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(1)Fe2O3(s)+3CO(g)=2Fe(s)+3CO2(g) ¡÷H = - 24. 9kJ¡¤mol -1
(2) NH3 (g) +HCl(g)=NH4Cl(s) ¡÷H=-176kJ¡¤ mol-1
(3) C6H12O6(s)+6O2(g)=6CO2(g)+6H2O(l) ¡÷H = -2 804kJ¡¤mol-1
(4)¢ÙCO(g)+H2O(g)=CO2(g)+H2(g) ¡÷H= - 41 kJ/mol
¢ÚCO2(g)+H2(g)=CO(g)+H2O(g) ¡÷H= +41 kJ/mol
(2) NH3 (g) +HCl(g)=NH4Cl(s) ¡÷H=-176kJ¡¤ mol-1
(3) C6H12O6(s)+6O2(g)=6CO2(g)+6H2O(l) ¡÷H = -2 804kJ¡¤mol-1
(4)¢ÙCO(g)+H2O(g)=CO2(g)+H2(g) ¡÷H= - 41 kJ/mol
¢ÚCO2(g)+H2(g)=CO(g)+H2O(g) ¡÷H= +41 kJ/mol
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