ÌâÄ¿ÄÚÈÝ
ÒÑÖªAΪÀ¶É«ÈÜÒº£¬B¡¢C¡¢I¡¢KΪµ¥ÖÊ£¬ÆäÓà¾ùΪ»¯ºÏÎï¡£B¡¢L¡¢K ³£ÎÂÏÂΪÎÞÉ«ÎÞÎ¶ÆøÌ壬IΪÓÐÉ«Óд̼¤ÐÔÆøÎ¶ÆøÌå¡£GΪºÚÉ«¹ÌÌ壬FµÄÑæÉ«·´Ó¦ÏÔ×ÏÉ«(͸¹ýîܲ£Á§¹Û²ì)¡£·´Ó¦¢ÝÖУ¬²úÎïF¡¢PµÄÎïÖʵÄÁ¿Ö®±ÈΪ1£º1¡£¸÷ÎïÖÊת»¯¹ØÏµÈçÏÂͼ£ºwww..com
![]()
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©PµÄµç×ÓʽÊÇ_________£»IËùº¬ÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÊÇ________________£»
£¨2£©Ð´³ö·´Ó¦¢ÙµÄÀë×Ó·½³Ìʽ£º ______________________________________________£»
£¨3£©MµÄË®ÈÜÒº³Ê___________£¨Ìî¡°ËáÐÔ¡±¡°¼îÐÔ¡±¡°ÖÐÐÔ¡±£©£¬ÓÃÀë×Ó·½³Ìʽ˵Ã÷ÔÒò£º______________________________________________________________
£¨4£©ÓöèÐԵ缫µç½â400.00mL AÈÜÒº£¬Ò»¶Îʱ¼äºó²âµÃÈÜÒºpH£½1£¬´ËʱÐèÒªÏòÈÜÒºÖмÓÈë___________£¬ÆäÖÊÁ¿Îª______g£¬²ÅÄÜʹÈÜÒº»Ö¸´µ½µç½âǰµÄ״̬£¨²»¿¼ÂÇÈÜÒºÌå»ý±ä»¯£©¡£
(14·Ö£©£¨1£©
£¨2·Ö£©£»µÚÈýÖÜÆÚ¢÷A×壻£¨2·Ö£©
£¨2£©3Cu + 8H+ + 2NO3£ = 3Cu2+ £« 2NO¡ü + 4H2O
£¨3£©ËáÐÔ£¨1·Ö£©£»Cu2+ + 2 H2O
Cu(OH)2 + 2 H+
£¨4£©CuO£¨»òÑõ»¯Í£©£¨2·Ö£©£»1.60 g£¨2·Ö£©£»£¨»òCuCO3£»2.48 g£©