题目内容
VmL Al2(SO4)3溶液中含agAl3+,则溶液中SO42-的浓度是( )
A.
| B.
| ||||||||
C.
| D.
|
ag Al3+的物质的量为
=
mol,
根据电荷守恒可知:2n(SO42-)=3n(Al3+),
故n(SO42-)=
n(Al3+)=
×
mol=
mol,
则溶液中SO42-的浓度=
=
mol/L,
故选:C.
| ag |
| 27g/mol |
| a |
| 27 |
根据电荷守恒可知:2n(SO42-)=3n(Al3+),
故n(SO42-)=
| 3 |
| 2 |
| 3 |
| 2 |
| a |
| 27 |
| a |
| 18 |
则溶液中SO42-的浓度=
| ||
| V×10-3L |
| 500a |
| 9V |
故选:C.
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