ÌâÄ¿ÄÚÈÝ
ÏÂÁÐÊÇA¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¡¢H¼°±û¶þËá(HOOCCH2COOH)¼äת»¯·´Ó¦µÄ¹ØÏµÍ¼£®AÊÇÒ»ÖÖÁ´×´ôÈËᣬ·Ö×ÓʽΪC3H4O2£»FÖк¬ÓÐÓɯߏöÔ×Ó¹¹³ÉµÄ»·£»HÊÇÒ»Öָ߷Ö×Ó»¯ºÏÎÇëÌîдÏÂÁпհףº
![]()
(1)CµÄ½á¹¹¼òʽ£º________£»FµÄ½á¹¹¼òʽ£º________£®
(2)д³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³ÌʽºÍ·´Ó¦ÀàÐÍ£º
¢ÙA¡úHµÄ»¯Ñ§·½³Ìʽ£º________£¬________£»
¢ÚBÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º________£¬________£»
¢ÛG¡ú±û¶þËáµÄ»¯Ñ§·½³Ìʽ£º________£¬________£»
(3)ʵÑéÊÒÖÆ±¸Òø°±ÈÜÒºµÄ²Ù×÷¹Ø¼üÊÇ£º________£®
´ð°¸£º
½âÎö£º
½âÎö£º
|
¡¡¡¡(1)C£ºBrCH2CH2COOH£»F£º ¡¡¡¡(2)ÿ¸ö·½³Ìʽ2·Ö£¬·´Ó¦ÀàÐÍ1·Ö ¡¡¡¡¢ÙnCH2£½CH£COOH ¡¡¡¡¢ÚCH3CHBrCOOH£«2NaOH ¡¡¡¡¢ÛOHCCH2COOH£«2Ag(NH3)2OH ¡¡¡¡(3)ÏòÏõËáÒøÈÜÒºÖеμӰ±Ë®ÖÁ³ÁµíÇ¡ºÃÏûʧΪֹ(2·Ö) |
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÏÂÁÐÊÇA¡¢B¡¢C¡¢D¡¢EÎåÖÐÔªËØµÄijЩÐÔÖÊ£º
£¨1£©ÔªËØAÊÇÐγÉÓлúÎïµÄÖ÷ÒªÔªËØ£¬ÏÂÁзÖ×ÓÖк¬ÓÐspºÍsp3 ÔÓ»¯·½Ê½µÄÊÇ
A£®
B£®CH4 C£®CH2=CHCH3D£®CH3CH2C¡ÔCH E£®CH3CH3
£¨2£©ÓÃÇâ¼ü±íʾʽд³öEµÄÇ⻯ÎïË®ÈÜÒºÖдæÔÚµÄËùÓÐÇâ¼ü £®
£¨3£©ÏàͬÌõ¼þÏ£¬AD2ÓëBD2·Ö×ÓÁ½ÕßÔÚË®ÖеÄÈܽâ¶È½Ï´óµÄÊÇ £¨Ð´·Ö×Óʽ£©£¬ÀíÓÉÊÇ £»
£¨4£©Èçͼ±íʾijÖÖÔªËØDÓëпÐγɵϝºÏÎï¾§°û£¬ÆäÖÐZnºÍDͨ¹ý¹²¼Û¼ü½áºÏ£¬¸Ã»¯ºÏÎïµÄ»¯Ñ§Ê½Îª £»¸Ã»¯ºÏÎïµÄ¾§ÌåÈÛµã±È¸É±ù¸ßµÃ¶à£¬ÔÒòÊÇ £®
| A | B | C | D | E | |
| »¯ºÏ¼Û | -4 | -2 | -1 | -2 | -1 |
| µç¸ºÐÔ | 2.55 | 2.58 | 3.16 | 3.44 | 3.98 |
A£®
£¨2£©ÓÃÇâ¼ü±íʾʽд³öEµÄÇ⻯ÎïË®ÈÜÒºÖдæÔÚµÄËùÓÐÇâ¼ü
£¨3£©ÏàͬÌõ¼þÏ£¬AD2ÓëBD2·Ö×ÓÁ½ÕßÔÚË®ÖеÄÈܽâ¶È½Ï´óµÄÊÇ
£¨4£©Èçͼ±íʾijÖÖÔªËØDÓëпÐγɵϝºÏÎï¾§°û£¬ÆäÖÐZnºÍDͨ¹ý¹²¼Û¼ü½áºÏ£¬¸Ã»¯ºÏÎïµÄ»¯Ñ§Ê½Îª