ÌâÄ¿ÄÚÈÝ
[Óлú»¯Ñ§»ù´¡]ÄÌÓÍÖÐÓÐÒ»ÖÖ»¯ºÏÎïA £¨C4H8O2£©£¬A¿ÉÓÃ×÷ÏãÁÏ£®
£¨1£©Ð´³öÓëA·Ö×ÓʽÏàͬµÄËùÓÐõ¥µÄ½á¹¹¼òʽ£º £®
ÒÑÖª£º
£¨2£©Ð´³öA¡úE¡¢E¡úFµÄ·´Ó¦ÀàÐÍ£ºA¡úE ¡¢E¡úF £»
£¨3£©Ð´³öA¡¢C¡¢FµÄ½á¹¹¼òʽ£ºA ¡¢C ¡¢F £»
£¨4£©Ð´³öB¡úD·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º £»
£¨5£©ÔÚ¿ÕÆøÖг¤Ê±¼ä½Á°èÄÌÓÍ£¬A¿Éת»¯ÎªÏà¶Ô·Ö×ÓÖÊÁ¿Îª86µÄ»¯ºÏÎïG£¬GµÄÒ»ÂÈ´úÎïÖ»ÓÐÒ»ÖÖ£¬Ð´³öGµÄ½á¹¹¼òʽ£º £®
¡¾´ð°¸¡¿·ÖÎö£ºAµÄ·Ö×ÓʽΪC4H8O2£¬²»±¥ºÍ¶ÈΪ
=1£¬AÖк¬ÓÐ̼ÑõË«¼ü£¬½áºÏAÓëEµÄÏ໥ת»¯¿ÉÖª£¬AÖк¬Óд¼ôÇ»ù-OH£¬ÓÉBת»¯ÎªCµÄ·´Ó¦Ìõ¼þ¿ÉÖª£¬·´Ó¦ÐÅÏ¢Öеķ´Ó¦£¬BÖк¬ÓÐ2¸öÏàÁÚµÄ-OH£¬¹ÊAº¬ÓеĹÙÄÜÍÅΪ-OH¡¢
£¬Bת»¯ÎªC£¬Éú³ÉÎïÖ»ÓÐÒ»ÖÖ£¬B·Ö×ÓΪ¶Ô³Æ½á¹¹£¬¹ÊAµÄ½á¹¹¼òʽΪ
£¬¹ÊBΪ
£¬CΪCH3CHO£¬EΪ
£¬BÓë×ãÁ¿µÄ±½¼×Ëá·¢Éúõ¥»¯·´Ó¦Éú³ÉD£¬DΪ
£®EÔÚÇâÑõ»¯ÄÆ´¼ÈÜÒº¡¢¼ÓÈÈÌõ¼þÏ·¢ÉúÏûÈ¥·´Ó¦Éú³ÉF£¬FΪ
£®A¿Éת»¯ÎªÏà¶Ô·Ö×ÓÖÊÁ¿Îª86µÄ»¯ºÏÎïG£¬ÓÉA¡¢GµÄÏà¶Ô·Ö×ÓÖÊÁ¿¿ÉÖª£¬Ó¦ÊÇAÖÐ-OHÑõ»¯Îª
£¬¹ÊGΪ
£¬¾Ý´Ë½â´ð£®
½â´ð£º½â£ºAµÄ·Ö×ÓʽΪC4H8O2£¬²»±¥ºÍ¶ÈΪ
=1£¬AÖк¬ÓÐ̼ÑõË«¼ü£¬½áºÏAÓëEµÄÏ໥ת»¯¿ÉÖª£¬AÖк¬Óд¼ôÇ»ù-OH£¬ÓÉBת»¯ÎªCµÄ·´Ó¦Ìõ¼þ¿ÉÖª£¬·´Ó¦ÐÅÏ¢Öеķ´Ó¦£¬BÖк¬ÓÐ2¸öÏàÁÚµÄ-OH£¬¹ÊAº¬ÓеĹÙÄÜÍÅΪ-OH¡¢
£¬Bת»¯ÎªC£¬Éú³ÉÎïÖ»ÓÐÒ»ÖÖ£¬B·Ö×ÓΪ¶Ô³Æ½á¹¹£¬¹ÊAµÄ½á¹¹¼òʽΪ
£¬¹ÊBΪ
£¬CΪCH3CHO£¬EΪ
£¬BÓë×ãÁ¿µÄ±½¼×Ëá·¢Éúõ¥»¯·´Ó¦Éú³ÉD£¬DΪ
£®EÔÚÇâÑõ»¯ÄÆ´¼ÈÜÒº¡¢¼ÓÈÈÌõ¼þÏ·¢ÉúÏûÈ¥·´Ó¦Éú³ÉF£¬FΪ
£®A¿Éת»¯ÎªÏà¶Ô·Ö×ÓÖÊÁ¿Îª86µÄ»¯ºÏÎïG£¬ÓÉA¡¢GµÄÏà¶Ô·Ö×ÓÖÊÁ¿¿ÉÖª£¬Ó¦ÊÇAÖÐ-OHÑõ»¯Îª
£¬¹ÊGΪ
£¬
£¨1£©ÓëA·Ö×ÓʽÏàͬµÄËùÓÐõ¥µÄ½á¹¹¼òʽΪ£ºCH3CH2COOCH3¡¢CH3COOCH2CH3¡¢HCOOCH£¨CH3£©2¡¢HCOOCH2CH2CH3£¬
¹Ê´ð°¸Îª£ºCH3CH2COOCH3¡¢CH3COOCH2CH3¡¢HCOOCH£¨CH3£©2¡¢HCOOCH2CH2CH3£»
£¨2£©A¡úEÊÇ
·¢ÉúÈ¡´ú·´Ó¦Éú³É
£¬
E¡úFÊÇ
ÔÚÇâÑõ»¯ÄÆ´¼ÈÜÒº¡¢¼ÓÈÈÌõ¼þÏ·¢ÉúÏûÈ¥·´Ó¦Éú³É
£¬
¹Ê´ð°¸Îª£ºÈ¡´ú·´Ó¦£»ÏûÈ¥·´Ó¦£»
£¨3£©ÓÉÉÏÊö·ÖÎö¿ÉÖª£¬AΪ
£¬CΪCH3CHO£¬FΪ
£¬
¹Ê´ð°¸Îª£º
£»CH3CHO£»
£»
£¨4£©B¡úD·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
£¬
¹Ê´ð°¸Îª£º
£»
£¨5£©£®A¿Éת»¯ÎªÏà¶Ô·Ö×ÓÖÊÁ¿Îª86µÄ»¯ºÏÎïG£¬ÓÉA¡¢GµÄÏà¶Ô·Ö×ÓÖÊÁ¿¿ÉÖª£¬Ó¦ÊÇAÖÐ-OHÑõ»¯Îª
£¬¹ÊGΪ
£¬¹Ê´ð°¸Îª£º
£®
µãÆÀ£º±¾Ì⿼²éÓлúÎïµÄÍÆ¶ÏÓëºÏ³É£¬ÐèҪѧÉú¶Ô·´Ó¦ÐÅÏ¢½øÐÐÀûÓ㬼ÆËãÍÆ¶ÏAµÄ½á¹¹¼òʽÊǽâÌâ¹Ø¼ü£¬×¢Òâ¸ù¾Ýת»¯Ìõ¼þ£¬½áºÏ¹ÙÄÜÍŵÄÐÔÖÊÍÆ¶Ï£¬ÄѶÈÖеȣ®
½â´ð£º½â£ºAµÄ·Ö×ÓʽΪC4H8O2£¬²»±¥ºÍ¶ÈΪ
£¨1£©ÓëA·Ö×ÓʽÏàͬµÄËùÓÐõ¥µÄ½á¹¹¼òʽΪ£ºCH3CH2COOCH3¡¢CH3COOCH2CH3¡¢HCOOCH£¨CH3£©2¡¢HCOOCH2CH2CH3£¬
¹Ê´ð°¸Îª£ºCH3CH2COOCH3¡¢CH3COOCH2CH3¡¢HCOOCH£¨CH3£©2¡¢HCOOCH2CH2CH3£»
£¨2£©A¡úEÊÇ
E¡úFÊÇ
¹Ê´ð°¸Îª£ºÈ¡´ú·´Ó¦£»ÏûÈ¥·´Ó¦£»
£¨3£©ÓÉÉÏÊö·ÖÎö¿ÉÖª£¬AΪ
¹Ê´ð°¸Îª£º
£¨4£©B¡úD·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
¹Ê´ð°¸Îª£º
£¨5£©£®A¿Éת»¯ÎªÏà¶Ô·Ö×ÓÖÊÁ¿Îª86µÄ»¯ºÏÎïG£¬ÓÉA¡¢GµÄÏà¶Ô·Ö×ÓÖÊÁ¿¿ÉÖª£¬Ó¦ÊÇAÖÐ-OHÑõ»¯Îª
µãÆÀ£º±¾Ì⿼²éÓлúÎïµÄÍÆ¶ÏÓëºÏ³É£¬ÐèҪѧÉú¶Ô·´Ó¦ÐÅÏ¢½øÐÐÀûÓ㬼ÆËãÍÆ¶ÏAµÄ½á¹¹¼òʽÊǽâÌâ¹Ø¼ü£¬×¢Òâ¸ù¾Ýת»¯Ìõ¼þ£¬½áºÏ¹ÙÄÜÍŵÄÐÔÖÊÍÆ¶Ï£¬ÄѶÈÖеȣ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿