ÌâÄ¿ÄÚÈÝ

ÏÂÁÐʵÑé»òͼ±íµÄ½áÂÛ»ò½âÊÍÕýÈ·µÄÊÇ£¨ £©
ʵÑé»òͼ±í½áÂÛ»ò½âÊÍ
AÂÁ²­Ôھƾ«µÆ»ðÑæÉϼÓÈÈÈÛ»¯µ«²»µÎÂäÂÁ²­±íÃæÉú³ÉµÄÑõ»¯Îï¾ßÓиßÈÛµã
BijCH3COOHºÍCH3COONa×é³ÉµÄËáÐÔÈÜÒºÖУ¬¼ÓÈëÒ»¶¨Á¿°±Ë®c£¨CH3COO-£©Ò»¶¨´óÓÚc£¨Na+£©¡¢c£¨NH4+£©Ö®ºÍ
C
¸Ã·´Ó¦ÈÈ»¯Ñ§·½³ÌʽΪ2CO£¨g£©+O2£¨g£©=2CO2£¨g£©¡÷H=-566kJ/mol
DÌúÖÆÈÝÆ÷¿ÉÓÃÓÚÊ¢×°ÀäµÄŨÁòËáÌúÓëŨÁòËá²»·´Ó¦

A£®A
B£®B
C£®C
D£®D
¡¾´ð°¸¡¿·ÖÎö£ºA¡¢Ñõ»¯ÂÁµÄÈÛµã±ÈÂÁµÄÈÛµã¸ß£¬ÂÁ²­Ôھƾ«µÆ»ðÑæÉϼÓÈÈÈÛ»¯µ«²»µÎÂ䣻
B¡¢CH3COOHºÍCH3COONa×é³ÉµÄËáÐÔÈÜÒºÖУ¬¼ÓÈëÒ»¶¨Á¿°±Ë®£¬ÈÜÒº¿ÉÄܳÊËáÐÔ¡¢¼îÐÔ»òÖÐÐÔ£¬½áºÏµçºÉÊغãÅжϣ»
C¡¢ÈÈ»¯Ñ§·´Ó¦·½³ÌʽÖз´Ó¦ÎïµÄÎïÖʵÄÁ¿Óë·´Ó¦·Å³öµÄÈÈÁ¿³ÉÕý±È£»
D¡¢ÌúÔÚŨÁòËáÖз¢Éú¶Û»¯£®
½â´ð£º½â£ºA¡¢Ñõ»¯ÂÁµÄÈÛµã±ÈÂÁµÄÈÛµã¸ß£¬ÂÁ²­Ôھƾ«µÆ»ðÑæÉϼÓÈÈÈÛ»¯µ«²»µÎÂ䣬½áÂÛ½âÊÍÕýÈ·£¬¹ÊAÕýÈ·£»
B¡¢ÈÜÒº³ÊµçÖÐÐÔ£¬ËùÒÔc£¨Na+£©+c£¨NH4+£©+c£¨H+£©=c£¨CH3COO-£©+c£¨OH-£©£¬ÈôÈÜÒº³ÊÖÐÐÔ£¬¼´c£¨H+£©=c£¨OH-£©£¬Ôòc£¨Na+£©+c£¨NH4+£©=c£¨CH3COO-£©£»ÈôÈÜÒº³ÊËáÐÔ£¬¼´c£¨H+£©£¾c£¨OH-£©£¬Ôòc£¨Na+£©+c£¨NH4+£©£¼c£¨CH3COO-£©£»ÈôÈÜÒº³Ê¼îÐÔ£¬¼´c£¨H+£©£¼c£¨OH-£©£¬Ôòc£¨Na+£©+c£¨NH4+£©£¾c£¨CH3COO-£©£¬¹ÊB´íÎó£»
C¡¢ÈÈ»¯Ñ§·´Ó¦·½³Ìʽ±íʾ2molCOȼÉշųöµÄÈÈÁ¿Îª566kJ£¬Í¼ÖÐÓ¦±íʾ1molCOȼÉÕÉú³É¶þÑõ»¯Ì¼·Å³öµÄÈÈÁ¿¹Øϵ£¬·´Ó¦ÈÈӦΪ-283kJ/mol£¬¹ÊC´íÎó£»
D¡¢ÌúÔÚŨÁòËá·´Ó¦Éú³ÉÒ»²ãÖÂÃܵÄÑõ»¯Îï±£»¤Ä¤×èÖ¹ÄÚ²¿½ðÊôÓëŨÁòËá¼ÌÐø·´Ó¦£¬¶ø·¢Éú¶Û»¯£¬¹ÊD´íÎó£®
¹ÊÑ¡A£®
µãÆÀ£º±¾Ì⿼²éÂÁ¼°»¯ºÏÎïÐÔÖÊ¡¢Àë×ÓŨ¶È±È½Ï¡¢ÈÈ»¯Ñ§·´Ó¦·½³Ìʽ¡¢Å¨ÁòËáÐÔÖʵȣ¬ÄѶÈÖеȣ¬×¢ÒâBÑ¡ÏîÈÜÒºµÄËá¼îÐÔ£®CÑ¡ÏîÖÐÃèÊöµÄ¾ÍÊÇÒ»¸öÈÈ»¯Ñ§·½³ÌʽעÒâ¡°¶ÌÏßÉÏ˵Ã÷µÄÎïÖÊ¡±²»½ö½ö´ú±íµÄÊÇ·´Ó¦Îï»òÕßÉú³ÉÎ¶øÆä¶ÔÓ¦µÄϵÊý´ú±íµÄÊDzμӷ´Ó¦µÄÎïÖʵÄÁ¿£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø