ÌâÄ¿ÄÚÈÝ

X¡¢Y¡¢Z¡¢WΪ¶ÌÖÜÆÚÔªËØÐγɵÄÁ£×Ó£¬ËüÃǵĵç×ÓÊýÏàµÈ¡£ÒÑÖªXΪ¸º¶þ¼Û˫ԭ×ÓÒõÀë×Ó£»YΪ˫ԭ×Ó·Ö×Ó£»ZÔÚ³£ÎÂÏÂΪҺÌ壬ÆäË®ÈÜÒº³ÊÈõËáÐÔ£»WÊÇÓɼ«ÐÔ¼üºÍ·Ç¼«ÐÔ¼ü¹¹³ÉµÄÁùÔ­×Ó·Ö×Ó¡£

(1)XÓëNa+×é³ÉµÄÀë×Ó»¯ºÏÎï³£ÎÂϸúË®·´Ó¦²úÉúÒ»ÖÖ¿ÉÖúȼµÄÆøÌ壬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____________________________¡£

(2)ÈôYΪÓöË®¾Í¾çÁÒ·´Ó¦µÄµ¥ÖÊ£¬ÔòYµÄµç×ÓʽΪ______________£»ÈôYΪ»¯ºÏÎÓÃʯī×÷µç¼«µç½âYµÄË®ÈÜÒº£¬Æäµç½â×Ü·´Ó¦Ê½Îª_____________________________¡£

(3)ÔÚµí·ÛKIÈÜÒºÖеμÓZµÄË®ÈÜÒº£¬ÈÜÒº±äÀ¶£¬ÆäÔ­Òò¿ÉÓÃÀë×Ó·½³Ìʽ±íʾΪ_____________________________¡£

(4)ÔÚ×î³õÔØÈË·É´¬µÄ»ð¼ýÍÆ½øÆ÷ÖУ¬Ò»°ã²ÉÓÃZºÍWÁ½ÖÖҺ̬»¯ºÏÎµ±ËüÃÇ»ìºÏ·´Ó¦Ê±Éú³ÉµªÆøºÍÒ»ÖÖ³£¼ûҺ̬Ñõ»¯Îï¡£ÒÑÖª16 g W·´Ó¦Ê±·ÅÈÈ409.6 kJ£¬ÔòZºÍW·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ_____________________________¡£

(1)2Na2O2+2H2O4NaOH+O2¡ü

(2)  2HClH2¡ü+Cl2¡ü

(3)H2O2+2I-+2H+I2+2H2O(д³ÉH2O2+2I-I2+2OH-Ò²¿É)

(4)N2H4(l)+2H2O2(l)N2(g)+4H2O(l)£»¦¤H=-819.2 kJ/mol

½âÎö£ºÓÉÌâÒ⣬X¡¢Y¡¢Z¡¢W·Ö±ðΪ¡¢F2(»òHCl)¡¢H2O2¡¢N2H4¡£

(3)KIÈÜÒºÖеμÓH2O2µÄÀë×Ó·½³ÌʽΪ2I-+H2O2I2+2OH-(»òH2O2+2I-+2H+I2+2H2O)

(4)H2O2ºÍN2H4·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪN2H4(l)+2H2O2(l)N2(g)+4H2O(l)£»¦¤H=-819.2 kJ¡¤mol-1¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø