ÌâÄ¿ÄÚÈÝ

£¨¹²13·Ö£©Ï±íÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö, Õë¶Ô±íÖеĢ١«¢áÖÖÔªËØ,ÌîдÏÂÁпհףº

   Ö÷×å

ÖÜÆÚ

¢ñA

¢òA

¢óA

¢ôA

¢õA

¢öA

¢÷A

0×å

2

 

 

 

¢Ù

¢Ú

¢Û

 

 

3

¢Ü

 

¢Ý

 

 

¢Þ

¢ß

¢à

4

¢á

 

 

 

 

 

 

 

(1) ÔÚÕâÐ©ÔªËØÖÐ,»¯Ñ§ÐÔÖÊ×î²»»îÆÃµÄÊÇ:         (Ìî¾ßÌåÔªËØ·ûºÅ,ÏÂͬ)¡£

(2) ÔÚ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÖУ¬ËáÐÔ×îÇ¿µÄ»¯ºÏÎïµÄ·Ö×ÓʽÊÇ_______£¬¼îÐÔ×îÇ¿µÄ»¯ºÏÎïµÄµç×ÓʽÊÇ£º_____________¡£

(3) ×î¸ß¼ÛÑõ»¯ÎïÊÇÁ½ÐÔÑõ»¯ÎïµÄÔªËØÊÇ_____ ____£»Ð´³öËüµÄÑõ»¯ÎïÓëÇâÑõ»¯ÄÆ·´Ó¦µÄÀë×Ó·½³Ìʽ_____ _________ _________ _________ _________ ____¡£

(4) Óõç×Óʽ±íÊ¾ÔªËØ¢ÜÓë¢ÞµÄ»¯ºÏÎïµÄÐγɹý³Ì£º                              £¬¸Ã»¯ºÏÎïÊôÓÚ          (Ìî ¡°¹²¼Û¡±»ò¡°Àë×Ó¡±)»¯ºÏÎï¡£

£¨5£©±íʾ¢ÙÓë¢ßµÄ»¯ºÏÎïµÄµç×Óʽ                        £¬¸Ã»¯ºÏÎïÊÇÓÉ       

£¨Ìî¡°¼«ÐÔ¡±¡°·Ç¼«ÐÔ¡±£©¼üÐγɵġ£

(6)д³öÔªËØ¢ßµÄµ¥ÖÊÓëË®·´Ó¦µÄÀë×Ó·½³Ìʽ                                    

 

¡¾´ð°¸¡¿

£¨·½³Ìʽ¡¢Ðγɹý³Ìÿ¿Õ2·Ö£¬ÆäÓàÿ¿Õ1·Ö£©

(1)Ar£»   (2)HClO4£»£»  £¨3£©Al£»  Al2O3+2OH-=2AlO2-+H2O

(4) £»   Àë×Ó

£¨5£©£»   ¼«ÐÔ¹²¼Û¼ü  £¨6£©Cl2 +H2O = H ++ Cl-  + HClO

¡¾½âÎö¡¿¿¼²éÔªËØÖÜÆÚ±íµÄ½á¹¹¼°ÔªËØÖÜÆÚÂɵÄÓ¦Ó᣸ù¾ÝÔªËØÔÚÖÜÆÚ±íÖеÄλÖÿÉÖª£¬¢Ù¡«¢áÖÖÔªËØ·Ö±ðÊÇC¡¢N¡¢O¡¢Na¡¢Al¡¢S¡¢Cl¡¢Ar¡¢K¡£

£¨1£©Ï¡ÓÐÆøÌåÔªËØµÄ×îÍâ²ãµç×ÓÊýÒѾ­´ïµ½Æ½ºâ״̬£¬ËùÒÔ»¯Ñ§ÐÔÖÊ×î±ä»¯»îÆÃ¡£

£¨2£©·Ç½ðÊôÐÔԽǿ£¬×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄËáÐÔԽǿ£¬Òò´ËÊÇHClO4£»Í¬Ñù½ðÊôÐÔԽǿ£¬×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄ¼îÐÔԽǿ£¬ËùÒÔÊÇKOH£¬µç×ÓʽÊÇ¡£

£¨3ÂÁµÄÑõ»¯ÎïÑõ»¯ÂÁÊÇÁ½ÐÔÑõ»¯Î¼ÈÄܺÍËḳ£¬Ò²ÄܺͼӦ¡£ÓëÇâÑõ»¯ÄÆ·´Ó¦µÄ·½³ÌʽÊÇAl2O3+2OH-=2AlO2-+H2O¡£

£¨4£©ÄƺÍÁòÐγɵϝºÏÎïÊÇÁò»¯ÄÆ£¬ÊôÓÚº¬ÓÐÀë×Ó¼üµÄÀë×Ó»¯ºÏÎÆäÐγɹý³Ì¿É±íʾΪ¡£

£¨5£©CºÍClÐγɵÄËÄÂÈ»¯Ì¼£¬ÊǺ¬Óм«ÐÔ¼üµÄ·Ç¼«ÐÔ·Ö×Ó£¬Æäµç×ÓʽÊÇ¡£

£¨6£©ÂÈÆøÈÜÓÚË®Éú³ÉÑÎËáºÍ´ÎÂÈËᣬ·½³ÌʽÊÇCl2 +H2O = H ++ Cl-  + HClO¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨¹²14·Ö£©Ï±íÊÇÔªËØÖÜÆÚ±íÖеÄÒ»²¿·Ö£¬¸ù¾ÝA¡ªIÔÚÖÜÆÚ±íÖеÄλÖã¬ÓÃÔªËØ·ûºÅ»ò»¯Ñ§Ê½»Ø´ðÏÂÁÐÎÊÌ⣺


¢ñA
 
 
 
 
 
 
0
1
 
¢òA
¢óA
¢ôA
¢õA
¢öA
¢÷A
 
2
 
 
 
D
E
 
G
I
3
A
B
C
 
F
 
H
 
£¨1£©±íÖÐÔªËØ£¬»¯Ñ§ÐÔÖÊ×î²»»îÆÃµÄÊÇ         £¬Ñõ»¯ÐÔ×îÇ¿µÄµ¥ÖÊÊÇ         £¬»¹Ô­ÐÔ×îÇ¿µÄµ¥ÖÊÊÇ         £»
£¨2£©×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯Îï¼îÐÔ×îÇ¿µÄÊÇ          £¬ËáÐÔ×îÇ¿µÄÊÇ         £¬³ÊÁ½ÐÔµÄÊÇ           £»
£¨3£©ÒªÖ¤Ã÷A¡¢B¡¢CµÄ½ðÊô»îÆÃÐÔ£¬¿ÉÒÔÓÃʲôʵÑéÀ´Ö¤Ã÷£¬ÊÔ¾ÙÒ»Àý
ʵÑé²Ù×÷                                                              £»
ʵÑéÏÖÏ󣺠                                                            £»
Óйػ¯Ñ§·½³Ìʽ£º                                                     
                                                                      
(4)GÓëHµÄÆøÌ¬Ç⻯ÎïÎȶ¨ÐÔ       >        £¬ËµÃ÷ÏàÓ¦µ¥ÖʵķǽðÊôÐÔ     >     ¡£

£¨¹²14·Ö£©Ï±íÊÇÔªËØÖÜÆÚ±íÖеÄÒ»²¿·Ö£¬¸ù¾ÝA¡ªIÔÚÖÜÆÚ±íÖеÄλÖã¬ÓÃÔªËØ·ûºÅ»ò»¯Ñ§Ê½»Ø´ðÏÂÁÐÎÊÌ⣺

¢ñA

 

 

 

 

 

 

0

1

 

¢òA

¢óA

¢ôA

¢õA

¢öA

¢÷A

 

2

 

 

 

D

E

 

G

I

3

A

B

C

 

F

 

H

 

£¨1£©±íÖÐÔªËØ£¬»¯Ñ§ÐÔÖÊ×î²»»îÆÃµÄÊÇ          £¬Ñõ»¯ÐÔ×îÇ¿µÄµ¥ÖÊÊÇ          £¬»¹Ô­ÐÔ×îÇ¿µÄµ¥ÖÊÊÇ          £»

£¨2£©×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯Îï¼îÐÔ×îÇ¿µÄÊÇ           £¬ËáÐÔ×îÇ¿µÄÊÇ          £¬³ÊÁ½ÐÔµÄÊÇ            £»

£¨3£©ÒªÖ¤Ã÷A¡¢B¡¢CµÄ½ðÊô»îÆÃÐÔ£¬¿ÉÒÔÓÃʲôʵÑéÀ´Ö¤Ã÷£¬ÊÔ¾ÙÒ»Àý

ʵÑé²Ù×÷                                                               £»

ʵÑéÏÖÏ󣺠                                                             £»

Óйػ¯Ñ§·½³Ìʽ£º                                                     

                                                                       

(4)GÓëHµÄÆøÌ¬Ç⻯ÎïÎȶ¨ÐÔ        >         £¬ËµÃ÷ÏàÓ¦µ¥ÖʵķǽðÊôÐÔ      >      ¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø