ÌâÄ¿ÄÚÈÝ
£¨24·Ö£©
X¡¢Y¡¢Z¡¢W¡¢QÊÇÔ×ÓÐòÊýÒÀ´ÎÔö´óµÄ¶ÌÖÜÆÚÖ÷×åÔªËØ£¬X¡¢WÔÚÖÜÆÚ±íÖеÄÏà¶ÔλÖÃÈçÏÂ±í£»XÔªËØ×îµÍ¸º»¯ºÏ¼ÛµÄ¾ø¶ÔÖµÓëÆäÔ×Ó×îÍâ²ãµç×ÓÊýÏàµÈ£»ZÊǵؿÇÖк¬Á¿×î¶àµÄ½ðÊôÔªËØ¡£
£¨1£©ÔªËØQÔÚÖÜÆÚ±íÖÐλÓÚµÚ_____×壬ZµÄÀë×ӽṹʾÒâͼΪ_____¡£
£¨2£©Z¡¢W¡¢QµÄÔ×Ó°ë¾¶ÓÉ´óµ½Ð¡µÄ˳ÐòΪ ¡££¨ÓÃÔªËØ·ûºÅ±íʾÆäÔ×Ó £©¡£
£¨3£©XºÍÇâ×é³ÉµÄ»¯ºÏÎï·Ö×ÓÖÐÓÐ6¸öÔ×Ó£¬Æä½á¹¹¼òʽΪ______£¬Ð´³ö¸ÃÎïÖÊÓëË®¼Ó³ÉµÄ»¯Ñ§·½³Ìʽ ¡£
£¨4£©YµÄ×î¼òµ¥ÆøÌ¬Ç⻯Îï¼×µÄË®ÈÜÒºÏÔ¼îÐÔ
¢ÙÓõçÀë·½³Ìʽ±íʾÇ⻯Îï¼×µÄË®ÈÜÒºÖеÄÏÔ¼îÐÔµÄÔÒò £¬
¢ÚÔÚ΢µç×Ó¹¤ÒµÖУ¬¼×µÄË®ÈÜÒº¿É×÷¿ÌÊ´¼ÁH2O2µÄÇå³ý¼Á£¬Ëù·¢Éú·´Ó¦µÄ²úÎï²»ÎÛȾ»·¾³£¬Æä»¯Ñ§·½³ÌʽΪ____ __¡£¸Ã·´Ó¦µÄÑõ»¯¼ÁÊÇ µ±ÓÐ1mol¼×²Î¼Ó·´Ó¦Ê±£¬µç×Ó×ªÒÆ mol¡£
¢ÛYµÄ×î¼òµ¥ÆøÌ¬Ç⻯Îï¼×ºÍQµÄÇ⻯ÎïÒÒ·´Ó¦Éú³ÉÕýÑεĵç×Óʽ £¬
¸Ã»¯ºÏÎïÖÐËùº¬»¯Ñ§¼üÀàÐÍÊÇ £¬¸Ã»¯ºÏÎïÊôÓÚ ¾§Ìå¡£
£¨1£©¢öA£¨2·Ö£© ¡¢ (2·Ö) £¨2£©Al>P>Cl (2·Ö)
£¨3£©CH2==CH2 £¨2·Ö£©
CH2==CH2 + H2O CH3CH2OH £¨2·Ö£©
£¨4£©¢Ù¢Ú 2NH3 + 3H2O2 === N2 +6H2O£¨2·Ö£© H2O2 £¨2·Ö£©3mol £¨2·Ö£©
¢Û(NH4)Sµç×ÓʽÂÔ £¨2·Ö£© Àë×Ó¼üºÍ¹²¼Û¼ü £¨2·Ö£©Àë×Ó¾§Ìå £¨2·Ö£©
½âÎö:
| A¡¢ÎåÖÖÔªËØÖУ¬Ô×Ó°ë¾¶×î´óµÄÊÇW | B¡¢YÓëZÐγɵϝºÏÎï¶¼¿ÉÒÔºÍÑÎËá·´Ó¦ | C¡¢YµÄ¼òµ¥ÒõÀë×Ó±ÈWµÄ¼òµ¥ÒõÀë×Ó»¹ÔÐÔÇ¿ | D¡¢ZÓëQÐγɵϝºÏÎïË®ÈÜÒºÒ»¶¨ÏÔËáÐÔ |
| A¡¢ÎåÖÖÔªËØÖУ¬Ô×Ó°ë¾¶×î´óµÄÊÇW | B¡¢YµÄ¼òµ¥ÒõÀë×Ó±ÈWµÄ¼òµ¥ÒõÀë×Ó»¹ÔÐÔÇ¿ | C¡¢YÓëZÐγɵϝºÏÎï¶¼¿ÉÒÔºÍÑÎËá·´Ó¦ | D¡¢ZÓëQÐγɵϝºÏÎïË®ÈÜÒºÒ»¶¨ÏÔËáÐÔ |
| A¡¢×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄËáÐÔ×îÇ¿µÄÊÇW | B¡¢YÓëZÖ»ÄÜÐγÉÒ»ÖÖ»¯ºÏÎï | C¡¢¼òµ¥ÒõÀë×Ó»¹ÔÐÔ£ºY£¾W | D¡¢ZÓëQÐγɵϝºÏÎïË®ÈÜÒº¿ÉÄÜÏÔËáÐÔ |