ÌâÄ¿ÄÚÈÝ

»¯Ñ§¼üµÄ¼üÄÜÊÇÐγɣ¨»ò²ð¿ª£©1mol»¯Ñ§¼üʱÊÍ·Å£¨»òÎüÊÕ£©³öµÄÄÜÁ¿¡£ÒÑÖª°×Á׺ÍP4O6£¨s£©µÄ·Ö×ӽṹÈçͼËùʾ£¬ÏÖÌṩÒÔÏ»¯Ñ§¼üµÄ¼üÄÜ£¨kJ¡¤mol£­1£©
£¨1£©Ð´³ö1mol P4£¨°×Á×£©ÓëO2·´Ó¦Éú³ÉP4O6µÄÈÈ»¯Ñ§·´Ó¦·½³Ìʽ_________________
£¨2£©ÒÑÖª°×Á×ÔÚÑõÆøÖÐȼÉÕ¿ÉÄÜÉú³ÉÁ½ÖÖ¹Ì̬Ñõ»¯ÎïÎP4O6Óë P4O10£©£¬3.1g°×Á×ÔÚ3.2gÑõÆøÖÐÇ¡ºÃÍêÈ«·´Ó¦£¬·Å³öÈÈÁ¿a kJ¡£¼ÆËã°×Á×µÄȼÉÕÈÈΪ¦¤H£½________£¨µÚ£¨1£©Ð¡ÌâÖеĦ¤HÒÔ-b kJ/mol´øÈë¼ÆË㣩
£¨3£©ÒÑÖª°×Á×ÓëºìÁ×»¥ÎªÍ¬ËØÒìÐÎÌ壬ËüÃǸ÷×ÔµÄÖ÷ÒªÀí»¯ÐÔÖÊÈçÏ£º
ÉÏͼΪºìÁ×Óë°×Á×Ï໥¼äת»¯µÄÄÜÁ¿±ä»¯Í¼£¬Çë¸ù¾ÝÉÏÊöÐÅÏ¢Ìî¿Õ¡£ X´ú±í_______£¨Ìî¡°ºìÁס±»ò¡°°×Áס±£©£»ÅжϵÄÀíÓÉ________________¡£
£¨1£©4P£¨°×Á×£©+3O2£¨g£©== P4O6£¨s£© ¡÷H=£­1638kJ/mol
£¨2£©(-80a+b)/4 kJ/mol
£¨3£©°×Á×£»°×Á×ÄÜÁ¿¸ß²»Îȶ¨
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨1£©»¯Ñ§·´Ó¦¿ÉÊÓΪ¾É¼ü¶ÏÁѺÍмüÐγɵĹý³Ì£®»¯Ñ§¼üµÄ¼üÄÜÊÇÐγɣ¨»ò²ð¿ª£©1mol»¯Ñ§¼üʱÊÍ·Å£¨»òÎüÊÕ£©µÄÄÜÁ¿£®ÒÑÖª£ºN¡ÔN¼üµÄ¼üÄÜÊÇ948.9kJ/mol£¬H-H¼üµÄ¼üÄÜÊÇ436.0kJ/mol£»ÓÉN2ºÍH2ºÏ³É1mol NH3ʱ¿É·Å³ö46.2kJµÄÈÈÁ¿£®ÔòN-H¼üµÄ¼üÄÜÊÇ
391.6KJ
391.6KJ
£®
£¨2£©¸Ç˹¶¨ÂÉÔÚÉú²úºÍ¿ÆÑ§Ñо¿ÖÐÓкÜÖØÒªµÄÒâÒ壮ÓÐЩ·´Ó¦µÄ·´Ó¦ÈÈËäÈ»ÎÞ·¨Ö±½Ó²âµÃ£¬µ«¿Éͨ¹ý¼ä½ÓµÄ·½·¨²â¶¨£®ÏÖ¸ù¾ÝÏÂÁÐ3¸öÈÈ»¯Ñ§·½³Ìʽ£º
Fe2O3£¨s£©+3CO£¨g£©=2Fe£¨s£©+3CO2£¨g£©¡÷H=-24.8kJ/mol      ¢Ù
3Fe2O3£¨s£©+CO£¨g£©=2Fe3O4£¨s£©+CO2£¨g£©¡÷H=-47.2kJ/mol    ¢Ú
Fe3O4£¨s£©+CO£¨g£©=3FeO£¨s£©+CO2£¨g£©¡÷H=+640.5kJ/mol      ¢Û
д³öCOÆøÌ廹ԭFeO¹ÌÌåµÃµ½Fe¹ÌÌåºÍCO2ÆøÌåµÄÈÈ»¯Ñ§·½³Ìʽ
CO£¨g£©+FeO£¨s£©=CO2£¨g£©+Fe£¨s£©£»¡÷H=-218.0kJ/mol
CO£¨g£©+FeO£¨s£©=CO2£¨g£©+Fe£¨s£©£»¡÷H=-218.0kJ/mol
£®
£¨3£©ÒÑÖªÁ½¸öÈÈ»¯Ñ§·½³Ìʽ£º
C£¨s£©+O2£¨g£©=CO2£¨g£©¡÷H=-393.5kJ/mol
2H2£¨g£©+O2£¨g£©=2H2O£¨g£©¡÷H=-483.6kJ/mol
ÏÖÓÐÌ¿·ÛºÍH2×é³ÉµÄÐü¸¡Æø¹²0.2mol£¬Ê¹ÆäÔÚO2ÖÐÍêȫȼÉÕ£¬¹²·Å³ö63.53kJµÄÈÈÁ¿£¬ÔòÌ¿·ÛÓëH2µÄÎïÖʵÄÁ¿Ö®±ÈÊÇ
1£º1
1£º1
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø