ÌâÄ¿ÄÚÈÝ
£¨11·Ö£©Ä³Ñо¿ÐÔѧϰС×éµÄͬѧΪÔÚʵÑéÊÒÔÙÏÖ¶þÑõ»¯Áò´ß»¯Ñõ»¯µÄ¹ý³Ì£¬²¢ÖÆÈ¡ÉÙÁ¿ÈýÑõ»¯Áò¾§Ì壬Éè¼ÆÁËÈçͼËùʾµÄ×°Öá£ÒÑÖªÈýÑõ»¯ÁòÓöË®Éú³ÉÁòËá²¢·Å³ö´óÁ¿ÈÈ£¬ÈÝÒ×ÐγÉËáÎí£¬¹¤ÒµÉϳ£ÓÃŨÁòËáÎüÊÕÈýÑõ»¯Áò¡£
![]()
ÊԻشð£º
£¨1£©ÒÑÖª6.4 g ¶þÑõ»¯Áò±»ÑõÆøÑõ»¯³ÉÆøÌ¬ÈýÑõ»¯Áò£¬·Å³ö9.83 kJÈÈÁ¿¡£·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ____________________________________________________£»[À´Ô´:ѧ+¿Æ+Íø]
£¨2£©A×°ÖÿÉÓÃÀ´¹Û²ì¶þÑõ»¯ÁòºÍÑõÆøµÄ½øÆøÁ¿¡£ÊµÑéʱʹAÖÐÑõÆøµ¼¹Üð³öµÄÆøÅÝÓë¶þÑõ»¯Áòµ¼¹Üð³öµÄÆøÅÝËÙÂÊÏà½ü£¬ÆäÄ¿µÄÊÇ___________________________£»
£¨3£©¼ì²éÍê×°ÖÃµÄÆøÃÜÐÔÇÒ¼ÓÈëÒ©Æ·ºó£¬¿ªÊ¼½øÐÐʵÑé¡£´ËʱÊ×ÏÈÓ¦¸Ã½øÐеIJÙ×÷ÊÇ________________________________¡£
£¨4£©C×°ÖÃÓÃÀ´ÊÕ¼¯ÈýÑõ»¯Áò£¬ÈôÓÃa g͸ú×ãÁ¿Å¨ÁòËá·´Ó¦ÖÆ¶þÑõ»¯Áò£¬ÊµÑé½áÊøÊ±µÃµ½b g ÈýÑõ»¯Áò£¬¸ÃʵÑéÖжþÑõ»¯ÁòµÄת»¯Âʲ»Ð¡ÓÚ_________________£»
£¨5£©ÎªÁ˼õÇáʵÑé¶Ô»·¾³µÄÎÛȾ£¬ÇëÄãÉè¼ÆÎ²Æø´¦Àí×°Ö㬻æ³ö×°ÖÃͼ£º
__________________________________________________________ ¡£
£¨11·Ö£©
£¨1£©SO2£¨g£©+
O2£¨g£©
SO3£¨g£©£»¦¤H=-98.3kJ/mol £¨3·Ö£©
£¨2£©Ìá¸ß¶þÑõ»¯ÁòµÄת»¯ÂÊ£» £¨2·Ö£©
£¨3£©¸ø´ß»¯¼Á¼ÓÈÈ£»£¨2·Ö£©
£¨4£©
»ò
¡Á100%£¨2·Ö£©
£¨5£©½«Î²ÆøÍ¨ÈëÊ¢ÓÐŨÁòËáµÄÏ´ÆøÆ¿ºóÔÙͨÈëÊ¢ÓÐÇâÑõ»¯ÄÆÈÜÒºµÄÏ´ÆøÆ¿£¨»òͨÈëÊ¢ÓÐ×ãÁ¿¼îʯ»ÒµÄ¸ÉÔï¹ÜµÈ£©£¨2·Ö£©
¡¾½âÎö¡¿
£¨1£©Ð´³öÍÓëŨÁòËá·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
£¨2£©¸ÃС×éͬѧÔÚʵÑéÖз¢ÏÖÒÔÉÏʵÑé×°ÖÃÓÐÏ൱¶à²»×ãÖ®´¦£¬ÈçʵÑé²»¹»°²È«ºÍÒ×Ôì³É»·¾³ÎÛȾµÈ£®Îª¸Ä½øÊµÑéºÍ¸ü¶àµØÁ˽âSO2µÄÐÔÖÊ£¬¾¹ýͬѧÎʵÄÌÖÂÛºÍÓëÀÏʦµÄ½»Á÷£¬Éè¼ÆÁËÈçͼ2ʵÑé×°Öã®
¢ÙÇëд³ö³¤µ¼¹ÜBµÄ×÷ÓÃ
¢Ú¶ÔÊÔ¹ÜAÖеÄŨH2SO4ºÍÍÆ¬½øÐмÓÈÈ£¬·¢ÏÖEÊÔ¹ÜÖÐÓÐÆøÅÝÒݳö£¬Æ·ºìÈÜÒººÜ¿ìÍÊÉ«£¬µ«×îÖÕδ¼ûDÊÔ¹ÜÖÐÇâÑõ»¯±µÈÜÒº³öÏÖ»ë×Ç£®ÎªÌ½¾¿DÊÔ¹ÜÖÐδ³öÏÖ»ë×ǵÄÔÒò£¬¸ÃС×éͬѧÔÚ»¯Ñ§ÊÖ²áÖÐÖ»²éÔĵ½ÏÂÁÐÎïÖʳ£ÎÂϵÄÈܽâ¶ÈÊý¾Ý£º
| ÎïÖÊ | Èܽâ¶È£¨g/100Ë®£© | ÎïÖÊ | Èܽâ¶È£¨g/100Ë®£© |
| Ca£¨OH£©2 | 0.173 | Ba£¨OH£©2 | 3.89 |
| CaCO3 | 0.0013 | BaSO3 | 0.016 |
| Ca£¨HCO3£©2 | 16.60 |
¢ÛΪÑéÖ¤DÊÔ¹ÜÖÐÈÜÒºµÄ×é³É£¬½øÐÐÁËÏÂÁÐʵÑ飬ÇëÄã°ïËûÃÇÍê³ÉÏÂÁÐʵÑéÄÚÈÝ£º
| ʵÑé·½°¸ | ÏÖÏó |
| 1£®È¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬¼ÓÈëÏ¡ÑÎËᣬ¼ÓÈÈ£¬ ÓÃʪÈóµÄÀ¶É«Ê¯ÈïÊÔÖ½¼ìÑéÉú³ÉµÄÆøÌ壮 |
|
| 2£®È¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬¼ÓÈë |