ÌâÄ¿ÄÚÈÝ
°×É«·ÛÄ©AÓÉNa2S¡¢Na2SO3¡¢Na2SO4ºÍNaClµÈÎïÖÊÖеÄÁ½ÖÖ»òÈýÖÖ»ìºÏ¶ø³É£¬È¡Ò»¶¨Á¿AÑùÆ·£¬Í¶Èë200 mL¡¡2.2 mol¡¤L£1ÑÎËáÖУ¬³ä·Ö·´Ó¦ºó¹ýÂË£¬×îÖÕµÃ200 mLº¬H+µÄÎïÖʵÄÁ¿Å¨¶ÈΪ1.0 mol¡¤L£1µÄÂËÒº£®Èô½«´ËÂËÒºÕô¸É£¬Ö»µÃµ½16.38 g´¿¾»ÎïB£®(ÒÑÖª2S2££«
£«6H+
3S¡ý£«3H2O)
(1)´¿¾»ÎïBµÄ»¯Ñ§Ê½Îª________£®
(2)AÖÐÊÇ·ñº¬ÓÐNaCl________(Ìîд¡°ÓС±»ò¡°Ã»ÓС±)£¬ÀíÓÉÊÇʲô(ͨ¹ý¼ÆËã»Ø´ð)£¿
(3)Èô·´Ó¦ºó»¹Éú³É1.008 L(±ê×¼×´¿ö)µÄÒ»ÖÖÆøÌ壬ÇÒ¸ÃÆøÌå²»»áʹƷºìÍÊÉ«£¬ÇóËùÈ¡µÄAÑùÆ·Öк¬ÓÐNa2SµÄÎïÖʵÄÁ¿£®
´ð°¸£º
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿