ÌâÄ¿ÄÚÈÝ

2008Äê±±¾©°ÂÔË»áËùÓûð¾æÈ¼ÁÏΪ±ûÍ飨C3H8£©£¬Ï¤Äá°ÂÔË»áËùÓûð¾æÈ¼ÁÏΪ65%¶¡Í飨C4H10£©ºÍ35%±ûÍ飨C3H8£©£¬ÒÑÖª³£ÎÂÏÂ1mol±ûÍéȼÉշųö2220kJÈÈÁ¿£¬1molÕý¶¡ÍéȼÉշųö2878kJÈÈÁ¿£¬1molÒì¶¡ÍéȼÉշųö2869.6kJÈÈÁ¿¡£ÊԻشðÏÂÁÐÎÊÌ⣺

£¨1£©±íʾÕý¶¡ÍéȼÉÕµÄÈÈ»¯Ñ§·´Ó¦·½³Ìʽ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £»

£¨2£©ÏÂÁÐÓйØËµ·¨ÕýÈ·µÄÊÇ¡¡¡¡¡¡¡¡ £»

¡¡¡¡ A£®°ÂÔË»ð¾æÈ¼ÉÕʱµÄÄÜÁ¿×ª»¯Ö÷ÒªÊÇÓÉ»¯Ñ§ÄÜת±äΪÈÈÄÜ

¡¡¡¡ B£®ÏàͬÌõ¼þÏÂÏàͬÖÊÁ¿µÄÕý¶¡ÍéºÍ±ûÍé³ä·ÖȼÉÕ£¬·Å³öµÄÈÈÁ¿Õý¶¡ÍéµÄ±È½Ï¶à

¡¡¡¡ C£®Õý¶¡Íé±ÈÒì¶¡Íé²»Îȶ¨

¡¡¡¡ D£®Òì¶¡Íé·Ö×ÓÖеÄ̼Çâ¼ü±ÈÕý¶¡ÍéµÄ¶à

£¨3£©ÒÑÖª1mol H2ȼÉÕÉú³ÉҺ̬ˮ·Å³öÈÈÁ¿ÊÇ285.8 kJ£¬ÏÖÓÐ5mol ÇâÆøºÍ±ûÍéµÄ»ìºÏÆøÌ壬ÍêȫȼÉÕʱ·ÅÈÈ3847kJ£¬ÔòÇâÆøºÍ±ûÍéµÄÌå»ý±ÈΪ¡¡¡¡¡¡¡¡ ¡£

£¨1£©C4H10(Õý¶¡Í飬g) + 13/2O2(g)¡ú4CO2(g)+5H2O(l) ¡÷H= -2878 kJ•mol-1£¨3·Ö£¬ÆäËûºÏÀí´ð°¸¶¼¶Ô£©£»

£¨2£©A C £¨2·Ö£¬ÓдíÈ«¿Û£¬²»È«¿Û1·Ö£©Ks5u

£¨3£©3:1£¨3·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø