ÌâÄ¿ÄÚÈÝ
ÒÀ¾ÝÊÂʵ£¬Ð´³öÏÂÁз´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£®
£¨1£©ÔÚ25¡æ¡¢101kPaÏ£¬3molNO2ÆøÌåÓë×ãÁ¿µÄË®·´Ó¦Éú³ÉÏõËáºÍNOÆøÌå·ÅÈÈ138KJ£®
£¨2£©ÒÑÖª²ð¿ª1mol H-H¼ü£¬1mol N-H¼ü£¬1mol N¡ÔN¼ü·Ö±ðÐèÒªµÄÄÜÁ¿ÊÇ436kJ¡¢391kJ¡¢946kJ£¬ÔòN2ÓëH2·´Ó¦Éú³ÉNH3µÄÈÈ»¯Ñ§·½³ÌʽΪ
£¨3£©ÒÔ¼×ÍéΪÔÁÏÖÆÈ¡ÇâÆøÊǹ¤ÒµÉϳ£ÓõÄÖÆÇâ·½·¨£®
ÒÑÖª£ºCH4£¨g£©+H2O£¨g£©¨TCO£¨g£©+3H2£¨g£©¡÷H=+206.2kJ?mol-1
CH4£¨g£©+CO2£¨g£©¨T2CO£¨g£©+2H2£¨g£©¡÷H=+247.4kJ?mol-1
Çëд³öCH4£¨g£©ÓëH2O£¨g£©·´Ó¦Éú³ÉCO2£¨g£©ºÍH2£¨g£©µÄÈÈ»¯Ñ§·½³Ìʽ
£¨1£©ÔÚ25¡æ¡¢101kPaÏ£¬3molNO2ÆøÌåÓë×ãÁ¿µÄË®·´Ó¦Éú³ÉÏõËáºÍNOÆøÌå·ÅÈÈ138KJ£®
3NO2£¨g£©+H2O£¨l£©=2HNO3£¨aq£©+NO£¨g£©¡÷H=-138 kJ?mol-1
3NO2£¨g£©+H2O£¨l£©=2HNO3£¨aq£©+NO£¨g£©¡÷H=-138 kJ?mol-1
£®£¨2£©ÒÑÖª²ð¿ª1mol H-H¼ü£¬1mol N-H¼ü£¬1mol N¡ÔN¼ü·Ö±ðÐèÒªµÄÄÜÁ¿ÊÇ436kJ¡¢391kJ¡¢946kJ£¬ÔòN2ÓëH2·´Ó¦Éú³ÉNH3µÄÈÈ»¯Ñ§·½³ÌʽΪ
N2£¨g£©+3H2£¨g£©?2NH3£¨g£©¡÷H=-92 kJ?mol-1
N2£¨g£©+3H2£¨g£©?2NH3£¨g£©¡÷H=-92 kJ?mol-1
£®£¨3£©ÒÔ¼×ÍéΪÔÁÏÖÆÈ¡ÇâÆøÊǹ¤ÒµÉϳ£ÓõÄÖÆÇâ·½·¨£®
ÒÑÖª£ºCH4£¨g£©+H2O£¨g£©¨TCO£¨g£©+3H2£¨g£©¡÷H=+206.2kJ?mol-1
CH4£¨g£©+CO2£¨g£©¨T2CO£¨g£©+2H2£¨g£©¡÷H=+247.4kJ?mol-1
Çëд³öCH4£¨g£©ÓëH2O£¨g£©·´Ó¦Éú³ÉCO2£¨g£©ºÍH2£¨g£©µÄÈÈ»¯Ñ§·½³Ìʽ
CH4£¨g£©+2H2O£¨g£©¨TCO2£¨g£©+4H2£¨g£©¡÷H=+165 kJ?mol-1
CH4£¨g£©+2H2O£¨g£©¨TCO2£¨g£©+4H2£¨g£©¡÷H=+165 kJ?mol-1
£®·ÖÎö£º£¨1£©Êéд»¯Ñ§·½³Ìʽ£¬±ê×¢ÎïÖʾۼ¯×´Ì¬ºÍ¶ÔÓ¦·´Ó¦Á¿µÄ·´Ó¦ÈÈ£»
£¨2£©ÒÀ¾Ý»¯Ñ§·½³Ìʽ½áºÏ·´Ó¦ÈÈ=²ð»¯Ñ§¼üÎüÊÕµÄÄÜÁ¿-Ðγɻ¯Ñ§¼ü·Å³öµÄÄÜÁ¿£¬¼ÆËã·´Ó¦ÈÈ£¬±ê×¢ÎïÖʾۼ¯×´Ì¬Ð´³öÈÈ»¯Ñ§·½³Ìʽ£»
£¨3£©ÒÀ¾Ý¸Ç˹¶¨ÂÉ£¬ÀûÓÃÈÈ»¯Ñ§·½³Ìʽ¼ÆËãµÃµ½ËùÐèÈÈ»¯Ñ§·½³Ìʽ£®
£¨2£©ÒÀ¾Ý»¯Ñ§·½³Ìʽ½áºÏ·´Ó¦ÈÈ=²ð»¯Ñ§¼üÎüÊÕµÄÄÜÁ¿-Ðγɻ¯Ñ§¼ü·Å³öµÄÄÜÁ¿£¬¼ÆËã·´Ó¦ÈÈ£¬±ê×¢ÎïÖʾۼ¯×´Ì¬Ð´³öÈÈ»¯Ñ§·½³Ìʽ£»
£¨3£©ÒÀ¾Ý¸Ç˹¶¨ÂÉ£¬ÀûÓÃÈÈ»¯Ñ§·½³Ìʽ¼ÆËãµÃµ½ËùÐèÈÈ»¯Ñ§·½³Ìʽ£®
½â´ð£º½â£º£¨1£©3molNO2ÆøÌåÓë×ãÁ¿µÄË®·´Ó¦Éú³ÉÏõËáºÍNOÆøÌå·ÅÈÈ138KJ£¬·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£º3NO2£¨g£©+H2O£¨l£©=2HNO3£¨aq£©+NO£¨g£©¡÷H=-138 kJ?mol-1£¬
¹Ê´ð°¸Îª£º3NO2£¨g£©+H2O£¨l£©=2HNO3£¨aq£©+NO£¨g£©¡÷H=-138 kJ?mol-1£»
£¨2£©ÒÑÖª²ð¿ª1mol H-H¼ü£¬1mol N-H¼ü£¬1mol N¡ÔN¼ü·Ö±ðÐèÒªµÄÄÜÁ¿ÊÇ436kJ¡¢391kJ¡¢946kJ£¬»¯Ñ§·½³ÌʽΪN2+3H2?2NH3£¬ÒÀ¾Ý»¯Ñ§·½³Ìʽ¼ÆËã·´Ó¦ÈÈ=946kJ/mol+3¡Á436kJ/mol-6¡Á391kJ/mol=-92KJ/mol£»·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©¡÷H=-92 kJ?mol-1£¬
¹Ê´ð°¸Îª£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©¡÷H=-92 kJ?mol-1£»
£¨3£©¢ÙCH4£¨g£©+H2O£¨g£©¨TCO£¨g£©+3H2£¨g£©¡÷H=+206.2kJ?mol-1
¢ÚCH4£¨g£©+CO2£¨g£©¨T2CO£¨g£©+2H2£¨g£©¡÷H=+247.4kJ?mol-1
ÒÀ¾Ý¸Ç˹¶¨ÂÉ¢Ù¡Á2-¢ÚµÃµ½£ºCH4£¨g£©+2H2O£¨g£©¨TCO2£¨g£©+4H2£¨g£©¡÷H=+165 kJ?mol-1£¬
¹Ê´ð°¸Îª£ºCH4£¨g£©+2H2O£¨g£©¨TCO2£¨g£©+4H2£¨g£©¡÷H=+165 kJ?mol-1£®
¹Ê´ð°¸Îª£º3NO2£¨g£©+H2O£¨l£©=2HNO3£¨aq£©+NO£¨g£©¡÷H=-138 kJ?mol-1£»
£¨2£©ÒÑÖª²ð¿ª1mol H-H¼ü£¬1mol N-H¼ü£¬1mol N¡ÔN¼ü·Ö±ðÐèÒªµÄÄÜÁ¿ÊÇ436kJ¡¢391kJ¡¢946kJ£¬»¯Ñ§·½³ÌʽΪN2+3H2?2NH3£¬ÒÀ¾Ý»¯Ñ§·½³Ìʽ¼ÆËã·´Ó¦ÈÈ=946kJ/mol+3¡Á436kJ/mol-6¡Á391kJ/mol=-92KJ/mol£»·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©¡÷H=-92 kJ?mol-1£¬
¹Ê´ð°¸Îª£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©¡÷H=-92 kJ?mol-1£»
£¨3£©¢ÙCH4£¨g£©+H2O£¨g£©¨TCO£¨g£©+3H2£¨g£©¡÷H=+206.2kJ?mol-1
¢ÚCH4£¨g£©+CO2£¨g£©¨T2CO£¨g£©+2H2£¨g£©¡÷H=+247.4kJ?mol-1
ÒÀ¾Ý¸Ç˹¶¨ÂÉ¢Ù¡Á2-¢ÚµÃµ½£ºCH4£¨g£©+2H2O£¨g£©¨TCO2£¨g£©+4H2£¨g£©¡÷H=+165 kJ?mol-1£¬
¹Ê´ð°¸Îª£ºCH4£¨g£©+2H2O£¨g£©¨TCO2£¨g£©+4H2£¨g£©¡÷H=+165 kJ?mol-1£®
µãÆÀ£º±¾Ì⿼²éÁËÈÈ»¯Ñ§·½³ÌʽµÄÊéд·½·¨ºÍ×¢ÒâÎÊÌ⣬ÒÀ¾Ý»¯Ñ§¼ü¼üÄܼÆËã·´Ó¦È˵ķ½·¨£¬¸Ç˹¶¨ÂɵļÆËãÓ¦Óã¬ÌâÄ¿ÄѶÈÖеȣ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿