ÌâÄ¿ÄÚÈÝ
ϱíÊÇijʳƷ°ü×°´üÉϵÄ˵Ã÷£¬´Ó±íÖеÄÅäÁÏÖзֱðÑ¡³öÒ»ÖÖÎïÖÊÌîÔÚÏàÓ¦µÄºáÏßÉÏ£®
£¨1£©¸»º¬µ°°×ÖʵÄÊÇ £»
£¨2£©¸»º¬ÌÇÀàµÄÊÇ £»
£¨3£©¸»º¬ÓÍÖ¬µÄÊÇ £»
£¨4£©¸»º¬Î¬ÉúËØµÄÊÇ £»
£¨5£©ÊôÓÚ×ÅÉ«¼ÁµÄÓÐ £»
£¨6£©ÊôÓÚµ÷ζ¼ÁµÄÓÐ £»
£¨7£©ÊôÓÚ·À¸¯¼ÁµÄÓÐ £»
£¨8£©ÊôÓÚÊèËɼÁµÄÓÐ £®
| Æ·Ãû | ¡Á¡Á¡Á |
| ÅäÁÏ | Ïʼ¦µ°¡¢¾«Ãæ·Û¡¢°×ɰÌÇ¡¢¾«Á¶Ö²ÎïÓÍ¡¢ÄÌÓÍ¡¢ÄÌ·Û¡¢Ì¼ËáÇâÄÆ¡¢ÄûÃÊËá¡¢ÄûÃÊÖ¡¢Ê³ÑΡ¢ÌðÃÛËØ¡¢²¤ÂÜÏ㾫¡¢ÄûÃʻơ¢ÈÕÂ仯¡¢É½ÀæËá¼ØµÈ |
| ±£ÖÊÆÚ | 240Ìì |
| Éú²úÈÕÆÚ | ±êÓÚ°ü×°´ü·â¿ÚÉÏ |
£¨2£©¸»º¬ÌÇÀàµÄÊÇ
£¨3£©¸»º¬ÓÍÖ¬µÄÊÇ
£¨4£©¸»º¬Î¬ÉúËØµÄÊÇ
£¨5£©ÊôÓÚ×ÅÉ«¼ÁµÄÓÐ
£¨6£©ÊôÓÚµ÷ζ¼ÁµÄÓÐ
£¨7£©ÊôÓÚ·À¸¯¼ÁµÄÓÐ
£¨8£©ÊôÓÚÊèËɼÁµÄÓÐ
¿¼µã£º³£¼ûµÄʳƷÌí¼Ó¼ÁµÄ×é³É¡¢ÐÔÖʺÍ×÷ÓÃ,Éú»îÖеÄÓлú»¯ºÏÎï
רÌ⣺Óлú»¯ºÏÎïµÄ»ñµÃÓëÓ¦ÓÃ,»¯Ñ§Ó¦ÓÃ
·ÖÎö£ºÈËÌå»ù±¾ÓªÑøÎïÖʰüÀ¨ÌÇÀà¡¢ÓÍÖ¬¡¢µ°°×ÖÊ¡¢Î¬ÉúËØºÍ΢Á¿ÔªËØ£¬Ïʼ¦µ°¡¢ÄÌ·ÛÖи»º¬µ°°×ÖÊ£»°×ɰÌÇΪÕáÌÇ£¬¾«Ãæ·ÛÖи»º¬µí·Û£»¾«Á¶Ö²ÎïÓÍ¡¢ÄÌÓÍÖи»¶¯ÎïÖ¬·¾£»Ë®¹ûÖи»º¬Î¬ÉúËØ£»
ʳƷÌí¼Ó¼Á°üÀ¨£º×ÅÉ«¼Á¡¢µ÷ζ¼Á¡¢·À¸¯¼Á¡¢ÓªÑøÇ¿»¯¼Á¡¢ÊèËɼÁµÈ£®ÄûÃʻơ¢ÈÕÂ仯¾ùΪÔÊÐíʹÓõĻ¯Ñ§ºÏ³É×ÅÉ«¼Á£¬°×ɰÌÇ¡¢Ê³ÑΡ¢ÄûÃÊËá¡¢ÌðÃÛËØ¡¢²¤ÂÜÏ㾫ÊôÓÚ³£Óõ÷ζ¼Á£¬É½ÀæËá¼ØÊôÓÚ·À¸¯¼Á£¬Ì¼ËáÇâÄÆÊÜÈÈ·Ö½â²úÉú¶þÑõ»¯Ì¼£¬ÊôÓÚÊèËɼÁ£®
ʳƷÌí¼Ó¼Á°üÀ¨£º×ÅÉ«¼Á¡¢µ÷ζ¼Á¡¢·À¸¯¼Á¡¢ÓªÑøÇ¿»¯¼Á¡¢ÊèËɼÁµÈ£®ÄûÃʻơ¢ÈÕÂ仯¾ùΪÔÊÐíʹÓõĻ¯Ñ§ºÏ³É×ÅÉ«¼Á£¬°×ɰÌÇ¡¢Ê³ÑΡ¢ÄûÃÊËá¡¢ÌðÃÛËØ¡¢²¤ÂÜÏ㾫ÊôÓÚ³£Óõ÷ζ¼Á£¬É½ÀæËá¼ØÊôÓÚ·À¸¯¼Á£¬Ì¼ËáÇâÄÆÊÜÈÈ·Ö½â²úÉú¶þÑõ»¯Ì¼£¬ÊôÓÚÊèËɼÁ£®
½â´ð£º
½â£ºÈËÌå»ù±¾ÓªÑøÎïÖʰüÀ¨ÌÇÀà¡¢ÓÍÖ¬¡¢µ°°×ÖÊ¡¢Î¬ÉúËØºÍ΢Á¿ÔªËØ£¬½áºÏÌâÒ⣬
Ïʼ¦µ°¡¢ÄÌ·ÛÖи»º¬µ°°×ÖÊ£»°×ɰÌÇΪÕáÌÇ£¬¾«Ãæ·ÛÖи»º¬µí·Û£¬ÕáÌǺ͵í·Û¾ùÊôÓÚÌÇÀࣻ¾«Á¶Ö²ÎïÓÍ¡¢ÄÌÓÍÖи»º¬ÓÍÖ¬£»Ë®¹ûÖи»º¬Î¬ÉúËØ£¬ÄûÃÊÖÖи»º¬Î¬ÉúËØ£»
ʳƷÌí¼Ó¼Á°üÀ¨£º×ÅÉ«¼Á¡¢µ÷ζ¼Á¡¢·À¸¯¼Á¡¢ÓªÑøÇ¿»¯¼Á¡¢ÊèËɼÁµÈ£¬½áºÏÌâÒâ¿ÉÖª£¬ÄûÃʻơ¢ÈÕÂä»ÆÎª×ÅÉ«¼Á£¬°×ɰÌÇ¡¢Ê³ÑΡ¢ÄûÃÊËá¡¢ÌðÃÛËØ¡¢²¤ÂÜÏ㾫ÊôÓÚµ÷ζ¼Á£¬É½ÀæËá¼ØÊôÓÚ·À¸¯¼Á£¬Ì¼ËáÇâÄÆÊÜÈÈ·Ö½â²úÉú¶þÑõ»¯Ì¼£¬ÊôÓÚÊèËɼÁ£¬
¹Ê´ð°¸Îª£º£¨1£©Ïʼ¦µ°£¨»òÄÌ·Û£©£» £¨2£©°×ɰÌÇ£¨»ò¾«Ãæ·Û£©£» £¨3£©¾«Á¶Ö²ÎïÓÍ£¨»òÄÌÓÍ£©£»£¨4£©ÄûÃÊÖ£»£¨5£©ÄûÃʻƣ¨»òÈÕÂ仯£©£»£¨6£©°×ɰÌÇ£¨»òʳÑΡ¢ÄûÃÊËá¡¢ÌðÃÛËØ¡¢²¤ÂÜÏ㾫£©£»£¨7£©É½ÀæËá¼Ø£»£¨8£©Ì¼ËáÇâÄÆ£®
Ïʼ¦µ°¡¢ÄÌ·ÛÖи»º¬µ°°×ÖÊ£»°×ɰÌÇΪÕáÌÇ£¬¾«Ãæ·ÛÖи»º¬µí·Û£¬ÕáÌǺ͵í·Û¾ùÊôÓÚÌÇÀࣻ¾«Á¶Ö²ÎïÓÍ¡¢ÄÌÓÍÖи»º¬ÓÍÖ¬£»Ë®¹ûÖи»º¬Î¬ÉúËØ£¬ÄûÃÊÖÖи»º¬Î¬ÉúËØ£»
ʳƷÌí¼Ó¼Á°üÀ¨£º×ÅÉ«¼Á¡¢µ÷ζ¼Á¡¢·À¸¯¼Á¡¢ÓªÑøÇ¿»¯¼Á¡¢ÊèËɼÁµÈ£¬½áºÏÌâÒâ¿ÉÖª£¬ÄûÃʻơ¢ÈÕÂä»ÆÎª×ÅÉ«¼Á£¬°×ɰÌÇ¡¢Ê³ÑΡ¢ÄûÃÊËá¡¢ÌðÃÛËØ¡¢²¤ÂÜÏ㾫ÊôÓÚµ÷ζ¼Á£¬É½ÀæËá¼ØÊôÓÚ·À¸¯¼Á£¬Ì¼ËáÇâÄÆÊÜÈÈ·Ö½â²úÉú¶þÑõ»¯Ì¼£¬ÊôÓÚÊèËɼÁ£¬
¹Ê´ð°¸Îª£º£¨1£©Ïʼ¦µ°£¨»òÄÌ·Û£©£» £¨2£©°×ɰÌÇ£¨»ò¾«Ãæ·Û£©£» £¨3£©¾«Á¶Ö²ÎïÓÍ£¨»òÄÌÓÍ£©£»£¨4£©ÄûÃÊÖ£»£¨5£©ÄûÃʻƣ¨»òÈÕÂ仯£©£»£¨6£©°×ɰÌÇ£¨»òʳÑΡ¢ÄûÃÊËá¡¢ÌðÃÛËØ¡¢²¤ÂÜÏ㾫£©£»£¨7£©É½ÀæËá¼Ø£»£¨8£©Ì¼ËáÇâÄÆ£®
µãÆÀ£º±¾Ì⿼²éÈËÌåÓªÑøÎïÖʺͳ£¼ûʳƷÌí¼Ó¼Á£¬ÊìÖª¸÷ÖÖʳÎïµÄ³É·ÖºÍ³£¼ûʳƷÌí¼Ó¼ÁµÄ×÷ÓÃÊǽâÌâµÄ»ù´¡£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
³ôÑõ²ãµÄÆÆ»µµ¼ÖÂ×ÏÍâÏß¶ÔµØÇò±íÃæ·øÉäÁ¿Ôö¼Ó£¬´Ó¶øÊ¹È«ÇòƤ·ô°©µÄ·¢²¡ÈËÊýÃ÷ÏÔÔö¼Ó£®Ôì³ÉÕâÒ»ÏÖÏóµÄÖ÷ÒªÔÒòÊÇ£¨¡¡¡¡£©
| A¡¢ÈËÃÇ´óÁ¿Ê¹Ó÷úÂÈ´úÍé |
| B¡¢ÈËÃÇÔÚÁ¶¸ÖʱÏò¿ÕÆøÖÐÅÅ·ÅÁË´óÁ¿µÄ¸ßÂ¯ÃºÆø |
| C¡¢Ê¯ÓÍÁ¶ÖƳ§ÅÅ·ÅÁË´óÁ¿µÄ¼×Íé¡¢ÇâÆø |
| D¡¢ÁòËá¡¢ÏõËṤ³§ÅÅ·ÅÁË´óÁ¿µÄ¶þÑõ»¯ÁòºÍÒ»Ñõ»¯µª |
ÏÂÁи÷×éÖеÄÁ½ÖÖÎïÖÊÔÚÈÜÒºÖеķ´Ó¦£¬¿ÉÓÃͬһÀë×Ó·½³Ìʽ±íʾµÄÊÇ£¨¡¡¡¡£©
| A¡¢NaHSO4+NaOH£»H2SO4+NaOH |
| B¡¢NaHCO3+H2SO4£»Na2CO3+HCl |
| C¡¢Cu£¨OH£©2+HCl£»Cu£¨OH£©2+CH3COOH |
| D¡¢BaCl2+H2SO4£»Ba£¨OH£©2+H2SO4 |