ÌâÄ¿ÄÚÈÝ

¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµ¥ÖÊ£¬ÒÒ¡¢±ûÁ½ÔªËØÔÚÖÜÆÚ±íÖÐλÓÚͬÖ÷×å¡£X¡¢A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¾ùΪ³£¼ûµÄ»¯ºÏÎÆäÖÐAºÍXµÄĦ¶ûÖÊÁ¿Ïàͬ£¬A¡¢F¡¢C¡¢GµÄÑæÉ«·´Ó¦¶¼Îª»ÆÉ«¡£ÔÚÒ»¶¨Ìõ¼þÏ£¬¸÷ÎïÖÊÏ໥ת»¯¹ØÏµÈçÏÂͼ¡£
Çë»Ø´ð£º  
£¨1£©Óû¯Ñ§Ê½±íʾ£º±ûΪ___________£¬EΪ ____________¡£
£¨2£©XµÄµç×ÓʽΪ_____________¡£
£¨3£©AÓëH2O·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________¡£
£¨4£©Ð´³ö¢á¶ÔÓ¦µÄÀë×Ó·´Ó¦·½³Ìʽ______________¡£
£¨5£©Ð´³öÒÒÓë±ûµãȼÉú³ÉDµÄ»¯Ñ§·´Ó¦·½³Ìʽ²¢±ê³öµç×Ó×ªÒÆÇé¿ö£º______________¡£
£¨1£©O2  £» SO3 
£¨2£©     
£¨3£©2Na2O2+2H2O==4NaOH+O2
£¨4£©HCO3+ OH= H2O + CO32-
£¨5£©S+O2SO2 
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµ¥ÖÊ£¬ÒÒ¡¢±ûÁ½ÔªËØÔÚÖÜÆÚ±íÖÐλÓÚͬһÖ÷×壮X¡¢A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¾ùΪ³£¼ûµÄ»¯ºÏÎÆäÖÐAºÍXµÄĦ¶ûÖÊÁ¿Ïàͬ£¬A¡¢FµÄÑæÉ«·´Ó¦Îª»ÆÉ«£®ÔÚÒ»¶¨Ìõ¼þÏ£¬¸÷ÎïÖÊÏ໥ת»¯¹ØÏµÈçͼ£®
Çë»Ø´ð£º
£¨1£©Ð´»¯Ñ§Ê½£º±û
O2
O2
    E
SO3
SO3

£¨2£©XµÄµç×ÓʽΪ
£¬GµÄ¿Õ¼ä¹¹ÐÍÊÇ
Ö±ÏßÐÍ
Ö±ÏßÐÍ
£®
£¨3£©Ð´³ö·´Ó¦¢ÝµÄ»¯Ñ§·´Ó¦·½³Ìʽ£º
2Na2O2+2H2O¨T4NaOH+O2¡ü
2Na2O2+2H2O¨T4NaOH+O2¡ü
£®
£¨4£©Ð´³öBÈÜÒºÓëG·´Ó¦Éú³ÉFµÄÀë×Ó·½³Ìʽ£º
CO2+2OH-¨TCO32-+H2O
CO2+2OH-¨TCO32-+H2O
£®
£¨5£©ÔÚÉÏͼ¢Ù-¢áµÄ·´Ó¦ÖУ¬²»ÊôÓÚÑõ»¯»¹Ô­·´Ó¦µÄÊÇ£¨ÌîÐòºÅ£©
¢à¢á
¢à¢á
£®
£¨6£©½«8g ÒÒÔÚ×ãÁ¿±ûÖÐȼÉÕ£¬ËùµÃÆøÌåDͨÈë100mL 3.5mol?L-1µÄBÈÜÒºÖУ¬ÍêÈ«ÎüÊÕºó£¬ÈÜÒºÖеÄÈÜÖʼ°ÆäÎïÖʵÄÁ¿·Ö±ðΪ
0.1 5mol NaHSO3ºÍ0.1 mol Na2SO3
0.1 5mol NaHSO3ºÍ0.1 mol Na2SO3
£»ÈôͬÌå»ýµÄÆøÌåDͨÈë100mL 2.5mol?L-1µÄBÈÜÒºÖУ¬ÍêÈ«ÎüÊÕºó£¬ÈÜÒºÖÐËùº¬Àë×ÓµÄÎïÖʵÄÁ¿Å¨¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ
c£¨Na+£©£¾c£¨HSO3-£©£¾c£¨H+£©£¾c£¨SO32-£©£¾c£¨OH-£©
c£¨Na+£©£¾c£¨HSO3-£©£¾c£¨H+£©£¾c£¨SO32-£©£¾c£¨OH-£©
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø