ÌâÄ¿ÄÚÈÝ
³£ÎÂÏÂÔÚ20mL0.1mol/LNa2CO3ÈÜÒºÖÐÖðµÎ¼ÓÈë0.1mol/L HClÈÜÒº40mL£¬ÈÜÒºµÄpHÖð½¥½µµÍ£¬´ËʱÈÜÒºÖк¬Ì¼ÔªËصÄ΢Á£ÎïÖʵÄÁ¿Å¨¶ÈµÄ°Ù·Öº¬Á¿£¨×ÝÖᣩҲ·¢Éú±ä»¯£¨CO2ÒòÒݳöδ»³ö£©£¬ÈçͼËùʾ£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺£¨1£©ÓõÈʽ±íʾNa2CO3ÈÜÒºÖÐËùÓÐÑôÀë×ÓºÍÒõÀë×ÓŨ¶ÈµÄ¹ØÏµ£º £®
£¨2£©Ð´³öNa2CO3ÈÜÒºÖмÓÈëÉÙÁ¿ÑÎËáµÄÀë×Ó·½³Ìʽ £®
£¨3£©µ±»ìºÏÒºµÄpH= ʱ£¬¿ªÊ¼·Å³öCO2ÆøÌ壮
£¨4£©ÔÚ20mL 0.1mol/LNa2CO3ÈÜÒºÖмÓÈëBaCl2·ÛÄ©3.328×10-7 gʱ¿ªÊ¼²úÉú³ÁµíX£¬ÔòKSP£¨X£©= £®
¡¾´ð°¸¡¿·ÖÎö£º£¨1£©¸ù¾ÝÈÜÒºµçÖÐÐÔÊéдÀë×ÓŨ¶È¹ØÏµ£»
£¨2£©Na2CO3ÈÜÒºÖмÓÈëÉÙÁ¿ÑÎËáÉú³ÉHCO3-£»
£¨3£©µ±ÈÜÒºÖÐH2CO3´ïµ½±¥ºÍºó£¬¿ªÊ¼·Å³öCO2ÆøÌ壻
£¨4£©¸ù¾ÝKSP£¨BaCO3£©=c£¨Ba2+£©×c£¨CO32-£©¼ÆË㣮
½â´ð£º½â£º£¨1£©Na2CO3ÈÜÒºÖдæÔÚµÄÑôÀë×ÓÓÐNa+¡¢H+£¬ÒõÀë×ÓÓÐCO32-¡¢HCO3-¡¢OH-£¬¸ù¾ÝÈÜÒºµÄµçÖÐÐÔÔÔò£¬ÔòÓÐc£¨Na+£©+c£¨H+£©=2c£¨CO32-£©+c£¨HCO3-£©+c£¨OH-£©£¬
¹Ê´ð°¸Îª£ºc£¨Na+£©+c£¨H+£©=2c£¨CO32-£©+c£¨HCO3-£©+c£¨OH-£©£»
£¨2£©Na2CO3ÈÜÒºÖмÓÈëÉÙÁ¿ÑÎËáÉú³ÉHCO3-£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪCO32-+H+=HCO3-£¬¹Ê´ð°¸Îª£ºCO32-+H+=HCO3-£»
£¨3£©µ±ÈÜÒºÖÐH2CO3´ïµ½±¥ºÍºó£¬¿ªÊ¼·Å³öCO2ÆøÌ壬ÓÉͼÏó¿ÉÒÔ¿´³ö£¬µ±PH=6ʱ£¬H2CO3´ïµ½±¥ºÍ£¬¿ªÊ¼·Å³öCO2ÆøÌ壬¹Ê´ð°¸Îª£º6£»
£¨4£©ÔÚ20mL 0.1mol/LNa2CO3ÈÜÒºÖмÓÈëBaCl2·ÛÄ©3.328×10-7 gʱ¿ªÊ¼²úÉú³ÁµíBaCO3£¬´Ëʱ£ºc£¨CO32-£©=0.1mol/L£¬
c£¨Ba2+£©=
=8.0×10-8£¬
Ôò£ºKSP£¨BaCO3£©=c£¨Ba2+£©×c£¨CO32-£©=0.1×8.0×10-8=8.0×10-9
¹Ê´ð°¸Îª£º8.0×10-9£®
µãÆÀ£º±¾Ì⿼²éÈÜÒºÀë×ÓŨ¶È´óС±È½ÏÒÔ¼°ÄÑÈܵç½âÖʵÄÈÜ½âÆ½ºâ¼°³Áµíת»¯µÈÎÊÌ⣬ÌâÄ¿ÄѶÈÖеȣ¬×¢Òâ·ÖÎöͼÏóÇúÏ߱仯Ç÷ÊÆ£¬°ÑÎÕÎïÖʵÄÐÔÖÊ£®
£¨2£©Na2CO3ÈÜÒºÖмÓÈëÉÙÁ¿ÑÎËáÉú³ÉHCO3-£»
£¨3£©µ±ÈÜÒºÖÐH2CO3´ïµ½±¥ºÍºó£¬¿ªÊ¼·Å³öCO2ÆøÌ壻
£¨4£©¸ù¾ÝKSP£¨BaCO3£©=c£¨Ba2+£©×c£¨CO32-£©¼ÆË㣮
½â´ð£º½â£º£¨1£©Na2CO3ÈÜÒºÖдæÔÚµÄÑôÀë×ÓÓÐNa+¡¢H+£¬ÒõÀë×ÓÓÐCO32-¡¢HCO3-¡¢OH-£¬¸ù¾ÝÈÜÒºµÄµçÖÐÐÔÔÔò£¬ÔòÓÐc£¨Na+£©+c£¨H+£©=2c£¨CO32-£©+c£¨HCO3-£©+c£¨OH-£©£¬
¹Ê´ð°¸Îª£ºc£¨Na+£©+c£¨H+£©=2c£¨CO32-£©+c£¨HCO3-£©+c£¨OH-£©£»
£¨2£©Na2CO3ÈÜÒºÖмÓÈëÉÙÁ¿ÑÎËáÉú³ÉHCO3-£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪCO32-+H+=HCO3-£¬¹Ê´ð°¸Îª£ºCO32-+H+=HCO3-£»
£¨3£©µ±ÈÜÒºÖÐH2CO3´ïµ½±¥ºÍºó£¬¿ªÊ¼·Å³öCO2ÆøÌ壬ÓÉͼÏó¿ÉÒÔ¿´³ö£¬µ±PH=6ʱ£¬H2CO3´ïµ½±¥ºÍ£¬¿ªÊ¼·Å³öCO2ÆøÌ壬¹Ê´ð°¸Îª£º6£»
£¨4£©ÔÚ20mL 0.1mol/LNa2CO3ÈÜÒºÖмÓÈëBaCl2·ÛÄ©3.328×10-7 gʱ¿ªÊ¼²úÉú³ÁµíBaCO3£¬´Ëʱ£ºc£¨CO32-£©=0.1mol/L£¬
c£¨Ba2+£©=
Ôò£ºKSP£¨BaCO3£©=c£¨Ba2+£©×c£¨CO32-£©=0.1×8.0×10-8=8.0×10-9
¹Ê´ð°¸Îª£º8.0×10-9£®
µãÆÀ£º±¾Ì⿼²éÈÜÒºÀë×ÓŨ¶È´óС±È½ÏÒÔ¼°ÄÑÈܵç½âÖʵÄÈÜ½âÆ½ºâ¼°³Áµíת»¯µÈÎÊÌ⣬ÌâÄ¿ÄѶÈÖеȣ¬×¢Òâ·ÖÎöͼÏóÇúÏ߱仯Ç÷ÊÆ£¬°ÑÎÕÎïÖʵÄÐÔÖÊ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿