ÌâÄ¿ÄÚÈÝ

A-H¼°X¾ùΪÖÐѧ»¯Ñ§³£¼ûÎïÖÊ£¬ XÊÇÒ»ÖÖ½ðÊôµ¥ÖÊ£¬A¡¢BÊǷǽðÊôµ¥ÖÊÇÒAÔÚ³£ÎÂÏÂÎªÆøÌå¡£ËüÃÇÔÚÒ»¶¨Ìõ¼þÏÂÓÐÈçÏÂת»¯¹ØÏµ£¨Í¼ÖÐÌõ¼þ¾ùÒÑÂÔÈ¥£©¡£
ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©Ð´³öCÎïÖʵĻ¯Ñ§Ê½_____________£»
£¨2£©ÔÚÉÏÊö¢Ù-¢Ý·´Ó¦Öп϶¨²»ÊôÓÚÑõ»¯»¹Ô­·´Ó¦µÄÊÇ______________£¨Ìî±àºÅ£©£»
£¨3£©Ö¸³öÔªËØXÔÚÔªËØÖÜÆÚ±íÖеÄλÖãº_____________£»
£¨4£©Çëд³ö·´Ó¦¢ÜºÍ¢ÝµÄÀë×Ó·½³Ìʽ£º ¢Ü______________£¬ ¢Ý_______________£»
£¨5£©ÓÃÀë×Ó·½³Ìʽ±íʾÔÚDÈÜÒºÖмÓÈëNaClOÈÜÒº²úÉúºìºÖÉ«³ÁµíµÄÔ­Òò£º______________________¡£
£¨1£©FeCl3    
£¨2£©4      
£¨3£©ËÄÖÜÆÚVIII×å           
£¨4£©FeS+2H+=Fe2+ +H2S¡ü  ; H2S+ Cl2=S+2H++2Cl                      £»
£¨5£©2Fe2++ClO-+4OH-+H2O=2Fe(OH)3+Cl- »ò 6Fe2++3ClO-+3H2O=2Fe(OH)3+3Cl-+4 Fe3+
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø