ÌâÄ¿ÄÚÈÝ
ÈçͼËùʾ£¬¿ÉÐγÉÇâÑõȼÁÏµç³Ø£¬Í¨³£ÇâÑõȼÁÏµç³ØÓÐËáʽ£¨µ±µç½âÖÊÈÜҺΪH2SO4ʱ£©ºÍ¼îʽ£¨µ±µç½âÖÊÈÜҺΪNaOHÏ¡ÈÜÒº»òKOHÏ¡ÈÜҺʱ£©Á½ÖÖ¡£ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©Ëáʽµç³ØµÄµç¼«·´Ó¦£º¸º¼«£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß___£¬Õý¼«£ß£ß£ß£ß£ß£ß£ß£ß___£»µç³Ø·´Ó¦Îª£ß£ß£ß£ß£ß£ß£ß£ß___£»µç½âÖÊÈÜÒºµÄpH½«£ß£ß£ß£ß£ß£ß£ß£ß£¨Ìî¡°±ä´ó¡±¡¢¡°±äС¡±»ò¡°²»±ä¡±£©¡£
£¨2£©¼îʽµç³ØµÄµç¼«·´Ó¦£º¸º¼«£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£¬Õý¼«£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß_£»µç³Ø·´Ó¦Îª£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß____£»µç½âÖÊÈÜÒºµÄpH½«£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£¨Ìî¡°±ä´ó¡±¡¢¡°±äС¡±»ò¡°²»±ä¡±£©¡£
![]()
£¨1£©2H2
£¨2£©2H2+4OH-
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿