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(5)CµãµÄpHΪ______________(pH¿ÉÖ±½ÓÓöÔÊý±íʾ)¡£
(1)0.1
(2)0.4
(3)0.466
(4)0.2 07
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½âÎö:
Ba2++
====BaSO4¡ý
H+ + OH-====H2O
1 1 1
n(
)=n¡²Ba(OH)2¡³=0.02 L¡Á0.1 mol¡¤L-1=2¡Á10-3 mol
c(H2SO4)=n(H2SO4)/V(aq)=2¡Á10-3 mol/002 L=0.1 mol¡¤L-1
n(H+)=2¡Á0.06 L¡Á0.1 mol¡¤L-1=0.012 mol
n(HCl)=n(H+)-2n(H2SO4)=0.012 mol-2¡Á0.002 mol=0.008 mol
c(HCl)=n(HCl)/V(aq)=0.008 mol/0.02 L=0.4 mol¡¤L-1
n(BaSO4)=n(
)=0.002 mol
m(BaSO4)=n(BaSO4)¡¤M(BaSO4)=0.002 mol¡Á233 g¡¤mol-1=0.466 g
(4)ÔÚAµãʱ£¬Ba(OH)2Ç¡ºÃÓëH2SO4ÍêÈ«·´Ó¦£¬ÕâʱÈÜÒºÖÐÊ£ÓàµÄH+È«²¿ÊÇHClµÄ£¬n(H+)=n(HCl)=0.008 mol£¬ËùÒÔ£¬c(H+)=n(H+)/V(×Ü)=0.008 mol/0.04 L=0.2 mol¡¤L-1,pH=-lg 0.2=0.7¡£
(5)CµãʱµÄ»ìºÏÒºÊÇÔÚAµãµÄ»ù´¡ÉÏÓÖµÎÈë20 mL Ba(OH)2ÈÜÒº£¬ÕâʱBa(OH)2Ö»ÓëHCl·´Ó¦£¬Ê£ÓàµÄH+ÊÇn(H+)=0.008 mol-2n¡²Ba(OH)2¡³=0.008 mol-2¡Á0.1 mol¡¤L-1¡Á0.02 L=0.004 mol,c(H+)=0.004 mol/0.06 L=1/15 mol¡¤L-1¡£pH=-lg
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