ÌâÄ¿ÄÚÈÝ

ÔÚÒ»´Î»¯Ñ§Ñо¿ÐÔѧϰʵÑéÖУ¬Ä³Ñо¿Ð¡×éѧÉú£¬Ñо¿·ÖÎöijÁ½Æ¿ÎÞ±êÇ©µÄÊÔ¼Á£¬Ö»ÖªµÀһƿÊǹÌÌ壬ÁíһƿÊÇÒºÌ壬ȡÉÙÁ¿Á½ÖÖÊÔ¼ÁÔÚÊÔ¹ÜÖлìºÏ£¬Á¢¼´²úÉúÒ»ÖÖÎÞÉ«ÎÞζµÄÆøÌå¡£ÏÖÇëÄã¶Ô´ËÆøÌ忪չһϵÁÐ̽¾¿£¬²¢Íê³ÉÏÂÁÐʵÑ鱨¸æ¡£

£¨1£©¢Ù´ËÆøÌåÊÇʲôÎïÖÊ£¨Ö»Ð´³öÆäÖпÉÄܵÄÒ»ÖÖ£©£¿ÑéÖ¤ËüµÄʵÑé·½°¸ÈçÏ£º

²ÂÏë

ʵÑé²½Öè

ÏÖÏó¼°½áÂÛ

´ËÆøÌå¿ÉÄÜÊÇ____

__

²úÉú´ËÆøÌåµÄ»¯Ñ§·½³Ìʽ¿ÉÄÜÊÇ___________________________

¢ÚÏëÖÆÈ¡¸ÃÆøÌ壨Óñ¾ÌâÖÐÁ½Æ¿ÎÞ±êÇ©µÄÊÔ¼Á£©£¬²ÉÓõķ¢Éú×°ÖÿÉÑ¡ÓÃÏÂͼA¡¢B¡¢CÖеÄ__________ (¶ÔÓ¦ÌîÐòºÅ)¡£ÊÕ¼¯¸ÃÆøÌå¿ÉÑ¡ÓÃDÖеĠ       ×°Öá£

 ¢ÛÈôÏÂͼEÊÇÊÕ¼¯¸ÃÆøÌåµÄ×°Öã¬ÆøÌåÓÉ         ¶Ë£¨Ìî¡°a¡±»ò¡°b¡±£©µ¼Èë¡£

    E

(2)²ÂÏë´ËÎÞÉ«ÆøÌ廹ÓÐÎÞ¿ÉÄÜÊÇÁíÒ»ÖÖÆøÌ壬Èç¹ûÓУ¬

Çëд³ö²úÉúËüµÄ»¯Ñ§·½³Ìʽ______      __                ___£¨Ö»ÐëдһÖÖ£©¡£

£¨1£©¢ÙÑõÆø(O2)[»ò¶þÑõ»¯Ì¼(CO2)»òÇâÆø(H2)]£»£¨2·Ö£©½«´ø»ðÐǵÄľÌõ²åÈëÊÔ¹ÜÖУ¬Ä¾Ìõ¸´È¼£¬ÔòÖ¤Ã÷ÊÇÑõÆø£»£¨»ò½«ÆøÌåͨÈë³ÎÇåµÄʯ»ÒË®ÖУ¬Ê¯»ÒË®±ä»ë×Ç£¬ÔòÖ¤Ã÷ÊǶþÑõ»¯Ì¼£»»ò½«ÊԹܿڶÂÒ»»á¶ù£¬µãȼ´ËÆøÌ壬ÄÜȼÉÕ£¬²úÉúµ­À¶É«»ðÑæ»òÌýµ½±¬ÃùÉù£¬ÔòÖ¤Ã÷ÊÇÇâÆø£©£»£¨4·Ö£©2H2O2 2H2O +O2¡ü£¨»ò CaCO3 + 2HCl = CaCl2 + H2O + CO2¡ü£»Zn + 2HCl = ZnCl2 + H2¡ü£©£»£¨2·Ö£©

¢Ú B£»  £¨2·Ö£©¢ÛÈôÉÏÌîO2»òCO2ÔòÌîa»òH2ÔòÌîb£»£¨2·Ö£©

£¨2£©ÉÏÊöÆøÌåÖеÄÈÎÒ»Öֵķ½³Ìʽ¾ù¿É£¨ÒÑÌîµÄ³ýÍ⣩¡££¨2·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨10·Ö£©Ëæ×ÅÈËÃÇÈÕ³£Éú»îˮƽµÄÌá¸ß£¬ÊÒÄÚ¿ÕÆøÎÛȾԽÀ´Ô½Êܵ½ÈËÃǵÄÖØÊÓ¡£Ôì³ÉÊÒÄÚ»·¾³ÎÛȾµÄÓж¾ÎïÖÊÖ÷ÒªÓм×È©¡¢±½¡¢°±¡¢ë±¡¢Ò»Ñõ»¯Ì¼µÈÎïÖÊ¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢Å±½·Ö×ӵĽṹ¼òʽΪ         ¡£
¢ÆÎÒ¹ú¡¶ÊÒÄÚ¿ÕÆøÖÊÁ¿±ê×¼¡·¹æ¶¨ÊÒÄÚ¿ÕÆøÖм×È©£¨HCHO£©º¬Á¿²»µÃ³¬¹ý0.08mg/m3¡£Ä³Ð£»¯Ñ§Ñо¿ÐÔѧϰС×éµÄͬѧͨ¹ý²éÔÄ×ÊÁÏ£¬Äâ²ÉÓÃÈçÏ·½·¨²â¶¨Ä³ÐÂ×°ÐÞ¾ÓÊÒÄÚ¿ÕÆøÖм×È©µÄº¬Á¿¡£
²â¶¨Ô­Àí£º5HCHO£«4KMnO4£«6H2SO4£½2K2SO4£«4MnSO4£«5CO2¡ü£«11H2O
ʵÑé²Ù×÷£ºÓÃÈÝ»ýΪ1000 mLµÄÒ½ÓÃ×¢ÉäÆ÷³éÈ¡¿ÕÆø£¬»ºÂý×¢ÈëËáÐÔ¸ßÃÌËá¼ØÈÜÒºÖУ¨×°ÖÃÈçÏ£©£¬µ±ËáÐÔ¸ßÃÌËá¼ØÈÜÒºÕýºÃÍÊɫʱ£¬Í£Ö¹×¢Èë¡£

¢ÙÓÃ0.1000mol/LµÄËáÐÔKMnO4ÈÜÒºÅäÖÆÊµÑéÖÐʹÓõÄËáÐÔKMnO4ÈÜÒº1000mL£¬Ðè0.1000mol/LµÄËáÐÔKMnO4ÈÜÒºµÄÌå»ýΪ         ¡£
¢ÚÏòËáÐÔ¸ßÃÌËá¼ØÈÜÒºÖÐ×¢Èë¿ÕÆøÇ°£¬Ó¦¼ì²éÎüÊÕÆ÷×°ÖÃÆøÃÜÐÔ£¬²Ù×÷·½·¨Îª         £»×°ÖÃÖжà¿×²£Á§ÇòµÄ×÷ÓÃÊÇ           ¡£
¢ÛʵÑéʱÔÚ¾ÓÊÒÄÚ²»Í¬µØµã³éÈ¡¿ÕÆø£¬²¢»ºÂý×¢ÈëËáÐÔ¸ßÃÌËá¼ØÈÜÒºÖС£µ±µÚ200´Î½«×¢ÉäÆ÷ÖÐ¿ÕÆøÈ«²¿»ºÂý×¢ÈëËáÐÔ¸ßÃÌËá¼ØÈÜÒºÖÐʱ£¬ËáÐÔ¸ßÃÌËá¼ØÈÜÒºÕýºÃÍÊÉ«¡£Çëͨ¹ý¼ÆËã˵Ã÷¸Ã¾ÓÊÒ¿ÕÆøÖм×È©º¬Á¿ÊÇ·ñ³¬±ê£¨¿ÕÆøÖÐÆäËû³É·Ö²»ÓëËáÐÔ¸ßÃÌËá¼ØÈÜÒº·´Ó¦£©¡£
¢ÜÇëÄã¾Ù³ö¼õÉÙÊÒÄÚ¿ÕÆøÎÛȾµÄÒ»ÌõºÏÀí´ëÊ©£º            ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø