ÌâÄ¿ÄÚÈÝ

ÂȼҵµÄ²úÎïNaOHÓ벻ͬÎïÖÊ·´Ó¦¿ÉÒÔÉú³É²»Í¬µÄÑΡ£ÒÑÖª³£ÎÂÏÂ,Ũ¶È¾ùΪ
0£®1 mol¡¤L-1µÄ4ÖÖÄÆÑÎÈÜÒºµÄpHÈçϱí:
ÈÜÖÊ
Na2CO3
NaHCO3
NaClO
NaHSO3
pH
11£®6
9£®7
10£®3
5£®2
 
ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ£¨ £©
A£®ÏòÂÈË®ÖмÓÈëNaHCO3ÈÜÒº,¿ÉÒÔÔö´óÂÈË®ÖдÎÂÈËáµÄŨ¶È
B£®ËÄÖÖÈÜÒºÖÐ,Ë®µÄµçÀë³Ì¶È×î´óµÄÊÇNaClO
C£®³£ÎÂÏÂ,ÏàͬÎïÖʵÄÁ¿Å¨¶ÈµÄH2SO3¡¢H2CO3¡¢HClOÈÜÒº,pH×î´óµÄÊÇH2SO3ÈÜÒº
D£®NaHSO3ÈÜÒºÖÐÀë×ÓŨ¶È´óС˳ÐòΪc(Na+)>c(H+)>c(HS)>c(S)>c(OH-)
A

ÊÔÌâ·ÖÎö£º²»Í¬µÄÈõËáÓëͬÖּÉú·´Ó¦µÃµ½µÄÑεÄË®ÈÜÒºµÄpH¹ØÏµÊÇ£ºËáԽǿ£¬ÑÎÈÜÒºµÄpH¾ÍԽС£¬ËáÔ½Èõ£¬ÏàÓ¦µÄÑÎÈÜÒºµÄpH¾ÍÔ½´ó¡£A£®ÏòÂÈË®ÖмÓÈëNaHCO3ÈÜÒº,ÓÉÓÚÔÚÂÈË®ÖдæÔÚÆ½ºâ£ºCl2£«H2OHCl£«HClO£¬ÓÉÓÚËáÐÔHCl> H2CO3> HClO£¬ËùÒԻᷢÉú·´Ó¦NaHCO3+HCl=NaCl+H2O+ CO2¡ü£¬Ê¹Cl2£«H2OHCl£«HClOÕýÏòÒÆ¶¯£¬c(HClO)Ôö´ó¡£ÕýÈ·¡£B£®ÔÚËÄÖÖÈÜÒºÖÐ,ÓÉÓÚNa2CO3µÄpH×î´ó£¬ËùÒÔË®µÄµçÀë³Ì¶È×î´óµÄÊÇNa2CO3¡£´íÎó¡£C£®³£ÎÂÏÂ,ÏàͬÎïÖʵÄÁ¿Å¨¶ÈµÄH2SO3¡¢H2CO3¡¢HClOÈÜÒº,µçÀë³Ì¶È×î´óµÄÊÇH2SO3¡£ËáµÄµçÀë³Ì¶ÈÔ½´ó£¬c(H+)Ô½´ó£¬ÈÜÒºµÄpHԽС¡£ËùÒÔpH×î´óµÄÊÇHClOÈÜÒº£®´íÎó¡£D£®ÔÚNaHSO3ÈÜÒºÖУ¬´æÔÚµçÀ룺NaHSO3=Na++ HSO3-£¬µçÀëÆ½ºâ£ºHSO3-H++ SO32-¡£Ë®½âƽºâ£ºHSO3-£«H2OOH-+ H2SO3¡£ÓÉÓÚÔÚNaHSO3ÈÜÒºÖУ¬pH=5£®2£®ËµÃ÷HSO3-µÄµçÀë×÷ÓôóÓÚË®½â×÷Óᣵ«ÊÇÑεĵçÀë×÷ÓôóÓÚÈõµç½âÖʵĵçÀë×÷Óã¬ËùÒÔÔÚ´ËÈÜÒºÖи÷ÖÖÀë×ÓŨ¶È´óС˳ÐòΪc(Na+)> c(HSO3-)> c(H+)>c(SO32-)>c(OH-)¡£´íÎó¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¸´·Ö½â·´Ó¦ÊÇÖÐѧ»¯Ñ§Öг£¼ûµÄÒ»ÖÖ·´Ó¦ÀàÐÍ¡£
(1)ÒÑÖªÔÚ³£ÎÂϲâµÃŨ¶È¾ùΪ0.1 mol¡¤L£­1µÄÏÂÁÐ6ÖÖÈÜÒºµÄpH(C6H5OHÏ൱ÓÚÒ»ÔªÈõËá)£º
ÈÜÖÊ
CH3COONa
NaHCO3
Na2CO3
NaClO
NaCN
C6H5ONa
pH
8.8
9.7
11.6
10.3
11.1
11.3
 
¸´·Ö½â´æÔÚÕâÑùÒ»¸ö¹æÂÉ£ºÒ»ÖÖ½ÏÇ¿ËáÓëÁíÒ»ÖÖ½ÏÈõËáµÄÑοÉÒÔ×Ô·¢µØ·´Ó¦£¬Éú³É½ÏÈõËáºÍ½ÏÇ¿ËáµÄÑΣ¬È磺2CH3COOH£«Na2CO3=2CH3COONa£«CO2¡ü£«H2O¡£Èô»»¸ö½Ç¶È¿´£¬Ëüͬʱ½Òʾ³öÁíÒ»Ìõ¹æÂÉ£¬¼´¼îÐÔ½ÏÇ¿µÄÎïÖÊ·¢ÉúÀàËÆ·´Ó¦¿ÉÒÔÉú³É¼îÐÔ½ÏÈõµÄÎïÖÊ¡£ÒÀÕոùæÂÉ£¬ÇëÅжÏÏÂÁз´Ó¦²»ÄܳÉÁ¢µÄÊÇ______________(Ìî±àºÅ)¡£
A£®CO2£«H2O£«2NaClO=Na2CO3£«2HClO
B£®CO2£«H2O£«NaClO=NaHCO3£«HClO
C£®CO2£«H2O£«C6H5ONa¨D¡úNaHCO3£«C6H5OH
D£®CO2£«H2O£«2C6H5ONa¨D¡úNa2CO3£«2C6H5OH
E£®Na2CO3£«C6H5OH¨D¡úNaHCO3£«C6H5ONa
F£®CH3COOH£«NaCN=CH3COONa£«HCN
(2)¸ù¾ÝǰÊöÐÅÏ¢Åжϣ¬Å¨¶È¾ùΪ0.05 mol¡¤L£­1µÄÏÂÁÐÁùÖÖÎïÖʵÄÈÜÒºÖУ¬pH×îСµÄÊÇ________(Ìî±àºÅ)£»ÆäpHµÈÓÚ________(ÌîÊýÖµ)£»pH×î´óµÄÊÇ________(Ìî±àºÅ)¡£
¢ÙC6H5OH¡¡¢ÚCH3COOH¡¡¢ÛHCN¡¡¢ÜHClO
¢ÝH2SO4¡¡¢ÞHClO4
(3)һЩ¸´·Ö½â·´Ó¦µÄ·¢Éú»¹×ñÑ­ÆäËûµÄ¹æÂÉ¡£ÏÂÁÐת»¯¶¼ÊôÓÚ¸´·Ö½â·´Ó¦£º
¢Ù¹¤ÒµÉϽ«Ê¯»ÒÈéÓë´¿¼îÈÜÒº»ìºÏ¿ÉÖÆµÃ¿ÁÐÔÄÆÈÜÒº
¢ÚºîÊÏÖÆ¼î·¨ÖУ¬Ïò±¥ºÍ̼ËáÇâï§ÈÜÒºÖмÓÈë±¥ºÍʳÑÎË®¿É»ñµÃСËÕ´ò¾§Ìå
¢ÛÕô·¢KClºÍNaNO3»ìºÏÈÜÒº£¬Ê×ÏÈÎö³öNaCl¾§Ìå¸ù¾ÝÉÏÊö·´Ó¦£¬×ܽá³ö¸´·Ö½â·´Ó¦·¢ÉúµÄÁíÒ»¹æÂÉ___________________________________________
½«KIÈÜÒººÍAgCl¹ÌÌå»ìºÏ½Á°è£¬»á¹Û²ìµ½µÄÏÖÏóÊÇ____________________________________£¬Çëд³ö·´Ó¦µÄÀë×Ó·½³Ìʽ______________________________________________

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø