ÌâÄ¿ÄÚÈÝ
£¨08¸£ÖÝÈýÖÐÄ£Ä⣩ÏÂÁÐÊÇÓйØ2008Äê±±¾©°ÂÔË»áµÄÐû´«±¨µÀ£¬ÆäÖÐÓÐÃ÷ÏÔ´íÎóµÄÊÇ£¨ £©
A£®±±¾©°ÂÔ˻ἪÏéÎï¨D¸£Í޵IJÄÖÊÊÇPVC£¨¾ÛÂÈÒÒÏ¡£©£¬Æäµ¥ÌåÊÇCH2=CHCl
B£®±±¾©°ÂÔË»á»ð¾æ¨DÏéÔÆ»ð¾æµÄȼÁÏΪ±ûÍ飬Æä·Ö×ÓʽΪC3H8
C£®±±¾©°ÂÔ˻ὫʹÓÃï®µç³Ø¹«½»³µ¡£ï®µç³Ø×î´óÌØµãÊÇÌṩÏàͬµçÁ¿Ê±Õý¼«ÉÏÏûºÄµÄ½ðÊôÖÊÁ¿×îС
D£®±±¾©°ÂÔË»á½±ÅÆ¨D½ðÏâÓñ£¬ÆäÖÐÓñµÄ»¯Ñ§³ä·Ö¶àΪº¬Ë®¸ÆÃ¾¹èËáÑΣ¬¿ÉÓÃÑõ»¯Îï±íʾ¡£Èç2CaO?5MgO?8SiO2?H2O
£¨08¸£ÖÝÈýÖÐÄ£Ä⣩ÏÂÁл¯Ñ§ÓÃÓï±íÊöÕýÈ·µÄÊÇ £¨ £©
A£® ̼ËáÇâÄÆÈÜÒºÓëÉÙÁ¿ÇâÑõ»¯±µÈÜÒº»ìºÏµÄÀë×Ó·½³Ìʽ£º
HCO3-+Ba2++OH¨D = BaCO3¡ý+H2O
B£® 101Kpaʱ£¬2gÐÁÍéÍêȫȼÉÕÉú³É¶þÑõ»¯Ì¼ÆøÌåºÍҺ̬ˮ£¬·Å³ö96.8kJÈÈÁ¿£¬ÔòÏÂ
ÁбíʾÐÁÍéȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ£º
2C8H18£¨l£©+25O2£¨g£©=16CO2£¨g£©+18H2O£¨l£©£»¡÷H= - 6486.28kJ?mol¨D1
C£®H2O2µÄ½á¹¹Ê½H¨DO¨DO¨DH£¬NH4ClµÄµç×Óʽ![]()
D£® ÇâÑõȼÁÏµç³Ø¸º¼«·´Ó¦Ê½£ºH2 -2e¨D= 2H+£»
µç½â±¥ºÍʳÑÎË®µÄÒõ¼«·´Ó¦Ê½£º2H+ +2e¨D= H2¡ü