ÌâÄ¿ÄÚÈÝ
ÔÚÒ»¶¨Î¶ÈÏ·¢Éú·´Ó¦£ºI2(g)+H2(g)
2HI(g)£» ¡÷H<0²¢´ïƽºâ¡£HIµÄÌå»ý·ÖÊý
ËæÊ±¼ä±ä»¯ÈçͼÇúÏߣ¨II£©Ëùʾ¡£Èô¸Ä±ä·´Ó¦Ìõ¼þ£¬ÔÚ¼×Ìõ¼þÏÂ
µÄ±ä»¯ÈçÇúÏߣ¨I£©Ëùʾ¡£ÔÚÒÒÌõ¼þÏÂ
µÄ±ä»¯ÈçÇúÏߣ¨III£©Ëùʾ¡£Ôò¼×Ìõ¼þ¡¢ÒÒÌõ¼þ·Ö±ðÊÇ![]()
¢ÙºãÈÝÌõ¼þÏ£¬Éý¸ßÎÂ¶È ¢ÚºãÈÝÌõ¼þÏ£¬½µµÍζÈ
¢ÛºãÎÂÌõ¼þÏ£¬ËõС·´Ó¦ÈÝÆ÷Ìå»ý ¢ÜºãÎÂÌõ¼þÏ£¬À©´ó·´Ó¦ÈÝÆ÷Ìå»ý
¢ÝºãκãÈÝÌõ¼þÏ£¬¼ÓÈëÊʵ±µÄ´ß»¯¼Á
| A£®¢Ù¢Ý£¬¢Û | B£®¢Ú¢Ý£¬¢Ü | C£®¢Û¢Ý£¬¢Ú | D£®¢Û¢Ý£¬¢Ü |
D
½âÎö
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
½«1mol A£¨g£©ºÍ2mol B£¨g£©ÖÃÓÚ2LijÃܱÕÈÝÆ÷ÖУ¬ÔÚÒ»¶¨Î¶ÈÏ·¢Éú·´Ó¦£ºA£¨g£©+2B£¨g£©?C£¨g£©+D£¨g£©¡÷H£¼0£¬CµÄÌå»ý·ÖÊýËæÊ±¼ä±ä»¯ÈçͼlÖÐÇúÏßaËùʾ ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

| A¡¢´Ë·´Ó¦¹ý³ÌÖеÄÄÜÁ¿±ä»¯¿ÉÓÃÉÏͼII±íʾ | B¡¢´ËζÈÏ£¬¸Ã·´Ó¦µÄƽºâ³£ÊýµÄֵΪ1 | C¡¢¸Ã·´Ó¦4sÄÚÆ½¾ùËÙÂÊv£¨A£©=0.125mol?L-1?s-1 | D¡¢ÈôÔÚºãμӴó·´Ó¦ÈÝÆ÷µÄÈÝ»ýÌõ¼þÏ£¬¸Ã·´Ó¦½«°´bÇúÏß½øÐÐ |