ÌâÄ¿ÄÚÈÝ
(11·Ö)ij̽¾¿Ð¡×éÔÚʵÑéÊÒÖÐÓÃÂÁÍÁ¿ó(Ö÷Òª³É·ÖΪAl2O3£¬»¹º¬ÓÐFe2O3¡¢SiO2)ÌáÈ¡Ñõ»¯ÂÁ¡£»Ø´ðÏÂÁÐÎÊÌ⣺![]()
(1)ÔÚʵÑéÖÐÐèÓÃ1 mol¡¤L£1µÄNaOHÈÜÒº480 mL£¬ÅäÖÆ¸ÃÈÜÒºÒÑÓÐÏÂÁÐÒÇÆ÷£ºÍÐÅÌÌìÆ½(íÀÂë)¡¢½ºÍ·µÎ¹Ü¡¢Ò©³×¡¢²£Á§°ô£¬»¹È±ÉÙµÄÒÇÆ÷ÊÇ_______________________¡£
ÔÚׯÉÕ²Ù×÷ÖÐÓõ½ÏÂÁÐÒÇÆ÷ÖеÄÒ»ÖÖ£¬ÆäÃû³ÆÊÇ________¡£![]()
(2)д³ö²½Öè¢ÙÖз¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ____________________________________
________________________________________________________________________¡£
(3)²Ù×÷¢ÛÖÐÏ´µÓÈçºÎ²Ù×÷_______________________________________________
________________________________________________________________________¡£
(4)¼×ͬѧÔÚʵÑéÊÒÖÐÓÃÏÂÁÐ×°ÖÃÖÆ±¸CO2ÆøÌ壬²¢Í¨ÈëÂËÒºBÖÐÖÆÈ¡Al(OH)3ʱ£¬½á¹ûûÓвúÉúÔ¤ÆÚÏÖÏó¡£![]()
ÒÒͬѧ·ÖÎöÈÏΪ£º¼×ͬѧͨÈëCO2²»×ãÊǵ¼ÖÂʵÑéʧ°ÜµÄÔÒòÖ®Ò»¡£ÄãÈÏΪÒҵķÖÎöÊÇ·ñºÏÀí£¿________¡£ÈôºÏÀí£¬ÇëÓÃÀë×Ó·½³Ìʽ½âÊÍÆäÔÒò________________________________________________________¡£
(ÈôÄãÈÏΪ²»ºÏÀí£¬¸Ã¿Õ²»×÷´ð)
±ûͬѧ·ÖÎöÈÏΪ£º¼×ͬѧͨÈëµÄCO2Öк¬ÓÐHClÆøÌ壬ҲÊǵ¼ÖÂʵÑéʧ°ÜµÄÔÒò£¬ÔÚʵÑéÖÐÔö¼ÓijװÖÿɽâ¾öÕâ¸öÎÊÌâ¡£Çë°ïÖú¸Ãͬѧ»³ö¸Ã×°ÖÃͼ£¬²¢×¢Ã÷ÊÔ¼ÁÃû³Æ¡£![]()
(1)500 mLÈÝÁ¿Æ¿¡¢ÉÕ±'ÛáÛö
(2)Fe2O3£«6H£«===2Fe3£«£«3H2O¡¢Al2O3£«6H£«===2Al3£«£«3H2O
(3)Ïò¹ýÂËÆ÷ÖмÓÈëÕôÁóË®£¬Ê¹Ë®¸ÕºÃû¹ý³ÁµíÎµÈË®Á÷¾¡ºó£¬Öظ´²Ù×÷2¡«3´Î
(4)ºÏÀí'2OH££«CO2===CO32££«H2O
ÔÚ×°ÖâñºÍ×°ÖâòÖ®¼ä¼ÓÒ»Ï´ÆøÆ¿£¬×°ÖÃÈçÏ¡£
½âÎö
£¨1£©(4·Ö)ij̽¾¿Ð¡×éÓÃHNO3Óë´óÀíʯ·´Ó¦¹ý³ÌÖÐÖÊÁ¿¼õСµÄ·½·¨£¬Ñо¿Ó°Ïì·´Ó¦ËÙÂʵÄÒòËØ¡£ËùÓÃHNO3Ũ¶ÈΪ1.00mol£¯L¡¢2.00mol£¯L£¬´óÀíʯÓÐϸ¿ÅÁ£Óë´Ö¿ÅÁ£Á½ÖÖ¹æ¸ñ£¬ÊµÑéζÈΪ298K¡¢308K£¬Ã¿´ÎʵÑéHNO3µÄÓÃÁ¿Îª25.0mL¡¢´óÀíʯÓÃÁ¿Îª10.00g¡£ÇëÍê³ÉÒÔÏÂʵÑéÉè¼Æ±í£¬²¢Íê³ÉʵÑéÄ¿µÄÒ»À¸ÖеÄÌî¿Õ£º
| ʵÑé ±àºÅ | T/K | ´óÀíʯ ¹æ¸ñ | HNO3Ũ¶È /(mol/L) | ʵ Ñé Ä¿ µÄ |
| ¢Ù | 298 | ´Ö¿ÅÁ£ | 2.00 | (I)ʵÑé¢ÙºÍ¢Ú̽¾¿HNO3Ũ¶È¶Ô¸Ã·´Ó¦ËÙÂʵÄÓ°Ï죻 (¢ò)ʵÑé¢ÙºÍ¢Û̽¾¿________________¶Ô¸Ã·´Ó¦ËÙÂʵÄÓ°Ï죻 (¢ó)ʵÑé¢ÙºÍ¢Ü̽¾¿________________¶Ô¸Ã·´Ó¦ËÙÂʵÄÓ°Ïì¡£ |
| ¢Ú | 298 | ´Ö¿ÅÁ£ | 1.00 | |
| ¢Û | 298 | ϸ¿ÅÁ£ | 2.00 | |
| ¢Ü | 308K | ´Ö¿ÅÁ£ | 2.00 |
£¨2£©£¨4·Ö£©½«11.2L£¨±ê×¼×´¿ö£©ÒÒÏ©ºÍÒÒÍéµÄ»ìºÏÆøÌåͨÈë×ãÁ¿µÄäåµÄËÄÂÈ»¯Ì¼ÈÜÒºÖУ¬³ä·Ö·´Ó¦ºó£¬äåµÄËÄÂÈ»¯Ì¼ÈÜÒºµÄÖÊÁ¿Ôö¼ÓÁË8.4g£¬ÇóÔÆøÌå»ìºÏÎïÖÐÒÒÏ©ÓëÒÒÍéµÄÎïÖʵÄÁ¿Ö®±ÈºÍÖÊÁ¿±È¡£
£¨1£©(4·Ö)ij̽¾¿Ð¡×éÓÃHNO3Óë´óÀíʯ·´Ó¦¹ý³ÌÖÐÖÊÁ¿¼õСµÄ·½·¨£¬Ñо¿Ó°Ïì·´Ó¦ËÙÂʵÄÒòËØ¡£ËùÓÃHNO3Ũ¶ÈΪ1.00mol£¯L¡¢2.00mol£¯L£¬´óÀíʯÓÐϸ¿ÅÁ£Óë´Ö¿ÅÁ£Á½ÖÖ¹æ¸ñ£¬ÊµÑéζÈΪ298K¡¢308K£¬Ã¿´ÎʵÑéHNO3µÄÓÃÁ¿Îª25.0mL¡¢´óÀíʯÓÃÁ¿Îª10.00g¡£ÇëÍê³ÉÒÔÏÂʵÑéÉè¼Æ±í£¬²¢Íê³ÉʵÑéÄ¿µÄÒ»À¸ÖеÄÌî¿Õ£º
|
ʵÑé ±àºÅ |
T/K |
´óÀíʯ ¹æ¸ñ |
HNO3Ũ¶È /(mol/L) |
ʵ Ñé Ä¿ µÄ |
|
¢Ù |
298 |
´Ö¿ÅÁ£ |
2.00 |
(I)ʵÑé¢ÙºÍ¢Ú̽¾¿HNO3Ũ¶È¶Ô¸Ã·´Ó¦ËÙÂʵÄÓ°Ï죻 (¢ò)ʵÑé¢ÙºÍ¢Û̽¾¿________________¶Ô¸Ã·´Ó¦ËÙÂʵÄÓ°Ï죻 (¢ó)ʵÑé¢ÙºÍ¢Ü̽¾¿________________¶Ô¸Ã·´Ó¦ËÙÂʵÄÓ°Ïì¡£ |
|
¢Ú |
298 |
´Ö¿ÅÁ£ |
1.00 |
|
|
¢Û |
298 |
ϸ¿ÅÁ£ |
2.00 |
|
|
¢Ü |
308K |
´Ö¿ÅÁ£ |
2.00 |
£¨2£©£¨4·Ö£©½«11.2L£¨±ê×¼×´¿ö£©ÒÒÏ©ºÍÒÒÍéµÄ»ìºÏÆøÌåͨÈë×ãÁ¿µÄäåµÄËÄÂÈ»¯Ì¼ÈÜÒºÖУ¬³ä·Ö·´Ó¦ºó£¬äåµÄËÄÂÈ»¯Ì¼ÈÜÒºµÄÖÊÁ¿Ôö¼ÓÁË8.4g£¬ÇóÔÆøÌå»ìºÏÎïÖÐÒÒÏ©ÓëÒÒÍéµÄÎïÖʵÄÁ¿Ö®±ÈºÍÖÊÁ¿±È¡£