæÊ¯ÃÞÍø£¬·ñÔò¼ÓÈÈʱ»áÊÜÈȲ»¾ù¶øÕ¨ÁÑ£»¢ÛÀäÀäÄý¹ÜÖÐÄýË®µÄÁ÷Ïò´íÎó£¬ÀäˮӦ´ÓÏ·½½ø£¬ÉÏ·½³ö£»ÓÖÓþƾ«µÆÖ±½Ó¼ÓÈÈζȱ仯¿ì£¬¶øË®Ô¡¼ÓÈÈÊÔ¹ÜÄÚÊÔ¼ÁÊÜÈȱȽϾùÔÈ£¬¹Ê´ð°¸Îª£º¢ÙζȼÆË®ÒøÇòµÄλÖôíÎó£¬Ó¦ÓëÕôÁóƿ֧¹ÜÏÂÑØÆ½Æë£»¢ÚÉÕ±ÏÂûµæÊ¯ÃÞÍø£¬·ñÔò¼ÓÈÈʱ»áÊÜÈȲ»¾ù¶øÕ¨ÁÑ£»¢ÛÀäÀäÄý¹ÜÖÐÄýË®µÄÁ÷Ïò´íÎó£¬ÀäˮӦ´ÓÏ·½½ø£¬ÉÏ·½³ö£»ÊÔ¼ÁÊÜÈȾùÔÈ£»
£¨4£©µâÀë×ÓÔÚËáÐÔÌõ¼þÏ¿ɱ»MnO2Ñõ»¯£»Cl2»òË«ÑõË®£¨H2O2£©¿ÉÑõ»¯µâÀë×Ó£¬¹Ê´ð°¸Îª£º2I-+MnO2+4H+=Mn2++I2+2H2O£»Cl2+2I-=2Cl-+I2£»H2O2+2I-+2H+=I2+2H2O£»
£¨5£©µâÓöµí·Û±äÀ¶É«£¬¹Ê´ð°¸Îª£ºµí·ÛÊÔÒº£»
£¨6£©ÈÈÁÑÆûÓÍÖк¬Óв»±¥ºÍµÄÏ©Ìþ£¬ÄÜÓëäå»òµâ·¢Éú·´Ó¦£¬ÈôÓÃÖ±ÁóÆûÓ;ͿÉÒÔÁË£»¾Æ¾«²»·Ö²ã£¬¹Ê´ð°¸Îª£ºAC£»
£¨7£©¹ýÂ˵Ĺý³ÌÖÐÈô°Ñ²£Á§°ô¿¿ÔÚÈý²ãÂËÖ½ÉÏʱ²»Ð¡ÐİÑÂËÖ½´ÁÆÆÁË£¬´Ëʱ¹ýÂ˳öµÄÂËÒº¿Ï¶¨ÊÇ»ì×ǵ컹ýÂËʱÂËÒºÒºÃæÒ»¶¨ÒªµÍÓÚÂËÖ½µÄ±ßÔµ£¬²»È»ÂËÒº¾Í»á²»¾¹ýÂËÖ½¶øÖ±½Ó´ÓÂËÖ½ºÍ©¶·Ö®¼äµÄ¿Õ϶ÖÐÁ÷¹ý£¬
¹Ê´ð°¸Îª£ºÂËÖ½ÆÆËð£»Çãµ¹ÒºÌåʱ£¬ÂËÒºÒºÃæ¸ßÓÚÂËÖ½±ßÔµ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿