ÌâÄ¿ÄÚÈÝ

ÏÂÁÐʵÑé»òͼ±íµÄ½áÂÛ»ò½âÊÍÕýÈ·µÄÊÇ

 

ʵÑé»òͼ±í

½áÂÛ»ò½âÊÍ

A

ÂÁ²­Ôھƾ«µÆ»ðÑæÉϼÓÈÈÈÛ»¯µ«²»µÎÂä

ÂÁ²­±íÃæÉú³ÉµÄÑõ»¯Îï¾ßÓиßÈÛµã

B

ijCH3COOHºÍCH3COONa×é³ÉµÄËáÐÔÈÜÒºÖУ¬¼ÓÈëÒ»¶¨Á¿°±Ë®

c(CH3COO-)Ò»¶¨´óÓÚc(Na+)¡¢c(NH4+)Ö®ºÍ

C

¸Ã·´Ó¦ÈÈ»¯Ñ§·½³ÌʽΪ2CO(g)+O2(g)=2CO2(g)¦¤H=-566 kJ/mol

D

ÌúÖÆÈÝÆ÷¿ÉÓÃÓÚÊ¢×°ÀäµÄŨÁòËá

ÌúÓëŨÁòËá²»·´Ó¦

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø