Question

N₂O ₅ºÜ²»Îȶ¨£¬ÔÚt ¡æʱÓÐÏÂÁÐÁ½¸ö¿ÉÄæ·´Ó¦£ºN₂O₅£¨g£©N₂O₃(g)+O₂£¨g£©,N₂O₃(g)N₂O(g)+O₂(g)¡£ÔÚt ¡æʱ£¬ÍùÒ»¹Ì¶¨ÈÝ»ýµÄÃܱÕÈÝÆ÷Àï³äÈë0.040 0 mol¡¤L^-1 N₂O₅£¨g£©£¬·´Ó¦½øÐÐ5 minºó´ïµ½Æ½ºâ£¬´ËʱO₂µÄŨ¶ÈΪ0.045 0 mol¡¤L^-1£¬N₂O₃£¨g£©µÄŨ¶ÈΪ0.016 2 mol¡¤L^-1,N₂O₃(g)µÄŨ¶ÈΪ0.016 2 mol¡¤L^-1£¬ÊÔÇó£º

£¨1£©Æ½ºâʱN₂O₅£¨g£©ºÍN₂O£¨g£©µÄŨ¶È¡£

£¨2£©´Ó·´Ó¦¿ªÊ¼µ½´ïµ½Æ½ºâʱN₂O₅£¨g£©µÄƽ¾ù·´Ó¦ËÙÂÊ¡£

Answer 1

£¨1£©c(N₂O₅)=0.009 4 mol¡¤L^-1£¬c(N₂O)=0.014 4 mol¡¤L^-1

£¨2£©v(N₂O₅)=0.006 12 mol¡¤L^-1¡¤min^-1

½âÎö£ºÉè´ïµ½Æ½ºâʱÏûºÄµÄN₂O₅£¨g£©ÎïÖʵÄÁ¿Å¨¶ÈΪx£¬Éú³ÉµÄN₂O£¨g£©ÎïÖʵÄÁ¿Å¨¶ÈΪy£¬Ôò

            N₂O₅£¨g£©          N₂O₃(g)  +  O₂(g)

¿ªÊ¼£º0.040 0 mol¡¤L^-1                  0            0

ƽºâ£º0.040 0  mol¡¤L^-1-x              x            x

      N₂O₃(g)N₂O(g)+O₂(g)

ƽºâ£ºx-y                 y           y

ÒÀÌâÒâµÃ£º

½âµÃ

ËùÒÔ£¬£¨1£©Æ½ºâʱc(N₂O₅)=0.040 0  mol¡¤L^-1-0.030 6  mol¡¤L^-1=0.009 4  mol¡¤L^-1,c(N₂O)=0.014 4  mol¡¤L^-1¡£