ÌâÄ¿ÄÚÈÝ
ijµØÓÐÒ»³ØÌÁ£¬Éú³¤×ŷḻµÄË®ÉúÖ²ÎïºÍ¶àÖÖÓ㡢Ϻ¡£ºóÀ´£¬ÓÉÓÚ»¯¹¤³§½«´óÁ¿ÎÛË®ÅÅÈë³ØÌÁÖУ¬Ê¹Ë®Öʶñ»¯£¬¸÷ÖÖË®ÉúÉúÎïÏȺóËÀÍö¡£¸ù¾ÝÌâÒâÍê³ÉÏÂÁÐÎÊÌ⣺£¨1£©´ÓÉú̬ƽºâ½Ç¶È¿´£¬³ØÌÁÕâÖֱ仯˵Ã÷ÁË________________________________________¡£
£¨2£©Ôì³ÉÕâÖֱ仯µÄÔÒòÊÇ______________________________________________________¡£
£¨3£©¾¼ìÑ飬ÎÛË®Öк¬ÓÐ0.012 mol¡¤L-1µÄÓÎÀëä壬¿ÉÓÃÑÇÁòËáÄÆ³ýÈ¥ÎÛË®ÖеÄä壬Çëд³öÆä»¯Ñ§·½³Ìʽ£º_____________________________________________________________¡£
£¨4£©´¦Àí
£¨5£©ÒªÊ¹³ØÌÁ»Ö¸´±¾À´ÃæÄ¿£¬Ê×ÏÈÒª½â¾öµÄÎÊÌâÊÇ________________________________£¬Ê×ÏÈÒª»Ö¸´µÄÉúÎïÊÇ______________________________¡£
½âÎö£º±¾ÌâÊǰѿα¾ÖªÊ¶ÓëÈÕ³£Éú»îÏàÁªÏµµÄÌâÄ¿¡£³ä·ÖÀí½âÌâÒâÐÅÏ¢£¬¾Í¿É½â´ð±¾Ìâ¡£Br2ÓëNa2SO3·¢ÉúÑõ»¯»¹Ô·´Ó¦¡£¾Ý»¯Ñ§·½³ÌʽºÍÒÑÖªBr2µÄÎïÖÊÁ¿¿ÉÇóNa2SO3µÄÎïÖʵÄÁ¿£¬´Ó¶ø¿ÉÇóÆäÌå»ý¡£
´ð°¸£º£¨1£©³ØÌÁµÄÉú̬ƽºâÔâÊÜÆÆ»µ
£¨2£©»¯¹¤³§¶Ô³ØÌÁµÄÎÛȾ³¬¹ýÁ˳ØÌÁÉú̬ϵͳµÄ×Ô¶¯µ÷½ÚÄÜÁ¦
£¨3£©Na2SO3+Br2+H2O
Na2SO4+2HBr
£¨4£©1.2
£¨5£©»¯¹¤³§µÄÎÛȾÎÊÌâ Ë®ÉúÖ²Îï