ÌâÄ¿ÄÚÈÝ

ÏÖÓйÌÌåÊÔ¼ÁX£ºZnÁ£¡¢Cu·Û¡¢NaCl¡¢£»Ëá»ò¼îÈÜÒºY£ºÅ¨¡¢Å¨ÑÎËá¡¢°±Ë®¡¢NaOHÈÜÒº£»ÑÎÈÜÒºZ£º¡¢¡¢KI¡¢£®

Ñ¡ÔñÉÏÊöÊÔ¼Á×öÒÔÏÂʵÑ飬¸ù¾ÝÏÖÏ󣬽«X¡¢Y¡¢ZµÄ»¯Ñ§Ê½ÌîÈë¿Õ°×´¦£º

(1)ºÚÉ«¹ÌÌåX________ÓëY________¹²ÈÈ£¬²úÉúÓд̼¤ÐÔÆøÎ¶µÄÆøÌå________£¬¸ÃÆøÌåÓöͨÈëÎÞÉ«Z________ÈÜÒºÖУ¬ÔټӺ󣬲ã³Ê×ÏÉ«£®

(2)ÊÔ¼ÁX________ºÍY________¹²ÈÈ£¬²úÉúÓд̼¤ÐÔÆøÎ¶µÄÆøÌåÓëÕ´ÓÐÊÔ¼ÁY________µÄ²£Á§°ô¿¿½üÓдóÁ¿°×ÑÌ________Éú³É£®

(3)ÊÔ¼ÁY________ÖмÓÈëX________¹²ÈÈ£¬XÈܽ⣬ÈÜÒº³ÊÀ¶É«£¬²¢²úÉúÓд̼¤ÐÔÆøÎ¶ÆøÌ壬¸ÃÆøÌåͨÈë×ÏÉ«Z________ÈÜÒºÖУ¬×ÏÉ«ÍÊÈ¥£®

(4)ÊÔ¼ÁY________ÓëYÖÐÁíÒ»ÊÔ¼Á________»ìºÏ£¬²úÉúÓд̼¤ÐÔÆøÎ¶ÆøÌå________£¬¸ÃÆøÌ弫Ò×ÈÜÓÚË®£¬ÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶£®

(5)ÊÔ¼ÁY________ÈÜÒºÓëZÈÜÒº·´Ó¦£¬Óа×

É«³Áµí________Éú³É£¬ZÓëZÖÐÁíÒ»ÊÔ¼Á________ÈÜÒº·´Ó¦Ò²Éú³É°×É«³Áµí£®

´ð°¸£º
½âÎö£º

(1)£¬Å¨ÑÎË᣻£»KI(2)NaCl£¬Å¨£»°±Ë®£» (3)Ũ£¬Cu·Û£¬£»(4)°±Ë®£¬NaOH£¬(5)HCl£»£»AgCl£»


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ÏÖÓйÌÌåÊÔ¼ÁX£ºZnÁ£¡¢Cu·Û¡¢NaCl¡¢MnO2£»Ëá»ò¼îÈÜÒºY£ºÅ¨H2SO4¡¢Å¨HCl¡¢°±Ë®¡¢NaOHÈÜÒº£»ÑÎÈÜÒºZ£ºAgNO3¡¢KMnO4¡¢KI¡¢BaCl2¡£Ñ¡ÔñÉÏÊöÊÔ¼Á×öÒÔÏÂʵÑ飬¸ù¾ÝÏÖÏ󣬽«X¡¢Y¡¢ZµÄ»¯Ñ§Ê½ÌîÓÚ¿Õ°×´¦£º

   £¨1£©ºÚÉ«¹ÌÌåX       ÓëY         ¹²ÈÈ£¬²úÉúÓд̼¤ÐÔÆøÎ¶µÄÆøÌå              £¬¸ÃÆøÌåͨÈëÎÞÉ«Z           ÈÜÒºÖУ¬ÔÙ¼ÓCCl4ºó£¬ÓͲã³Ê×ÏÉ«¡£

   £¨2£©ÊÔ¼ÁX           ºÍY        ¹²ÈÈ£¬²úÉúÓд̼¤ÐÔÆøÎ¶µÄÆøÌåÓëÕ´ÓÐÊÔ¼ÁY               µÄ²£Á§°ô¿¿½üÓдóÁ¿°×ÑÌ    Éú³É¡£

   £¨3£©ÊÔ¼ÁY                  ÖмÓÈëX                     ¹²ÈÈ£¬XÈܽ⣬ÈÜÒº³ÊÀ¶É«£¬²¢²úÉúÓд̼¤ÐÔÆøÎ¶ÆøÌ壬¸ÃÆøÌåͨÈë×ÏÉ«Z                          ÈÜÒºÖУ¬×ÏÉ«ÍÊÈ¥¡£

   £¨4£©ÊÔ¼ÁY                         ÓëYÖÐÁíÒ»ÊÔ¼Á                        »ìºÏ£¬²úÉúÓд̼¤ÐÔÆøÎ¶ÆøÌå                  £¬¸ÃÆøÌ弫Ò×ÈÜÓÚË®£¬ÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶¡£

   £¨5£©ÊÔ¼ÁY                  ÈÜÒºÓëZ                      ÈÜÒº·´Ó¦£¬Óа×É«³Áµí                     Éú³É£¬ZÓëZÖÐÁíÒ»ÊÔ¼Á                  ÈÜÒº·´Ó¦Ò²Éú³É°×É«³Áµí¡£

ÏÖÓйÌÌåÊÔ¼ÁX£ºZnÁ£¡¢Cu·Û¡¢NaCl¡¢MnO2£»Ëá»ò¼îÈÜÒºY£ºÅ¨H2SO4¡¢Å¨HCl¡¢°±Ë®¡¢NaOHÈÜÒº£»ÑÎÈÜÒºZ£ºAgNO3¡¢KMnO4¡¢KI¡¢BaCl2¡£Ñ¡ÔñÉÏÊöÊÔ¼Á×öÒÔÏÂʵÑ飬¸ù¾ÝÏÖÏ󣬽«X¡¢Y¡¢ZµÄ»¯Ñ§Ê½ÌîÓÚ¿Õ°×´¦£º

   £¨1£©ºÚÉ«¹ÌÌåX       ÓëY         ¹²ÈÈ£¬²úÉúÓд̼¤ÐÔÆøÎ¶µÄÆøÌå              £¬¸ÃÆøÌåͨÈëÎÞÉ«Z           ÈÜÒºÖУ¬ÔÙ¼ÓCCl4ºó£¬ÓͲã³Ê×ÏÉ«¡£

   £¨2£©ÊÔ¼ÁX           ºÍY        ¹²ÈÈ£¬²úÉúÓд̼¤ÐÔÆøÎ¶µÄÆøÌåÓëÕ´ÓÐÊÔ¼ÁY               µÄ²£Á§°ô¿¿½üÓдóÁ¿°×ÑÌ    Éú³É¡£

   £¨3£©ÊÔ¼ÁY                  ÖмÓÈëX                     ¹²ÈÈ£¬XÈܽ⣬ÈÜÒº³ÊÀ¶É«£¬²¢²úÉúÓд̼¤ÐÔÆøÎ¶ÆøÌ壬¸ÃÆøÌåͨÈë×ÏÉ«Z                          ÈÜÒºÖУ¬×ÏÉ«ÍÊÈ¥¡£

   £¨4£©ÊÔ¼ÁY                         ÓëYÖÐÁíÒ»ÊÔ¼Á                        »ìºÏ£¬²úÉúÓд̼¤ÐÔÆøÎ¶ÆøÌå                  £¬¸ÃÆøÌ弫Ò×ÈÜÓÚË®£¬ÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶¡£

   £¨5£©ÊÔ¼ÁY                  ÈÜÒºÓëZ                      ÈÜÒº·´Ó¦£¬Óа×É«³Áµí                     Éú³É£¬ZÓëZÖÐÁíÒ»ÊÔ¼Á                  ÈÜÒº·´Ó¦Ò²Éú³É°×É«³Áµí¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø